(......9) nha

\((3.x-2^{4} ):7^3 =2.7^{4}\)

\(=>(3.x-16):7^{3} =2.7^{4}\)

\(=>3.x-16=2.7^{4}:7^{3}\)

\(=>3.x-16=2.7^{4-3}\)

\(=>3.x-16=2.7\)

\(=>3.x-16=14\)

\(=>3.x=14+16\)

\(=>3.x=30\)

\(=>x=30:3\)

\(=>x=10\)

\(\left(3x-2^4\right):7^3=\left(2.7\right)^4\)

\(\Rightarrow\left(3x-2^4\right)=2^4.7^4.7^3\)

\(\Rightarrow3x-2^4=2^4.7^7\)

\(\Rightarrow3x=2^4.7^7+2^4\)

\(\Rightarrow3x=2^4.\left(7^7+1\right)=16\left(7^7+1\right)\)

\(\Rightarrow x=\dfrac{16\left(7^7+1\right)}{3}\)

Sửa lại.

\((3x-2^{4}):7^{3}=2.7^{4}\)

\(=>3x-2^{4} =2.7^{4}.7^{3}\)

\(=>3x-2^{4} =2.7^{7}\)

\(=>3x=2.7^{7}+2^{4}\)

\(=>x=\dfrac{2.7^{7}+16}{3}\)
 

Ai giúp mình với

bạn viết tách ra chứ mk ko hiểu

a: \(2^6=64\)

\(6^2=36\)

Do đó: \(2^6>6^2\)

c: \(7^{3+1}=7^4=7^3+2058\)

\(7^3+1=7^3+1\)

mà 2058>1

nên \(7^{3+1}>7^3+1\)

\(\left(3x-2^4\right).7^3=2.7^4\)

\(\Rightarrow\left(3x-2^4\right)=2.7^4:7^3=14\)

\(\Rightarrow\)\(3x=14+16=30\)

\(\Rightarrow x=30:3=10\)

nghĩ là ông dũng đi trần duy hưng

a) \(7^5.7^6=7^{5+6}=7^{11}\)

b) \(5^{20}.5=5^{20+1}=5^{21}\)

c) \(7^9:7=7^{9-1}=7^8\)

d) \(25^3.5^2=\left(5^2\right)^3.5^2=5^{2.3}.5^2=5^6.5^2=5^{6+2}=5^8\)

a. =7^11

b. =5^21

c. =7^8

d. =5^8

e. =a

f. =x^6

a 7^11

b 5^21 

c 7^8

d 5^8

e a

f x^6

giups mình với

a) \(\left(7^{60}:7^{14}\right):7^{12}\)

\(=7^{46}:7^{12}=7^{34}\)

b) \(\left(5^{32}.5^9\right):\left(5^{48}.25\right)\)

\(=\left(5^{32}.5^9\right):\left(5^{48}.5^2\right)\)

\(=5^{41}:5^{50}=-\left(5^9\right)\)

c) \(\left(11^{154}-11^{152}\right):11^{152}\)

= \(\left(11^{152}.121-11^{152}\right):11^{152}\)

=\(\left[11^{152}.\left(121-1\right)\right]:11^{152}\)

= \(11^{152}.120:11^{152}\)

= \(120\)

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