tìm x
x+13=15
Tìm x
x+(13-15)=5+(10-7)
\(x+\left(13-15\right)=5+\left(10-7\right)\)
\(< =>x-2=8=>x=10\)
Ta có: \(x+\left(13-15\right)=5+10-7\)
\(\Leftrightarrow x-2=15-7=8\)
hay x=10
x + (13 - 15) = 5 + (10 - 7)
x + (13 - 15) = 5 + 3
x + (13 - 15) = 8
x + (-2) = 8
x = 8 - (-2)
x = 10
Chúc bạn học tốt!
Tìm x
x - 6/7 = 7/3
x + 13/14 = 15/7
9/4 - 3xX=5/6
Cho mình lời giải chi tiết,10 bạn nhanh nhất mình tích nha!
\(a,\Rightarrow x=\dfrac{7}{3}+\dfrac{6}{7}=\dfrac{49+18}{21}=\dfrac{67}{21}\\ b,\Rightarrow x=\dfrac{15}{7}-\dfrac{13}{14}=\dfrac{30-13}{14}=\dfrac{17}{14}\\ c,\Rightarrow3x=\dfrac{9}{4}-\dfrac{5}{6}=\dfrac{27-10}{12}=\dfrac{17}{12}\\ \Rightarrow x=\dfrac{17}{12}\cdot\dfrac{1}{3}=\dfrac{17}{36}\)
\(x=\dfrac{7}{3}+\dfrac{6}{7}=\dfrac{67}{21}\)
\(x=\dfrac{15}{7}-\dfrac{13}{14}=\dfrac{17}{14}\)
\(x=\left(\dfrac{9}{4}-\dfrac{5}{6}\right):3=\dfrac{17}{36}\)
\(x-\dfrac{6}{7}=\dfrac{7}{3}\\ \Rightarrow x=\dfrac{7}{3}+\dfrac{6}{7}\\ \Rightarrow x=\dfrac{67}{21}\)
\(x+\dfrac{13}{14}=\dfrac{15}{7}\\ \Rightarrow x=\dfrac{15}{7}-\dfrac{13}{14}\\ \Rightarrow x=\dfrac{17}{14}\)
\(\dfrac{9}{4}-3\times x=\dfrac{5}{6}\\ \Rightarrow3\times x=\dfrac{9}{4}-\dfrac{5}{6}\\ \Rightarrow3\times x=\dfrac{17}{12}\\ \Rightarrow x=\dfrac{17}{12}:3\\ \Rightarrow x=\dfrac{17}{36}\)
1) Tìm x
x - 35% . x = 1/25
2) Tính
a) 17 2/31 - ( 15/17 + 6 2/31 )
b) 27 51/59 - ( 25 51/29 - 1 1/3 )
c) ( 4 5/23 - 2 2/5 + 7 7/13 ) - ( 3 5/23 - 6 6/13 )
d) 8 1/3 + 7,8 + 5 2/3 - 1,8
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
Tim X
a,X - 20/11 x 13 - 20/13 x 15 - 20/15 x 17 -...-20/53 x 55 = 3/11
b,1/21 + 1/28 +1/36 + ... +2/Xx(x + 1) = 2/9
Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
Tìm x
x/12=x+15/16
\(\dfrac{x}{12}=x+\dfrac{15}{16}\)
\(\Leftrightarrow\dfrac{x}{12}=\dfrac{16x+15}{16}\)
\(\Rightarrow12\left(16x+15\right)=16x\)
\(\Leftrightarrow192x+180=16x\)
\(\Leftrightarrow176x=-180\)
\(\Leftrightarrow x=-\dfrac{45}{44}\)
Vậy \(x=-\dfrac{45}{44}\)
\(\dfrac{x}{12}=\dfrac{x+15}{16}\)
\(\Rightarrow12\left(x+15\right)=16x\)
\(\Leftrightarrow12x+180=16x\)
\(\Leftrightarrow4x=180\)
\(\Leftrightarrow x=45\)
Vậy x = 45
\(\dfrac{x}{12}=\dfrac{x+15}{16}\)
\(16x=12\left(x+15\right)\)
\(16x=12x+180\)
\(4x=180\)
\(x=45\)
tìm x
x+x+x+15=141
(khó quá có ai giải giúp tôi với)
\(x+x+x+15=141\)
\(3x=141-15\)
\(3x=126\)
\(x=42\)
\(\text{x+x+x+15=141}\)
\(3x+15=141\)
\(3x=141-15\)
\(3x=126\)
\(x=126\div3\)
\(x=42\)
Tìm số nguyên x, biết:
a) 3 4 = x x + 1
b) 2 3 = x + 1 2 x
c) 1 x + 1 = 2 x + 3
d) 5 4 x − 2 = − 1 5 − x
Tìm số thực xx, biết:
a) 3√x<2x3<2 :
b) 3√2x−1>−3:2x−13>−3:
c) 3√2−3x≤1:2−3x3≤1:
d) 3√3−4x≥53−4x3≥5.
Tìm x biết
x-11/13=15/13
\(x=\dfrac{15}{13}+\dfrac{11}{13}=\dfrac{15+11}{13}=\dfrac{26}{13}\)
\(x=\dfrac{15}{13}+\dfrac{11}{13}\\ x=\dfrac{26}{13}\)
37−xx+13 7=37