\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)

\(3x^2-51=-24\)

\(3x^2=27\)

\(x^2=9\)

\(x^2=3^2=\left(-3\right)^2\)

TH1: x=3

TH2: x=-3

=.= hok tốt!!

(3x²-51)²ⁿ=-24²ⁿ

=>(3x²-51)=-24

3x²=-24+51

3x²=27

x²=27:3

x²=9

x²=3² hoặc x²=(-3)²

=>x=3 hoặc x=-3

bạn ơi

x=-5

và x=5 cx dc nhé

how to play free water?

Có: (x² - 25)²ⁿ = 24²ⁿ

=> x² - 25 = 24

=> x² = 24 + 25 = 49

=> x = 7

a/ \(\Leftrightarrow3^{2x}:3^2=\left(\frac{1}{3}\right)^5\Rightarrow3^x=\frac{1}{3^5}\Rightarrow3^x.3^5=1\Rightarrow3^{5x}=3^0\)

=> 5x = 0 => x = 0 

(3x² - 51)²ⁿ = 576ⁿ

=> (3x² - 51)²ⁿ = 24²ⁿ = (-24)²ⁿ

\(\Rightarrow\left[\begin{array}{nghiempt}3x^2-51=24\\3x^2-51=-24\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}3x^2=75\\3x^2=27\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x^2=25\\x^2=9\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\\\left[\begin{array}{nghiempt}x=3\\x=-3\end{array}\right.\end{array}\right.\)

Vậy \(\left[\begin{array}{nghiempt}x=5\\x=-5\\x=3\\x=-3\end{array}\right.\)

(3x²-51)²ⁿ=(-24)²ⁿ\(\Rightarrow\)(51-3x²)²ⁿ=(24)²ⁿ\(\Rightarrow\)(51-3x²)=24

\(\Rightarrow\)51-24=3x²\(\Rightarrow\)27\(\Rightarrow\)x²=3²\(\Rightarrow\)x=3 hoặc x=-3

từ đề bài => 3x^2-51=24

=>3x^2=75

=>x^2=75:3=25

=>x=-5 hoặc x=5