\(x\) - (10 - \(x\)) = \(x\) - 22

\(x\) - 10 + \(x\) = \(x\) - 22

2\(x\) - 10 = \(x\) - 22

2\(x\) - \(x\)  = -22 + 10

\(x\)         = - 12

Dạ,em cảm ơn cô ạ!

2.08813781251 nhé

Số lít mật ong lấy ra là:

24 : 3 = 8 (l)

Số lít mật ong còn lại là:

24 – 8 = 16(l).

Đáp số: 16 lít

  đây má ! ko nói ai bt tr . Con thị mẹ

Bài đó trang mấy ?

$1-\frac{1}{99}x1-\frac{1}{100}....1-\frac{1}{2006}$
=($\frac{99}{99}-\frac{1}{99}$)x($\frac{100}{100}-\frac{1}{100}$)....($\frac{2006}{2006}-\frac{1}{2006}$) = $\frac{98}{99}x\frac{99}{100}....\frac{2005}{2006}=\frac{98}{2006}$

$\frac{\mathrm{NÈ\; EM}}{}$

1) \(\left(x+\dfrac{1}{3}\right)^3=x^3+3.x^2.\dfrac{1}{3}+3.x.\left(\dfrac{1}{3}\right)^2+\left(\dfrac{1}{3}\right)^3\)

\(=x^3+x^2+\dfrac{x}{3}+\dfrac{1}{27}\)

2) \(\left(2x+y^2\right)^3=\left(2x\right)^3+3.\left(2x\right)^2.y^2+3.2x.\left(y^2\right)^2+\left(y^2\right)^3\)

\(=8x^3+12x^2y^2+6xy^4+y^6\)

3) \(\left(\dfrac{1}{2}x^2+\dfrac{1}{3}y\right)^3=\left(\dfrac{1}{2}x^2\right)^3+3.\left(\dfrac{1}{2}x^2\right)^2.\dfrac{1}{3}y+3.\dfrac{1}{2}x^2.\left(\dfrac{1}{3}y\right)^2+\left(\dfrac{1}{3}y\right)^3\)

\(=\dfrac{1}{8}x^6+\dfrac{1}{4}x^4y+\dfrac{1}{6}x^2y^2+\dfrac{1}{27}y^3\)

4) \(\left(3x^2-2y\right)^3=\left(3x^2\right)^3-3.\left(3x^2\right)^2.2y+3.3x^2.\left(2y\right)^2-\left(2y\right)^3\)

\(=27x^6-54x^4y+36x^2y^2-8y^3\)

5) \(\left(\dfrac{2}{3}x^2-\dfrac{1}{2}y\right)^3=\left(\dfrac{2}{3}x^2\right)^3-3.\left(\dfrac{2}{3}x^2\right)^2.\dfrac{1}{2}y+3.\dfrac{2}{3}x^2.\left(\dfrac{1}{2}y\right)^2-\left(\dfrac{1}{2}y\right)^3\)

\(=\dfrac{8}{27}x^6-\dfrac{1}{3}x^4y+\dfrac{1}{2}x^2y^2-\dfrac{1}{8}y^3\)

6) \(\left(2x+\dfrac{1}{2}\right)^3=\left(2x\right)^3+3.\left(2x\right)^2.\dfrac{1}{2}+3.2x.\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3\)

\(=8x^3+6x^2+\dfrac{3}{2}x+\dfrac{1}{8}\)

7) \(\left(x-3\right)^3=x^3-3.x^2.3+3.x.3^2-3^3\)

\(=x^3-9x^2+27x-27\)

8) \(\left(x+1\right)\left(x^2-x+1\right)\)

\(=\left(x+1\right)\left(x^2-x.1+1^2\right)\)

\(=x^3+1^3\)

\(=x+1\)

9) \(\left(x-3\right)\left(x^2+3x+9\right)\)

\(=\left(x-3\right)\left(x^2+x.3+3^2\right)\)

\(=x^3-3^3\)

\(=x^3-27\)

10) \(\left(x-2\right)\left(x^2+2x+4\right)\)

\(=\left(x-2\right)\left(x^2+x.2+2^2\right)\)

\(=x^3-2^3\)

\(=x^3-8\)

11) \(\left(x+4\right)\left(x^2-4x+16\right)\)

\(=\left(x+4\right)\left(x^2-x.4+4^2\right)\)

\(=x^3+4^3\)

\(=x^3+64\)

12) \(\left(x-3y\right)\left(x^2+3xy+9y^2\right)\)

\(=\left(x-3y\right)\left[x^2+x.3y+\left(3y\right)^2\right]\)

\(=x^3-\left(3y\right)^3\)

\(=x^3-27y^3\)

13) \(\left(x^2-\dfrac{1}{3}\right)\left(x^4+\dfrac{1}{3}x^2+\dfrac{1}{9}\right)\)

\(=\left(x^2-\dfrac{1}{3}\right)\left[\left(x^2\right)^2+x^2.\dfrac{1}{3}+\left(\dfrac{1}{3}\right)^2\right]\)

\(=\left(x^2\right)^3-\left(\dfrac{1}{3}\right)^3\)

\(=x^6-\dfrac{1}{27}\)

14) \(\left(\dfrac{1}{3}x+2y\right)\left(\dfrac{1}{9}x^2-\dfrac{2}{3}xy+4y^2\right)\)

\(=\left(\dfrac{1}{3}x+2y\right)\left[\left(\dfrac{1}{3}x\right)^2-\dfrac{1}{3}x.2y+\left(2y\right)^2\right]\)

\(=\left(\dfrac{1}{3}x\right)^3+\left(2y\right)^3\)

\(=\dfrac{1}{27}x^3+8y^3\)

\(2^{10}< 2^{11}\)

~ hok tốt ~

không cần k nha ^.^

Bài này có j để làm đâu bàn 

ta có2^10 và 2^11

2 lũy thừa trên có cùng cơ số là 2 nhưng số mũ có 10<11

=> 2^10 < 2^11

thanks bn nha

ĐKXĐ: ...

\(5\left(\frac{sinx+2sin2x.sinx+sin3x+cos3x}{1+2sin2x}\right)=cos2x+3\)

\(\Leftrightarrow5\left(\frac{sinx+cosx-cos3x+sin3x+cos3x}{1+2sin2x}\right)=cos2x+3\)

\(\Leftrightarrow5\left(\frac{sinx+sin3x+cosx}{1+2sin2x}\right)=cos2x+3\)

\(\Leftrightarrow5\left(\frac{2sin2x.cosx+cosx}{1+2sin2x}\right)=cos2x+3\)

\(\Leftrightarrow5cosx=cos2x+3\)

\(\Leftrightarrow5cosx=2cos^2x+2\)

\(\Leftrightarrow2cos^2x-5cosx+2=0\Leftrightarrow cosx=\frac{1}{2}\)

nick dưới 10đ hỏi đáp ~ ko ai cần tk :))

\(\left|x\right|\ge0\)mà \(\left|-3\right|=3\)nên \(x\in\left\{3;-3;4;-4;5;-5;6;-6;....\right\}\)

\(3>x;x>3\)

\(a,\Rightarrow x\times\left(42+54+4\right)=25400\\ \Rightarrow x\times100=25400\\ \Rightarrow x=254\\ b,\Rightarrow x\times\left(142-41-1\right)=40800\\ \Rightarrow x\times100=40800\\ \Rightarrow x=408\)

a) \(x\)(42+54+4)=15400            b) (142-41-1)\(x\)=10800
\(x\)x100=15400                             100x\(x\)=10800
\(x\)=15400:100                                      \(x\)=10800:100
\(x\)=154                                                 \(x\)=108