a: =16*20=320

b: =2/3+1/3*1/6:2/3

=2/3+1/18*3/2

=2/3+3/36

=2/3+1/12

=9/12=3/4

(2/9.3/5+1/3.3/5).(1/3-5/8)

(6/35+1/5).(1/3-5/8

(6/35+7/35).(1/3-5/8

13/35.(1/3-5/8)

13/35.-7/24

-91/840

\(\left(\frac{2}{9}:\frac{5}{3}+\frac{1}{3}:\frac{5}{3}\right).\left(\frac{1}{3}-\frac{5}{8}\right)\)

\(=\left[\left(\frac{2}{9}+\frac{1}{3}\right).\frac{3}{5}\right].\frac{-7}{24}\)

\(=\left(\frac{5}{9}.\frac{3}{5}\right).\frac{-7}{24}\)

\(=\frac{1}{3}.\frac{-7}{24}\)

\(=\frac{-7}{72}\)

\(a.20-\left[30-\left(5-1\right)^2\right]\)                             \(b.75-\left(3.5^2-4.2^3\right)\)

\(=20-\left[30-4^2\right]\)                                       \(=75-\left(75-4.2^3\right)\)

\(=20-14=6\)                                          \(=75-\left(75-32\right)\)

                                                                 \(=75-43=32\)

Đáp án:

Giải thích các bước giải:

1-2+3-4+5-6+... + 2009 - 2010 + 2011

=(1-2)+(3-4)+(5-6)+...+(2009-2010)+2011

=[(-1)+(-1)+(-1)+...+(-1)]+2011

=(-1005)+2011

=1006

Ta có: \(1-2+3-4+5-6+...+2009-2010+2011\)

\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(2009-2010\right)+2011\)

\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)+2011\)

\(=-1005+2011\)

\(=1006\)

 1-2+3-4+5-6+...+2009-2010+2011.=( 1 - 2 ) + (3-4) + ( 5-6) +...+ (2009- 2010)+2011.=(-1) + (-1) + (-1) + ... + ( - 1) + 2011.=(-1). 1005+2011.=(-1005) + 2011.=1006.

chúc bạn học tốt

a)

\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)

\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

b)

\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)

\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)

\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)

\(=6-\dfrac{18}{7}\)

\(=\dfrac{24}{7}\)

\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)

\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)

\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)

\(=\dfrac{2}{7}\times2\)

\(=\dfrac{4}{7}\)

a. 

\(\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{12}\right)+\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{12}\right)\) 

\(=\left(\frac{5}{4}+\frac{3}{5}+\frac{3}{8}-\frac{7}{5}\right):\left(-\frac{11}{12}\right)\)  

\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{12}\right)\) 

\(=\frac{33}{40}:\left(-\frac{11}{12}\right)\) 

\(=\frac{33}{40}\cdot\left(-\frac{12}{11}\right)\) 

\(=\frac{-9}{10}\)  

b. 

\(\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{15}\right)+\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\) 

\(=\left(\frac{3}{8}-\frac{7}{5}+\frac{5}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)  

\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{15}\right)\) 

\(=\frac{33}{40}:\left(-\frac{11}{15}\right)\) 

\(=\frac{33}{40}\cdot\left(-\frac{15}{11}\right)\) 

\(=\frac{-9}{8}\)

`a)-4/9(5/6*90%-8:0,32)`

`=-4/9(5/6*9/10-8:8/25)`

`=-4/9(3/4-25)`

`=-4/9*(-97)/4=97/9`

`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`

`=4/25+11/2*5/2+8/(-4)`

`=4/25+55/4-2`

`=1191/100`