a) \(-\frac{x}{15}=-\frac{60}{x}\Rightarrow-15.\left(-60\right)=x^2\Rightarrow900=x^2\Rightarrow x=\sqrt{900}=30\)

\(x=-\sqrt{900}=-30\)

b) \(-\frac{2}{x}=-\frac{x}{0,32}\Rightarrow-2.\left(-0,32\right)=x^2\Rightarrow\frac{16}{25}=x^2\Rightarrow x=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\)

\(x=-\frac{\sqrt{16}}{\sqrt{25}}=-\frac{4}{5}\)

a) \(\frac{x}{-15}=\frac{-60}{x}\)

=> x.x = (-60)  .  (-15)

=>x²  = 900

=>x²  = 30²

=>x=30

b)\(\frac{-2}{x}=\frac{-x}{0,32}\)

=>x.(-x) =(-2).0,32

=>-(x²)  =-0,64

=>-(x²)  =-(0,8²)

=>x=0,8

Bài 2: 

a: \(\Leftrightarrow x-7=36\)

hay x=43

219 - 7(x + 1) = 10²

7(x + 1) = 219 - 10²

7(x + 1) = 219 - 100

7(x + 1) = 119

x + 1 = 119 : 7

x + 1 = 17

x = 17 - 1

x = 16

--------------------

(3x - 2⁴) . 7³ = 2.7⁴

(3x - 16).7³ = 2.7⁴

3x - 16 = 2.7⁴:7³

3x - 16 = 2.7

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

Lời giải:

$10+2x=4^5:4^3=4^2=16$

$2x=16-10=6$

$x=6:2=3$

---------

$2x-6^2:18=3.2^2$
$2x-2=12$

$2x=14$

$x=14:2=7$

--------------

$70-5(x-3)=3.2^5=96$

$5(x-3)=70-3.2^5=-26$

$x-3=\frac{-26}{5}$

$x=3+\frac{-26}{5}=\frac{-11}{5}$

------------------

$19-7(x+1)=10^2=100$

$7(x+1)=19-100=-81$

$x+1=\frac{-81}{7}$

$x=\frac{-81}{7}-1=\frac{-88}{7}$

------------

$(3x-2^4).7^3=2.7^4$

$3x-16=2.7^4:7^3=2.7=14$

$3x=14+16=30$

$x=30:3=10$

\(a,14-5+x=30\)

\(\Rightarrow9+x=30\Rightarrow x=30-9\)

\(\Rightarrow x=21\)

\(b,45-\left(3+x\right)=14\)

\(\Rightarrow3+x=45-14\)

\(\Rightarrow3+x=31\Rightarrow x=31-3\)

\(\Rightarrow x=28\)

\(c,18+\left(-3+x\right)-\left(44-x\right)=55\)

\(\Rightarrow18-3+x-44+x=55\)

\(\Rightarrow2x-29=55\Rightarrow2x=55+29\)

\(\Rightarrow2x=84\Rightarrow x=84:2\)

\(\Rightarrow x=42\)

\(d,\left(x-45\right).27=0\)

\(\Rightarrow x-45=0\Rightarrow x=45\)

\(a,14-5+x=30\)

\(\Rightarrow9+x=30\)

\(\Rightarrow x=30-9=21\)

\(b,45-\left(3+x\right)=14\)

\(\Rightarrow3+x=45-14=31\)

\(\Rightarrow x=31-3=28\)

7^x+2+2.7^x-1=345

=>7^x-1(7³+2)=345

=>7^x-1=345:345=1

=>x-1=0

=>x=1

7^x-1 . 7^x+3 + 2. 7^x-1 = 345

7^x-1 .(7^x+3 + 2)  =345

7^x-1. (7^x+3 + 2) = 7^x+3 -2

7^x-1                    =(7^x+3 - 2) : (7^x+3 +2)

7^x-1                    = 0

=> x-1                  = 1

chắc chắn luôn

2,5 x 2,7 < X x 2 < 2,7 x 4,5 

6,75 < X x 2 < 12,15 

=> x = 4 ; 5 , 6 

<=>6.75<Xx2<12.15

=>X=4;5;6

2,3 x 2,7 < X x 2 < 2,7 x 4,5

6,75 < X x 2 < 12,15

=> x = 4 ; 5 ; 6

a.

\(7^{x+2}+2\times7^{x-1}=345\)

\(7^x\times7^2+2\times7^x\div7=345\)

\(7^x\times\left(7^2+\frac{2}{7}\right)=345\)

\(7^x\times\frac{345}{7}=345\)

\(7^x=345\div\frac{345}{7}\)

\(7^x=345\times\frac{7}{345}\)

\(7^x=7\)

\(x=1\)

b.

\(2^{x+2}-2^x=96\)

\(2^x\times\left(2^2-1\right)=96\)

\(2^x\times3=96\)

\(2^x=\frac{96}{3}\)

\(2^x=32\)

\(2^x=2^5\)

\(x=5\)

\(a,7^{x+2}+2.7^{x-1}=345\Rightarrow7^x.49+\frac{2}{7}.7^x=345\Rightarrow7^x\left(49+\frac{2}{7}\right)=345\Rightarrow7^x.\frac{345}{7}=345\Rightarrow7^x=345:\frac{345}{7}=7^1\Rightarrow x=1\)

\(b,2^{x+2}-2^x=96\Rightarrow2^x.4-2^x=96\Rightarrow2^x\left(4-1\right)=96\Rightarrow2^x.3=96\Rightarrow2^x=96:3=32\Rightarrow2^x=2^5\Rightarrow x=5\)

\(a,7^{x+2}+2.7^{x-1}=345=>7^{x-1+3}+2.7^{x-1}=345=>7^{x-1}.7^3+2.7^{x-1}=345\)

\(=>\left(7^3+2\right).7^{x-1}=345=>345.7^{x-1}=345=>7^{x-1}=1=7^0=>x-1=0=>x=1\)

\(b,2^{x+2}-2^x=96=>2^x.2^2-2^x=96=>2^x.\left(4-1\right)=96=>2^x.3=96=>2^x=32=2^5=>x=5\)