1/3 +1/6+ 1/10 + .......+2/x(x+1 ) = 2016/2018
giúp tôi với
Những câu hỏi liên quan
1/2+1/3+1/4+...+1/2018
giúp tôi, cảm ơn!
số số hạng của mẫu dãu số :
`(2018 - 2) : 1 + 1= 2017(số hạng)`
tổng mãu dãu trên là :
` (2018 + 2) xx 2017 : 2 = 2037170`
=> `1/2 + 1/3 + 1/4 + ... + 1/2018 = 1/2037170`
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Cho tôi hỏi bài này với
Bài 1: Tính nhanh
A (a x 7 + a x 8 - a x 15) : ( 1 + 2 + 3 + ........ + 10)
B ( 18 - 9 x 2) x ( 2 + 4 + 6 + 8 + 10 )
các bạn giúp tôi nhé
Đọc tiếp
Cho tôi hỏi bài này với
Bài 1: Tính nhanh
A = (a x 7 + a x 8 - a x 15) : ( 1 + 2 + 3 + ........ + 10)
B = ( 18 - 9 x 2) x ( 2 + 4 + 6 + 8 + 10 )
các bạn giúp tôi nhé
\(A=\left(a\text{x}7+a\text{x}8-a\text{x}15\right):\left(1+2+3+...+10\right)\)
\(A=\left(a\text{x}\left(7+8-15\right)\right):\left(1+2+3+...+10\right)\)
\(A=\left(a\text{x}0\right):\left(1+2+3+..+10\right)\)
\(A=0:\left(1+2+3+...+10\right)\)
\(A=0\)
\(B=\left(18-9\text{x}2\right)\text{x}\left(2+4+6+8+10\right)\)
\(B=\left(18-18\right)\text{x}\left(2+4+6+8+10\right)\)
\(B=0\text{x}\left(2+4+6+8+10\right)\)
\(B=0\)
Câu trả lời B=0
tim x : 1/3+1/6 +1/10 + .... +2/x(x+1) = 2016/2018
\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+.........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2017}\)
\(\Leftrightarrow\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{20}+........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2017}\)
\(\Leftrightarrow\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+..........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2018}\)
\(\Leftrightarrow2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}\right)=\dfrac{2016}{2018}\)
\(\Leftrightarrow2\left(\dfrac{1}{2}-\dfrac{1}{x+1}\right)=\dfrac{2016}{2018}\)
\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{x+1}=\dfrac{1008}{2018}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{2018}\)
\(\Leftrightarrow x+1=2018\)
\(\Leftrightarrow x=2017\)
Vậy ..
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\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2018}\)
\(\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{20}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{x\left(x+1\right)}\right)=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{x\left(x+1\right)}\right)=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2}-\dfrac{1}{x-1}\right)\) = \(\dfrac{1008}{1009}\)
\(\dfrac{1}{2}-\dfrac{1}{x-1}=\dfrac{504}{1009}\)
\(\dfrac{1}{x-1}=\dfrac{1}{2018}\)
\(x-1=2018\)
\(x=2019\)
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1/3+1/6+1/10+...+1/x(x+1)/2=2016/2018
\(\frac{1}{3}\) + \(\frac{1}{6}\) + \(\frac{1}{10}\) + ... + \(\frac{1}{x\left(x+1\right):2}\)
= \(\left(1-\frac{1}{2018}\right)-\frac{1}{2018}\)
= \(\frac{2017}{2018}-\frac{1}{2018}\)
= \(\frac{2016}{2018}=\frac{1008}{1009}\)
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Tôi biết nhưng tôi chỉ hỏi cho zui Hãy làm 10 x 10 = 9 x 9 = 8 x 8 = 7 x 7 = 6 x 6 = 5 x 5 = 4 x 4 = 3 x 3 = 2 x 2 = 1 x 1 =
1/3+1/6+1/10+...+2/x.(x+1)=2016/2018
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2016}{2018}\)
\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x\left(x+1\right)}=\frac{504}{1009}\)
\(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{504}{1009}\)
\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\frac{1}{2}-\frac{1}{x+1}=\frac{504}{1009}\)
\(\frac{1}{x+1}=\frac{1}{2}-\frac{504}{1009}\)
\(\frac{1}{x+1}=\frac{1}{2018}\)
\(\Rightarrow x+1=2018\)
\(\Rightarrow x=2017\)
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1/3 + 1/6 + 1/10 + 2/x.(x + 1) = 2014/2016
Tìm số tự nhiên x
tìm x
1/3 + 1//6 + 1/10 + . . . . +1/x^2/2=2017/2016
Tìm x,y
1} |3x-5|+(4y+1)2016+(5x.2)10 < hoặc = 10
2} |x-1| +(\(\frac{2}{3}\).y-2)2016+(z-1)2 > hoặc = 0
3} 1\x=1\6+y\3