tìm x biết (1/9)^2017 . 9^2017 - 96^2 : 24^2 = (3x-2)^3 +12
GIÚP MK VỚI
Những câu hỏi liên quan
a. (2x - 3)3 - (3x -2).(3x+2)
b. (5x - 2)3 - (x2 -1).(x2 +1)
c. (5a - 3).(5a +3) - (2a - 1)3
d. (x + 2)3 - 6.(x +2)2 + 12.(x + 2) -8
e. (2x - 3)2 - 6.(2x - 3) +9
f. (3x -2017)3 +3. (3x - 2017)2 + 3.(3x - 2017) +1
Giải giúp mk nha k cho nè.
Tìm x:
C, X^2-9=2×(x+3)^2
b, x^3-3x^2+3x-1=0
d, x^2-8x+3x-24=0
Giúp mk với. Mk cảm ơn
c) \(x^2-9=2\cdot\left(x+3\right)^2\)
\(\Leftrightarrow\left(x-3\right)\left(x+3\right)-2\left(x+3\right)^2=0\)
\(\Leftrightarrow\left(x+3\right)\left[x-3-2\left(x+3\right)\right]=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-3-2x-6\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(-x-9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-9\end{matrix}\right.\)
b) \(x^3-3x^2+3x-1=0\)
\(\Leftrightarrow x^3-3\cdot x^2\cdot1+3\cdot x\cdot1^2-1^3=0\)
\(\Leftrightarrow\left(x-1\right)^3=0\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
d) \(x^2-8x+3x-24=0\)
\(\Leftrightarrow\left(x^2-8x\right)+\left(3x-24\right)=0\)
\(\Leftrightarrow x\left(x-8\right)+3\left(x-8\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(x-8\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-8=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=8\end{matrix}\right.\)
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a) \(x^2-9=2\left(x+3\right)^2\)
\(\Leftrightarrow\left(x+3\right)\left(x-3\right)=2\left(x+3\right)^2\)
\(\Leftrightarrow2\left(x+3\right)^2-\left(x+3\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left[2\left(x+3\right)-\left(x-3\right)\right]=0\)
\(\Leftrightarrow\left(x+3\right)\left[2x+6-x+3\right]=0\)
\(\Leftrightarrow\left(x+3\right)\left(x+9\right)=0\)
\(\)\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x+9=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-9\end{matrix}\right.\)
b) \(x^2-8x+3x-24=0\)
\(\Leftrightarrow\left(x-8\right)x+3\left(x-8\right)=0\)
\(\Leftrightarrow\left(x-8\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x+3=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-3\end{matrix}\right.\)
c) \(x^3-3x^2+3x-1=0\)
\(\Leftrightarrow\left(x-1\right)^3=0\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
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Bài 1:a)Tính giá trị biểu thức :
A = 3^100 . (-2) + 3^101 / (-3)^101 - 3^100 b) 1/50 + 1/51 + ... + 1/99
b) Tìm x,biết 3^x + 3^x+1 3^x+2 + ... + 3^2017= 3^2020 - 9 / 2
ai nhanh mk K ạ.
A = \(\dfrac{3^{100}.\left(-2\right)+3^{101}}{\left(-3\right)^{101}-3^{100}}\)
A = \(\dfrac{3^{100}.\left(-2\right)+3^{100}.3}{\left(-3\right)^{100}.\left(-3\right)-3^{100}}\)
A = \(\dfrac{3^{100}.\left(-2+3\right)}{3^{100}.\left(-3\right)-3^{100}}\)
A = \(\dfrac{3^{100}.1}{3^{100}.\left(-3-1\right)}\)
A = \(\dfrac{3^{100}}{3^{100}}\) . \(\dfrac{1}{-4}\)
A = - \(\dfrac{1}{4}\)
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A) 5\4 + 3\5 B) 7\8 + 9\24 C) 2\36 + 1\6 + 5\12
giúp mình với
a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)
b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{15}{12}\)
c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)
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a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)
b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{5}{4}\)
c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)
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Xem thêm câu trả lời
a. (2x - 3)3 - (3x - 2).(3x + 2)b. (4x + 3)3 - (5x + 1).(1 -5x)c. (5x - 2)3 - (x2 - 1) . (x2 +1)d. (3a - 2)3 - (4a + 1).(1 - 4a)e. (5a - 3).(5a +3) - (2a -1)3f. (9a - 2).(9a + 2) - (3a +1)3g. (3x + 5)3 - (8x -3).(8x +3)h.(x +2)3 - 6 (x +2)2 + 12.(x + 2) - 8i. (2x - 3)2 - 6 (2x - 3) + 9k. (3x - 2017)3 + 3.(3x - 2017)2 + 3.(3x - 2017) + 1giải giúp mk nha thks cần gấp sắp đi họk rồj HELP ME :(
Đọc tiếp
a. (2x - 3)3 - (3x - 2).(3x + 2)
b. (4x + 3)3 - (5x + 1).(1 -5x)
c. (5x - 2)3 - (x2 - 1) . (x2 +1)
d. (3a - 2)3 - (4a + 1).(1 - 4a)
e. (5a - 3).(5a +3) - (2a -1)3
f. (9a - 2).(9a + 2) - (3a +1)3
g. (3x + 5)3 - (8x -3).(8x +3)
h.(x +2)3 - 6 (x +2)2 + 12.(x + 2) - 8
i. (2x - 3)2 - 6 (2x - 3) + 9
k. (3x - 2017)3 + 3.(3x - 2017)2 + 3.(3x - 2017) + 1
giải giúp mk nha thks cần gấp sắp đi họk rồj HELP ME :(
Tìm x biết 3x + 3^x+1= 3^8 . 2 + 2 . 3^8. 2017^0
\(3^x+3^{x+1}=3^8.2+2.3^8.2017^0\)
\(3^x+3^x.3=3^8.2^2\)
\(3^x=3^8.2^2:3\)
\(3^x=3^7.2^2\)
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3x+3x+1=38.2+2.38.201703x+3x+1=38.2+2.38.20170
3x+3x.3=38.223x+3x.3=38.22
3x=38.22:33x=38.22:3
3x=37.223x=37.22
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tìm x, biết x thuộc Z
(x+2).(x-5)=0
(2x+9)2=0
(2x-1)3=8
(1-3x)2=16
(3x+1)+1=-26
(x+1)+(x+3)+(x+5)+...+(x+2017)=0
(x-3).(x-2)+(x-1)+...+10+11=11
(x+3).(x2+1)=0
làm giúp mình với,cảm ơn
câu đầu bạn dưới làm rồi nên mình k làm lại
(2x+9)2=0
=> 2x+9=0
=> 2x=-9
=> x=-9/2
(2x-1)3=8
=> 2x-1=2
=> 2x=3
=> x=3/2
(1-3x)2=16
=> 1-3x=4
=> 3x=-3
=> x=-1
(3x+1)+1=-26
=> 3x=-27
=> x=-9
(x+1)+(x+3)+(x+5)+...+(x+2017)=0
(x+x+x+...+x)+(1+3+5+...+2017)=0
=> 1009x+1018081=0
1009x=-1018081
=> x=-1009
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\(\left(x+2\right)\left(x-5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+2=0\\x-5=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-2\\x=5\end{cases}}}\)
Vậy x = -2 hoặc x = 5
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lm luôn cho đủ
\(\left(x+3\right)\left(x^2+1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+3=0\\x^2+1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-3\\x^2=-1\left(ktm\right)\end{cases}}}\)
vậy x=-3
Xem thêm câu trả lời
(35x1985-1993)x(24-48:2)x(1998:9-58)1+3+5+.....+2016+2017
thu gọn
a, X= 2 + 2^9×2+2^9×3.....................+2^9×2017
Giúp mk nhé