a) 3/4 - 1/1/2 + 0,5 : 5/12
b) ( -2)2 - 1/5/27 . ( -3/2 )
c) 2/2.3 + 2/3.4 + ...+ 2/99.100
tìm x
a) x - 43 = ( 57-x) -50
b) / 5x-2 / \(\le\)0
1. Tính và tìm x
a, |3| - căn bậc hai của 11^2-21 - 4^15 : 2^27 + (-1)^2020
b, 1/1.2+1/2.3+1/3.4+.......+1/99.100
c, 1/2+1/2^2+1/2^3+.....+1/2^100
d, 1/1.2+3/2.5+5/5.10+11/10.21+13/21.34+1/34+35
f, ( x - 1/3)^4 .7^13= 7^16
e, |3x-2| - 5 = 11
g, x : 0,25 - x : 0,125 + 5.x= 2109
tinh:
a. \(\dfrac{3}{4}-1\dfrac{1}{2}+0,5:\dfrac{5}{12}\)
b. \(\left(-2\right)^2-1\dfrac{5}{27}.\left(-\dfrac{3}{2}\right)^3\)
c. \(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{99.100}\)
\(a,\dfrac{3}{4}-1\dfrac{1}{2}+0,5:\dfrac{5}{12}.\)
\(=\dfrac{3}{4}-\dfrac{3}{2}+\dfrac{1}{2}:\dfrac{5}{12}.\)
\(=\dfrac{3}{4}-\dfrac{6}{4}+\dfrac{1}{2}.\dfrac{12}{5}.\)
\(=-\dfrac{3}{4}+\dfrac{12}{10}.\)
\(=-\dfrac{3}{4}+\dfrac{6}{5}.\)
\(=-\dfrac{15}{20}+\dfrac{24}{20}=\dfrac{9}{20}.\)
Vậy.....
\(b,\left(-2\right)^2-1\dfrac{5}{27}.\left(-\dfrac{3}{2}\right)^3.\)
\(=4-1\dfrac{5}{27}.\left(-\dfrac{27}{8}\right).\)
\(=4-\dfrac{32}{27}.\left(-\dfrac{27}{8}\right).\)
\(=4-\left(-4\right).\)
\(=4+4=8.\)
Vậy.....
\(c,\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{99.100}.\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{99}-\dfrac{1}{100}.\)
\(=\dfrac{1}{2}+\left(\dfrac{1}{3}-\dfrac{1}{3}\right)+\left(\dfrac{1}{4}-\dfrac{1}{4}\right)+...+\left(\dfrac{1}{99}-\dfrac{1}{99}\right)-\dfrac{1}{100}.\)
\(=\dfrac{1}{2}+0+0+...+0-\dfrac{1}{100}.\)
\(=\dfrac{1}{2}-\dfrac{1}{100}.\)
\(=\dfrac{50}{100}-\dfrac{1}{100}=\dfrac{49}{100}.\)
Vậy.....
Tìm x:
a,x-3/97+x-2/98=x-1/99+x/100
b,x+2/327+x+3/326+x+4/325+x+5/324+xx349/5=0
c,(1/1.2+1/2.3+...+1/99.100)-2x=1/2
a) x - 3/97 + x - 2/98 = x - 1/99 + x/100
<=> x + 1/99 + 1 + x + 2/98 + 1 + x + 3/97 + 1 + (x + 4/96 + 1 + x + 5/95 + 1 + x + 10/90 + 1) = 0
<=> x + 100/99 + x + 100/98 + x + 100/97 + (x + 100/96 + x + 100/95 + x + 100/90) = 0
<=> (x + 100)(1/99 + 1/98 + 1/97 + 1/96 + 1/95 + 1/90) = 0
Mà 1/99 + 1/98 + 1/97 + 1/96 + 1/95 + 1/90 khác 0
=> x + 100 = 0
=> x = -100
c) (1/1.2 + 1/2.3 + ... + 1/99.100) - 2x = 1/2
<=> (1 - 1/2 + 1/2 - 1/3 + ... + 1/99 - 1/100) - 2x = 1/2
<=> (1 - 1/100) - 2x = 1/2
<=> 99/100 - 2x = 1/2
<=> -2x = 1/2 - 99/100
<=> -2x = -49/100
<=> x = 49/200
=> x = 49/200
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\Rightarrow\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\left(\frac{x+349}{5}-4\right)=0\)
\(\Rightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)
\(\Rightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)
Dễ thấy \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\Rightarrow x+329=0\)
\(\Rightarrow x=-329\)
1) Đổi các sau ra phân số tối giản:6,53(21); 49,3(27); 0,53(213); 9,63(7)
2) Tìm x: a) 3,12:2,4=6,4:x
b)6,36:x=1,8:2
3) Tính tổng:a)1+2+3+...+200
b)S=1+1/2+1/4+1/8+...+1/1024
c)S=1.2+2.3+3.4+...99.100
3]
c]S=1.2+2.3+3.4+...+99.100
3S=1.2.3+2.3.[4-1]+3.4.[5-2]+...+99.100.[101-98]
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.10-98.99.100
3S=99.100.101
Con lai ban tu giai nha
1:Tìm x, biết:
a) (3/5)^2x-1 = 125/27
b)1/2+(1/2.3)+(1/3.4)+...+(1/2015.2016)-2x=1/2-1/2016
c)/2x^2+/x-2//=2x^2+3
Tìm x, biết:
a, (3/5)^2x-1=125/27
b,1/2+1/2.3+1/3.4+...+1/2015.2016 - 2x=1/2-1/2016
c,/2x^2+/x-2//=2x^2+3
Bài 1:
a) Ta có: \(x\left(x^2-4\right)=0\)
\(\Leftrightarrow x\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
Vậy: \(x\in\left\{0;2;-2\right\}\)
b) Ta có: \(\left(2x-3\right)+\left(-3x\right)-\left(x-5\right)=40\)
\(\Leftrightarrow2x-3-3x-x+5=40\)
\(\Leftrightarrow-2x+2=40\)
\(\Leftrightarrow-2x=38\)
hay x=-19
Vậy: x=-19
Bài 2:
a) Ta có: \(-45\cdot12+34\cdot\left(-45\right)-45\cdot54\)
\(=-45\cdot\left(12+34+54\right)\)
\(=-45\cdot100\)
\(=-4500\)
b) Ta có: \(43\cdot\left(57-33\right)+33\cdot\left(43-57\right)\)
\(=43\cdot57-43\cdot33+43\cdot33-33\cdot57\)
\(=43\cdot57-33\cdot57\)
\(=57\cdot\left(43-33\right)\)
\(=57\cdot10=570\)
1 Tìm số tự nhiên x biết :
a .4^5 : 4^x =16
b (x -1 ) ^2 =25
c . (2x+1) ^3 =27
2 .So sánh
a . 3^100 và 9^50
b. 2^98 và 9^49
c . 5^30 và 6.5^29
d. 3^30 và 8^10
3 .Tính giá trị của biểu thức sau :
a . {145-[130-(246-236)]:2}.5
b.4 +96 :[(2^4.2+4):3^2]
c. 17^0 +[5^13:511+(136-130)^3]
d.100:{250:[450-(4.5^3-2^2.25]}
4.tìm x , biết :
a . 210-5 (x-10)=200
b[3.(70-x)+5]:2=46
c.230+[2^4+(x-5)]=315.2018^0
d . 707 : [(2^x-5)+74] = 4^2-3^2
5. cho tổng A=77+105+161+x với x thuộc N .tìm điều kiện của x để :
a. A chia hết cho 7
b.A không chia hết cho 7
giúp mình với ạ . mình cần khá gấp. bạn nào làm bài này mình tick cho nha
\(1,\\ a,\Leftrightarrow4^{5-x}=4^2\Leftrightarrow5-x=2\Leftrightarrow x=3\\ b,\Leftrightarrow\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\\ c,\Leftrightarrow2x+1=3\Leftrightarrow x=2\\ 2,\\ a,3^{100}=\left(3^2\right)^{50}=9^{50}\\ b,2^{98}=\left(2^2\right)^{49}=4^{49}< 9^{49}\\ c,5^{30}=5^{29}\cdot5< 6\cdot5^{29}\\ d,3^{30}=\left(3^3\right)^{10}=27^{10}>8^{10}\\ 4,\\ a,\Leftrightarrow5\left(x-10\right)=10\\ \Leftrightarrow x-10=2\Leftrightarrow x=12\\ b,\Leftrightarrow3\left(70-x\right)+5=92\\ \Leftrightarrow3\left(70-x\right)=87\\ \Leftrightarrow70-x=29\\ \Leftrightarrow x=41\\ c,\Leftrightarrow16+x-5=315-230=85\\ \Leftrightarrow x=74\\ d,\Leftrightarrow2^x-5+74=707:\left(16-9\right)=707:7=101\\ \Leftrightarrow2^x=32=2^5\\ \Leftrightarrow x=5\)
tìm x a) (8x+2) (1-3x)+(6x -1)(4x-10)=-50
b) (1 -4x)(x-1)+4(3x+2)(x+3)=38
c)5(2x+3)(x+2)- 2.(5x-4)(x-1)=75
hộ mk vs ạ
a: ta có: \(\left(8x+2\right)\left(1-3x\right)+\left(6x-1\right)\left(4x-10\right)=-50\)
\(\Leftrightarrow8x-24x^2+2-6x+24x^2-60x-4x+40=-50\)
\(\Leftrightarrow-62x=-92\)
hay \(x=\dfrac{46}{31}\)
b: ta có: \(\left(1-4x\right)\left(x-1\right)+4\left(3x+2\right)\left(x+3\right)=38\)
\(\Leftrightarrow x-1-4x^2+4x+4\left(3x^2+9x+2x+6\right)=38\)
\(\Leftrightarrow-4x^2+5x-1+12x^2+44x+24-38=0\)
\(\Leftrightarrow8x^2+49x-15=0\)
\(\text{Δ}=49^2-4\cdot8\cdot\left(-15\right)=2881\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{-49-\sqrt{2881}}{16}\\x_2=\dfrac{-49+\sqrt{2881}}{16}\end{matrix}\right.\)