Phân tích đa thức thành nhân tử:
a. \(x^6-x^4-9x^3+9x^2\)
b. \(x^4+x^3+6x^2+5x+5\)
c. \(\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
Phân tích đa thức thành nhân tử:
a. \(x^6-x^4-9x^3=9x^2\)
b. \(x^4+x^3+6x^2+5x+5\)
c. \(\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
Phân tích đa thức thành nhân tử:
a. \(x^6-x^4-9x^3+9x^2\)
b. \(x^4+x^3+6x^2+5x+5\)
c. \(\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
\(x^6-x^4-9x^3+9x^2\)
\(=x^4\left(x^2-1\right)-9x^2\left(x-1\right)\)
\(=x^4\left(x+1\right)\left(x-1\right)-9x^2\left(x-1\right)\)
\(=\left(x^5+x^4\right)\left(x-1\right)-9x^2\left(x-1\right)\)
\(=\left(x-1\right)\left(x^5+x^4-9x^2\right)\)
\(x^4+x^3+6x^2+5x+5\)
\(=x^4+x^3+x^2+5x^2+5x+5\)
\(=x^2\left(x^2+x+1\right)+5\left(x^2+x+1\right)\)
\(=\left(x^2+5\right)\left(x^2+x+1\right)\)
\(\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
\(=3\left(4x^2-4xy+y^2\right)-10\left(2x-y\right)+8\)
\(=3\left[\left(2x\right)^2-2.2x.y+y^2\right]-10\left(2x-y\right)+8\)
\(=3\left(2x-y\right)^2-10\left(2x-y\right)+8\)
\(=\left(2x-y\right)\left[3\left(2x-y\right)-10\right]+8\)
\(=\left(2x-y\right)\left(6x-3y-10\right)+8\)
Phân tích đa thức thành nhân tử
\(a.\left(x^2+4x-3\right)^2-5x\left(x^2+4x-3\right)+6x^2\)
B. \(x^2-2xy+y^2+3x-3y-4\)
\(c.\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
\(d.\left(x^2-2x\right)\left(x^2-2x-1\right)-6\)
Phân tích các đa thức sau thành nhân tử:
a) \({\left( {x - 1} \right)^2} - 4\)
b) \(4{x^2} + 12x + 9\)
c) \({x^3} - 8{y^6}\)
d) \({x^5} - {x^3} - {x^2} + 1\)
e) \( - 4{x^3} + 4{x^2} + x - 1\)
f) \(8{x^3} + 12{x^2} + 6x + 1\)
\(a,\left(x-1\right)^2-2^2=\left(x-1-2\right)\left(x-1+2\right)=\left(x-3\right)\left(x+1\right)\\ b,=\left(2x\right)^2+2.2x.3+3^2\\ =\left(2x+3\right)^2\\ c,=x^3-\left(2y\right)^3\\ =\left(x-2y\right)\left(x^2+2xy+4y^2\right)\\ d,=x^3\left(x^2-1\right)-\left(x^2-1\right)\\ =\left(x^3-1\right)\left(x^2-1\right)\\ =\left(x-1\right)\left(x^2+x+1\right)\left(x-1\right)\left(x+1\right)\\ =\left(x-1\right)\left(x+1\right)\left(x^2+x+1\right)\)
\(e,=-4x^2\left(x-1\right)+\left(x-1\right)\\ =\left(1-4x^2\right)\left(x-1\right)\\ =\left(1-2x\right)\left(1+2x\right)\left(x-1\right)\)
\(f,=\left(2x\right)^3+3.\left(2x\right)^2.1+3.2x.1^2+1^3\\ =\left(2x+1\right)^3\)
Phân tích đa thức sau thành nhân tử:
a) \(x^2-2xy+3x-3y+y^2-4\)
b) \(2\left(x^2-6x+1\right)^2+5\left(x^2-6x+1\right)\left(x^2+1\right)+2\left(x^2+1\right)^2\)
a: \(x^2-2xy+y^2+3x-3y-4\)
\(=\left(x-y\right)^2+3\left(x-y\right)-4\)
\(=\left(x-y+4\right)\left(x-y-1\right)\)
Phân tích đa thức thành nhân tử :
a)\(A=x^2-2xy+y^2+3x-3y-4\)
b)\(B=\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
a) \(A=x^2-2xy+y^2+3x-3y-4\)
\(=\left(x-y\right)^2-1+3x-3y-3\)
\(=\left(x-y-1\right)\left(x-y+1\right)+3\left(x-y-1\right)\)
\(=\left(x-y-1\right)\left(x-y+1+3\right)\)
\(=\left(x-y-1\right)\left(x-y+4\right)\)
Phân tích đa thức \(18x^3-\dfrac{8}{25}x\) thành nhân tử
a. \(\dfrac{2}{25}x\left(9x^2-4\right)=\dfrac{2}{25}x\left(3x-2\right)\left(3x+2\right)\)
b. \(2x\left(9x^2-\dfrac{4}{25}\right)=2x\left(3x-\dfrac{2}{5}\right)\left(3x+\dfrac{2}{5}\right)\)
Cách phân tích nào đúng, a hay b. Giải thích vì sao?
giải pt:
a,\(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)
b,\(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)
c, \(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)
giải pt :
a,\(\left(6x-5\right)\sqrt{x+1}-\left(6x+2\right)\sqrt{x-1}+4\sqrt{x^2-1}=4x-3\)
b, \(\left(9x-2\right)\sqrt{3x-1}+\left(10-9x\right)\sqrt{3-3x}-4\sqrt{-9x^2+12x-3}=4\)
c, \(\left(13-4x\right)\sqrt{2x-3}+\left(4x-3\right)\sqrt{5-2x}=2+8\sqrt{-4x^2+16x-15}\)