\(\dfrac{-9}{46}\)-4\(\dfrac{1}{23}\):(3\(\dfrac{1}{4}\)-x:\(\dfrac{3}{5}\))+2\(\dfrac{8}{23}\)=1
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\(B=\dfrac{\left(\dfrac{11^2}{200}+0,415\right):0,01}{\dfrac{1}{12}-37,25+3\dfrac{1}{6}}\) tính B
tìm X
\(\dfrac{-9}{46}-4\dfrac{1}{23}:\left(3\dfrac{1}{4}-x:\dfrac{3}{5}\right)+2\dfrac{8}{23}=1\)
câu dễ như này sao bạn không tự giải ? cứ phụ thuộc vào người khác thôi
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\(a,\dfrac{3}{5}+\dfrac{-5}{9}\)
\(b,\dfrac{1}{3}+\dfrac{-4}{3};\dfrac{4}{7}\)
\(c,-\dfrac{27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}\)
\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}\)
\(a,\dfrac{3}{5}+\dfrac{-5}{9}=\dfrac{27-25}{45}=\dfrac{2}{49}.\)
\(c,\dfrac{-27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}=\dfrac{-23}{23}+\dfrac{21}{21}+\dfrac{1}{2}=-1+1+\dfrac{1}{2}=\dfrac{1}{2}.\)
\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}=\dfrac{-8}{9}+\dfrac{1}{9}.\left(\dfrac{2}{9}+\dfrac{7}{9}\right)=\dfrac{-8}{9}+\dfrac{1}{9}.1=\dfrac{-8+1}{9}=\dfrac{-7}{9}.\)
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a) 4.left(-dfrac{1}{2}right)^3-2.left(-dfrac{1}{2}right)^2+3.left(-dfrac{1}{2}right)+1
b) 8.sqrt{9}-sqrt{64}
c) sqrt{dfrac{9}{16}}+dfrac{25}{46}:dfrac{5}{23}-dfrac{7}{4}
đung cho 5 sao
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a) \(4.\left(-\dfrac{1}{2}\right)^3\)\(-2.\left(-\dfrac{1}{2}\right)^2\)+\(3.\left(-\dfrac{1}{2}\right)\)+1
b) \(8.\sqrt{9}\)\(-\sqrt{64}\)
c) \(\sqrt{\dfrac{9}{16}}\)\(+\dfrac{25}{46}\)\(:\dfrac{5}{23}\)\(-\dfrac{7}{4}\)
đung cho 5 sao
a) \(4.\left(-\dfrac{1}{2}\right)^3-2.\left(-\dfrac{1}{2}\right)^2+3.\left(-\dfrac{1}{2}\right)+1\)
\(=4.\left(-\dfrac{1}{8}\right)-2.\dfrac{1}{4}+3.\left(-\dfrac{1}{2}\right)+1\)
\(=-\dfrac{1}{2}-\dfrac{1}{2}-\dfrac{3}{2}+1\)
\(=-\dfrac{3}{2}\)
b) \(8.\sqrt{9}-\sqrt{64}\)
\(=8.3-8\)
\(=24-8\)
\(=16\)
c) \(\sqrt{\dfrac{9}{16}}+\dfrac{25}{46}:\dfrac{5}{23}-\dfrac{7}{4}\)
\(=\dfrac{3}{4}+\dfrac{5}{2}-\dfrac{7}{4}\)
\(=-1+\dfrac{5}{2}\)
\(=\dfrac{3}{2}\)
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Bài 1: Tínha) dfrac{9}{5}+dfrac{2}{5} x dfrac{4}{6} b) dfrac{3}{8} x 2 - dfrac{6}{7} x dfrac{1}{3}Bài 2: Tính bằng cách thuận tiện nhất:a) dfrac{11}{23}+dfrac{2}{23}+dfrac{9}{23}+dfrac{18}{23} b)dfrac{25}{12}+dfrac{17}{6}-dfrac{15}{36}-dfrac{15}{6}Bài 3: Một hình chữ nhật có chiều rộng là dfrac{3}{5} m và bằng một nửa chiều dài. Tính diện tích hình chữ nhật đó.
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Bài 1: Tính
a) \(\dfrac{9}{5}+\dfrac{2}{5}\) x \(\dfrac{4}{6}\) b) \(\dfrac{3}{8}\) x 2 - \(\dfrac{6}{7}\) x \(\dfrac{1}{3}\)
Bài 2: Tính bằng cách thuận tiện nhất:
a) \(\dfrac{11}{23}+\dfrac{2}{23}+\dfrac{9}{23}+\dfrac{18}{23}\) b)\(\dfrac{25}{12}+\dfrac{17}{6}-\dfrac{15}{36}-\dfrac{15}{6}\)
Bài 3: Một hình chữ nhật có chiều rộng là \(\dfrac{3}{5}\) m và bằng một nửa chiều dài. Tính diện tích hình chữ nhật đó.
a)dfrac{7}{8}xdfrac{3}{13}+dfrac{4}{9}xdfrac{4}{13}b)dfrac{6}{5}+dfrac{7}{3}+dfrac{8}{9}c)23: dfrac{5}{14}+dfrac{6}{7}+dfrac{4}{9}d)4dfrac{1}{4}+7dfrac{3}{7}-2dfrac{4}{17}e)8-(9dfrac{2}{11}+dfrac{8}{33})
Đọc tiếp
a)\(\dfrac{7}{8}\)x\(\dfrac{3}{13}\)+\(\dfrac{4}{9}\)x\(\dfrac{4}{13}\)
b)\(\dfrac{6}{5}\)+\(\dfrac{7}{3}\)+\(\dfrac{8}{9}\)
c)23: \(\dfrac{5}{14}\)+\(\dfrac{6}{7}\)+\(\dfrac{4}{9}\)
d)\(4\dfrac{1}{4}\)+\(7\dfrac{3}{7}\)-\(2\dfrac{4}{17}\)
e)8-(9\(\dfrac{2}{11}\)+\(\dfrac{8}{33}\))
a, \(\dfrac{7}{8}\) \(\times\) \(\dfrac{3}{13}\) + \(\dfrac{4}{9}\) \(\times\) \(\dfrac{4}{13}\)
= \(\dfrac{1}{13}\) \(\times\)( \(\dfrac{21}{8}\) + \(\dfrac{16}{9}\))
= \(\dfrac{1}{13}\) \(\times\)( \(\dfrac{189}{72}\) + \(\dfrac{128}{72}\))
= \(\dfrac{1}{13}\) \(\times\) \(\dfrac{317}{73}\)
= \(\dfrac{317}{949}\)
b, \(\dfrac{6}{5}\) + \(\dfrac{7}{3}\) + \(\dfrac{8}{9}\)
= \(\dfrac{54}{45}\) + \(\dfrac{105}{45}\) + \(\dfrac{40}{45}\)
= \(\dfrac{199}{45}\)
c, 23 : \(\dfrac{5}{14}\) + \(\dfrac{6}{7}\) + \(\dfrac{4}{9}\)
= \(\dfrac{322}{5}\) + \(\dfrac{6}{7}\) + \(\dfrac{4}{9}\)
= \(\dfrac{20286}{315}\) + \(\dfrac{270}{315}\) + \(\dfrac{140}{315}\)
= \(\dfrac{20696}{315}\)
d, 4\(\dfrac{1}{4}\) + 7\(\dfrac{3}{7}\) - 2\(\dfrac{4}{17}\)
= 4 + \(\dfrac{1}{4}\) + 7 + \(\dfrac{3}{7}\) - 2 - \(\dfrac{4}{17}\)
= (4+7-2) + (\(\dfrac{1}{4}\) + \(\dfrac{3}{7}\) - \(\dfrac{4}{17}\))
= 9 + \(\dfrac{119}{476}\) + \(\dfrac{204}{476}\) - \(\dfrac{112}{476}\)
= 9\(\dfrac{211}{476}\) = \(\dfrac{4495}{476}\)
e, 8 - (9\(\dfrac{2}{11}\) + \(\dfrac{8}{33}\))
= 8 - 9 - \(\dfrac{2}{11}\) - \(\dfrac{8}{33}\)
= -1 - \(\dfrac{2}{11}\) - \(\dfrac{8}{33}\)
= \(\dfrac{-33}{33}\) - \(\dfrac{-6}{33}\) - \(\dfrac{8}{33}\)
= - \(\dfrac{47}{33}\)
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thực hiện phép tínha)left(dfrac{9}{25}-2,18right):left(3dfrac{4}{5}+0,2right)b)dfrac{3}{8}.19dfrac{1}{3}-dfrac{3}{8}.33dfrac{1}{3}c)1dfrac{4}{23}+dfrac{5}{21}-dfrac{4}{23}+0,5+dfrac{16}{21}d)dfrac{2^{12}.3^5-4^6.81}{2^2.3^6+8^4.3^5}e)4left(-dfrac{1}{2}right)^2-2.left(dfrac{-1}{2}right)^2+3.left(dfrac{-1}{2}right)+1g)sqrt{dfrac{4}{81}}:sqrt{dfrac{25}{81}}-1dfrac{2}{5}
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thực hiện phép tính
a)\(\left(\dfrac{9}{25}-2,18\right):\left(3\dfrac{4}{5}+0,2\right)\)
b)\(\dfrac{3}{8}.19\dfrac{1}{3}-\dfrac{3}{8}.33\dfrac{1}{3}\)
c)\(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
d)\(\dfrac{2^{12}.3^5-4^6.81}{2^2.3^6+8^4.3^5}\)
e)\(4\left(-\dfrac{1}{2}\right)^2-2.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{-1}{2}\right)+1\)
g)\(\sqrt{\dfrac{4}{81}}:\sqrt{\dfrac{25}{81}}-1\dfrac{2}{5}\)
\(\dfrac{-9}{46}\)-4\(\dfrac{1}{23}\)\(\div\)(3\(\dfrac{1}{4}\)-x\(\div\)\(\dfrac{3}{5}\))+2\(\dfrac{8}{23}\)=1
\(\Leftrightarrow-\dfrac{93}{23}:\left(\dfrac{13}{4}-x\cdot\dfrac{5}{3}\right)=1-\dfrac{99}{46}=-\dfrac{53}{46}\)
\(\Leftrightarrow\dfrac{13}{4}-\dfrac{5}{3}x=-\dfrac{99}{23}:-\dfrac{53}{46}=\dfrac{198}{53}\)
=>5/3x=-103/212
hay x=-309/1060
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dfrac{4}{9}.19dfrac{1}{3}+dfrac{-4}{9}.39dfrac{1}{3}+dfrac{-3^2}{5}:left(-0,2right)
dfrac{left(-5^3right)^2}{27}.dfrac{3}{23}.dfrac{6^2}{-5^6}
1dfrac{4}{23}+dfrac{5}{21}-dfrac{4}{23}+0,5+dfrac{16}{21}
dfrac{3}{7}.19dfrac{1}{3}-dfrac{3}{7}:33dfrac{1}{3}
dfrac{3}{4}-left(x+dfrac{1}{2}right)dfrac{4}{5}
x:(-2,14)(-3,12):1,2
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\(\dfrac{4}{9}.19\dfrac{1}{3}+\dfrac{-4}{9}.39\dfrac{1}{3}+\dfrac{-3^2}{5}:\left(-0,2\right)\)
\(\dfrac{\left(-5^3\right)^2}{27}.\dfrac{3}{23}.\dfrac{6^2}{-5^6}\)
\(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}:33\dfrac{1}{3}\)
\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
x:(-2,14)=(-3,12):1,2
Tính 1 câu thoy nhé !
\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}.33\dfrac{1}{3}\)
= \(\dfrac{3}{7}.\left(19\dfrac{1}{3}-33\dfrac{1}{3}\right)\)
=\(\dfrac{3}{7}.-14=-6\)
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-\(\dfrac{4}{7}\)+\(\dfrac{15}{4}\)-(\(\dfrac{11}{4}\)+\(\dfrac{3}{7}+\dfrac{1}{2}-\dfrac{1}{3}\))
\(\dfrac{1}{5}\left(\dfrac{1}{2}-\dfrac{1}{3}\right):\left(\dfrac{-9}{10}\right)+\dfrac{-7}{3}\)
\(\dfrac{-20}{23}+\dfrac{2}{3}-\dfrac{3}{23}+\dfrac{2}{5}+\dfrac{7}{15}\)
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