\(\dfrac{2.3.5.\left(-7\right).12}{3.\left(-5\right).7.14}=\dfrac{2.3.5.\left(-7\right).12}{3.5.\left(-7\right).2.7}=\dfrac{12}{7}\)

\(\dfrac{2.3.5.\left(-7\right).12}{3.\left(-5\right).7.14}=\dfrac{1.1.1.\left(-1\right).12}{1.\left(-1\right).1.7}=\dfrac{-12}{-7}=\dfrac{12}{7}\)

h) \(\left(a-b\right)-\left(c-d\right)-\left(a+d\right)-\left(b+c\right)\)

\(=a-b-c+d-a-d-b-c\)

\(=\left(a-a\right)-\left(b+b\right)-\left(c+c\right)+\left(d+d\right)\)

\(=-2b-2c\)

i) \(-\left(-a+c-d\right)-\left(c-a+d\right)\)

\(=a-c+d-c+a-d\)

\(=\left(a+a\right)-\left(c+c\right)+\left(d+d\right)\)

\(=2a-2c\)

k) \(-\left(a+b-c+d\right)+\left(a-b-c-d\right)\)

\(=-a-b+c-d+a-b-c-d\)

\(=\left(-a+a\right)-\left(b+b\right)+\left(c-c\right)-\left(d+d\right)\)

\(=-2b-2d\)

n) \(-a\left(-b-c+d-e\right)-\left(-a\right)-\left(-b+c-d\right)\)

\(=ab+ac-ad+ae+a+b-c+d\)

Trả lời:

M = ( x - 3 )³ - ( x + 1 )³ - 12x ( x - 1 )

= x³ - 3.x².3 + 3.x.3² - 3³ - ( x³ + 3.x².1 + 3.x.1² + 1³ ) - 12x² - 12x

= x³ - 9x² + 27x - 27 - x³ - 3x² - 3x - 1 - 12x² - 12x

= - 24x² + 12x - 28

ĐAY NÈ BẠN

nhầm,  đây nhá

M= (x - 3)3 - (x + 1)3 + 12x (x -1)

= x3 -  9x2 + 27x - 27 - x3  - 3x2 - 3x - 1 + 12x2 - 12x

= 12x - 28

Đây là phân số tối giản rồi

M = (x - 3)³ - (x + 1)³ + 12x (x - 1)

= x³ - 9x² + 27x - 27 - (x³ + 3x² + 3x + 1) + 12x² - 12x

= x³ - 9x² + 27x - 27 - x³ - 3x² - 3x - 1 + 12x² - 12x

= (x³ - x³) + (12x² - 9x² - 3x²) + (27x - 3x - 12x) - (27 + 1)

= 12x - 28

Bỏ () Rồi tính nhé
 

nhấn vào đúng 0 sẽ ra

tách 2 ở mẫu ra thì mẫu nó sẽ giống tử  42.44 + 152.158 + 162.170     =       2( 21.22 + 76.79 + 81.85 )

giản ước cuối cùng ra là 1/2

`a,-2022.(x+8)=0`

`=>x+8=0:(-2022)`

`=>x+8=0`

`=>x=0-8`

`=>x=-8`

`b,(7-x)(x+3)=0`

`@ TH1`

`7-x=0`

`=>x=7-0`

`=>x=7`

`@ TH2`

`x+3=0`

`=>x=0-3`

`=>x=-3`

`c,2023x .(14-x)=0`

`@ TH1`

`2023x=0`

`=>x=0:2023`

`=>x=0`

`@ TH2`

`14-x=0`

`=>x=14-0`

`=>x=14`

`d,x^2-x=0`

`=>x(x-1)=0`

`@ TH1`

`x=0`

`@ TH2`

`x-1=0`

`=>x=0+1`

`=>x=1`

\(a,\left(-2022\right).\left(x+8\right)=0\\ \Rightarrow\left(x+8\right)=0:\left(-2022\right)\\ \Rightarrow x+8=0\\ \Rightarrow x=-8\\ b,\left(7-x\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}7-x=0\\x+3=0\end{matrix}\right. \Rightarrow\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\\ c,2023x.\left(14-x\right)=0\\ \Rightarrow\left[{}\begin{matrix}2023x=0\\14-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=14\end{matrix}\right.\\ d,x^2-x=0\\ \Rightarrow x\left(x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

\(\left(-2020\right).\left(x+8\right)=0\)

\(=>x+8=0=>x=-8\)

\(\left(7-x\right).\left(x+3\right)=0\)

\(=>\left[{}\begin{matrix}7-x=0\\x+3=0\end{matrix}\right.=>\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)

\(2023x.\left(14-x\right)=0\)

\(=>\left[{}\begin{matrix}x=0\\14-x=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=14\end{matrix}\right.\)

\(x^2-x=0\)

\(x\left(x-1\right)=0\)

\(=>\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

\(\frac{75}{2}\)

\(=\frac{\left(2.3\right)^6.\left(5.7\right)^7}{\left(2.7\right)^4.\left(3.5\right)^5}=\frac{2^6.3^6.5^7.7^7}{2^4.7^4.3^5.5^5}=\frac{2^2.3.5^2.7^3}{1.1.1.1}=\left(4.25\right).3.7^3=100.3.343=102900\)

kiều bích huyền ghi sai đề làm bậy luôn