tìm x
(x-5) x 30%= 20 x \(\dfrac{x}{100}\)+5
TÌM X biết:
(x-5).30/100= 20 X 100 +5
(x-5).3/10=2000+5
(x-5).3/10=2005
x-5=2005:3/10
x-5=2005.10/3
x-5=20050/3
x=20050/3 +5
x=20065/3
\(\left(x-5\right)\)\(.\)\(\frac{30}{100}\)\(=\)\(20\times100+5\)
\(\left(x-5\right)\)\(.\)\(\frac{3}{10}\)\(=\)\(2005\)
\(\left(x-5\right)\)\(=\)\(2005\)\(\div\)\(\frac{3}{10}\)
\(\left(x-5\right)\)\(=\)\(2005\)\(.\)\(\frac{10}{3}\)
\(\left(x-5\right)\)\(=\)\(\frac{20050}{3}\)
\(x=\frac{20055}{3}\)
Hok tốt
Tìm số tự nhiên, biết: (x-5).30/100=20.x/100+5
Tìm số tự nhiên x, biết rằng:
(x-5).30/100=20.x/100+5
tìm x
(x - 5) x 30% = 20 x \(\frac{x}{100}\)+5
x = 65 đấy bạn
nếu chưa chắc chắn thì bạn tính thử đi
chúc bạn học giỏi
\(\left\{{}\begin{matrix}y=20+x\\\dfrac{100}{x}-\dfrac{100}{20+x}=\dfrac{5}{6}\end{matrix}\right.\)
ĐKXĐ: \(x\notin\left\{0;-20\right\}\)
\(\left\{{}\begin{matrix}y=20+x\\\dfrac{100}{x}-\dfrac{100}{20+x}=\dfrac{5}{6}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\\dfrac{20}{x}-\dfrac{20}{x+20}=\dfrac{1}{6}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\\dfrac{20x+400-20x}{x\left(x+20\right)}=\dfrac{1}{6}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\\dfrac{400}{x\left(x+20\right)}=\dfrac{1}{6}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=x+20\\x\left(x+20\right)=2400\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\x^2+20x-2400=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\\left(x+60\right)\left(x-40\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=x+20\\\left[{}\begin{matrix}x+60=0\\x-40=0\end{matrix}\right.\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}y=x+20\\x\in\left\{-60;40\right\}\end{matrix}\right.\)(nhận)
=>\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x=-60\\y=x+20=-60+20=-40\end{matrix}\right.\\\left\{{}\begin{matrix}x=40\\y=x+20=60\end{matrix}\right.\end{matrix}\right.\)
Tìm x
a, -12 . (x-5)+ 7 . ( 3-x ) =15
b, 30(x+20 - 6(x-5) - 24 - x =100
b, 30(x+20) - 6(x-5) - 24 - x =100
30x+600-6x+30-24-x=100
30x-6x+x=100-600-30-24
25x=-554
x=\(-\frac{554}{25}\)
cho li-ke nha
a, -12 . (x-5)+ 7 . ( 3-x ) =15
-12x+60+21-7x=15
-12x7x=15-60-21
-21x=-66
x= -544/25
tick nha
Giải pt:
\(\dfrac{100}{x+20}\)-\(\dfrac{100}{x}\)=\(\dfrac{5}{12}\)
=) đây là bài giải bằng cách lập pt mà nãy bạn đã đăng nè:v mà giải thì ra vô nghiệm á bạn nên mik ko có làm:v
tìm x thuộc Z
a)30(x+20)-6(x-5)-24x=100
b)52-/x/=80
c)(-3).x+(-5)^1=(-2)^3.(-5)+1
Tìm X: \(\dfrac{30-x}{30}=\dfrac{8}{15};\dfrac{x+30}{72}=\dfrac{5}{8}\)
\(\dfrac{30-x}{30}=\dfrac{8}{15}\)
\(\Rightarrow\left(30-x\right)15=30\times8\)
\(\Rightarrow\left(30-x\right)15=240\)
\(\Rightarrow30-x=240:15\)
\(\Rightarrow30-x=16\)
\(\Rightarrow x=30-16\)
\(\Rightarrow x=14\)
__
\(\dfrac{x+30}{72}=\dfrac{5}{8}\)
\(\Rightarrow\left(x+30\right)8=5\times72\)
\(\Rightarrow\left(x+30\right)8=360\)
\(\Rightarrow x+30=360:8\)
\(\Rightarrow x+30=45\)
\(\Rightarrow x=45-30\)
\(\Rightarrow x=15\)