cho S = 1-\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)-\(\dfrac{1}{4}\)+....+\(\dfrac{1}{2011}\)-\(\dfrac{1}{2012}\)+\(\dfrac{1}{2013}\)
P= \(\dfrac{1}{1007}\)+\(\dfrac{1}{1008}\)+...+\(\dfrac{1}{2012}\)+\(\dfrac{1}{2013}\)
tính \(^{\left(S-P\right)^{2018}}\)