(\(20^2+18^2+16^2+...+4^2\)) - (\(19^2+17^2+...+3^2+1^2\)) = ?
\(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{2}{18}+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{19}+\dfrac{1}{20}}\)
\(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)
Biến đổi tử số
\(19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}\)
= 1 + \(\left(1+\dfrac{18}{2}\right)+\left(1+\dfrac{17}{3}\right)+\left(1+\dfrac{16}{4}\right)+...+\left(1+\dfrac{1}{19}\right)\)
= \(\dfrac{20}{20}+\dfrac{20}{2}+\dfrac{20}{3}+...+\dfrac{1}{19}\)
= 20 x \(\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)\)
Vậy \(A=\dfrac{19+\dfrac{18}{2}+\dfrac{17}{3}+\dfrac{16}{4}+...+\dfrac{1}{19}}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}\)
= \(\dfrac{20\times\left(\dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{19}+\dfrac{1}{20}\right)}{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{20}}=20\)
Vậy A = 20
B=20^2 - 19^2 + 18^2 - 17^2 + ......+ 2^2 - 1^2
3 *(2^2 + 1)*(2^4 + 1)*(2^8 + 1)*(2^16 + 1)
Tính giá trị của biểu thức: (20^2 + 18^2+ 16^2...+4^2+2^2)-(19^2+17^2+15^2+...+3^2+1^2)
\(\left(20^2+18^2+16^2+......+4^2+2^2\right)-\left(19^2+17^2+.....+3^2+1^2\right)\)
\(=20^2-19^2+18^2-17^2+......+2^2-1^2\)
\(=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+.......+\left(2-1\right)\left(2+1\right)\)
\(=39+35+....+7+3\)
\(=\left(39+3\right)\left[\left(39-3\right):4+1\right]:2=210\)
14. √(7-4√3)
15. √(8+2√15)
16. √(10-2√21)
17. √(11+2√18)
18. √(7+2√10)
19. √(7+4√3)
20. √(12-2√35)
14) \(\sqrt{7-4\sqrt{3}}=2-\sqrt{3}\)
15) \(\sqrt{8+2\sqrt{15}}=\sqrt{5}+\sqrt{3}\)
16) \(\sqrt{10-2\sqrt{21}}=\sqrt{7}-\sqrt{3}\)
17) \(\sqrt{11+2\sqrt{18}}=3+\sqrt{2}\)
18) \(\sqrt{7+2\sqrt{10}}=\sqrt{5}+\sqrt{2}\)
19) \(\sqrt{7+4\sqrt{3}}=2+\sqrt{3}\)
20) \(\sqrt{12-2\sqrt{35}}=\sqrt{7}-\sqrt{5}\)
\(\sqrt{7-4\sqrt{3}}=\sqrt{2^2-2.2.\sqrt{3}+\left(\sqrt{3}\right)^2}=\sqrt{\left(2-\sqrt{3}\right)^2}=\left|2-\sqrt{3}\right|=2-\sqrt{3}\)
√7−4√3=√22−2.2.√3+(√3)2=√(2−√3)2=∣∣2−√3∣∣=2−√3
1+2+3+4+5...+15+16+17+18+19+20
1+2+3+4+5+...+15+16+17+18+19+20
= ( 1 + 19 ) + ( 2 + 18 ) + ( 3 + 17 ) + ( 4 + 16 ) + ( 5 + 15 ) + ... + ( 9 + 11 ) + ( 10 + 20 )
= 20 + 20 + 20 + 20 + ... + 20 + 30
= 180 + 30 = 210
Tính số phần tử: \(\text{1+2+3+4+...+18+19+20}\)
\(=\left(20-1\right):1+1\) \(=20\)
Tổng : \(\dfrac{\left(20+1\right)\times20}{2}=210\)
20-19+18-17+16-15+ ...+4-3+2-1=...
20-19+18-17+16-15+14-13+12-11+11-10+10-9+9-8+8-7+7-6+6-5+5-4+4-3+3-2+2-1
=1+1+1+1+1+1+1+1+1+1+1+1+1+1+1
=1x15
=15
tk nhé
20 - 19 + 18 - 17 + 16 - 15 + ... + 4 - 3 + 2 - 1
= ( 20 - 19 ) + ( 18 - 17 ) + ( 16 - 15 ) + ... + ( 4 - 3 ) + ( 2 - 1 )
=> Có 10 cặp số 1
<=> 1 x 10
= 10
Đáp số: Kết quả là 10
20-19+18-17+16-15+...+4-3+2-1=...
20 - 19 + 18 - 17 + 16 - 15 +....+ 4-3 + 2 - 1
= ( 20 - 19 ) + ( 18 - 17 ) + ( 16 - 15 ) + .... + ( 4 - 3 ) + ( 2 - 1 )
= 1 + 1 + 1 + .... + 1 + 1
=> có 10 số 1
=> Tổng dãy số đó là : 1 . 1 = 10
nguyễn tiến mạnh
20 - 19 + 18 - 17 + 16 - 15 +....+ 4 - 3 + 2 - 1
= ( 20 - 19 ) + ( 18 - 17 ) + ( 16 - 15 ) + .... + ( 4 - 3 ) + ( 2 - 1 )
= 1 + 1 + 1 + .... + 1 + 1
=> có 10 số 1
=> Tổng dãy số đó là : 1 x 10 = 10
Bài 1:Tính
1, 5 mũ 3
2, 2 mũ 7
3, 4 mũ 4
4, 7 mũ 3
6, 3 mũ 5
7, 2 mũ 6
8, 3 mũ 4
9, 8 mũ 3
11, 13 mũ 2
12, 11 mũ 2
13, 14 mũ 2
14, 15 mũ 2
16, 17 mũ 2
17, 18 mũ 2
18, 19 mũ 2
19, 20 mũ 2
21, 10 mũ 4
22, 10 mũ 5
23, 10 mũ 6
24, 10 mũ 7
CÁC BẠN ƠI GIÚP MÌNH VỚI !!
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
tính 20-19+18-17+16-15+...+4-3+2-1=...
tính :20-19+18-17+16-15+...+4-3+2-1=...
20-19+18-17+16-15+...+4-3+2-1=(20-19)+(18-17)+(16-15)+...+(4-3)+(2-1) (có 10 nhóm)
=1+1+1+...+1+1( có 10 số 1) =10.