\(=95-95:\left\{6^2-\left(4^2+1\right)\right\}\)

\(=95-5=90\)

a, (-0,2)² \(\times\) 5 - \(\dfrac{2^{13}\times27^3}{4^6\times9^5}\)

= 0,04 \(\times\) 5 - \(\dfrac{2^{13}\times3^9}{2^{12}\times3^{10}}\)

= 0,2 - \(\dfrac{2}{3}\)

= \(\dfrac{2}{10}\) - \(\dfrac{2}{3}\)

=  - \(\dfrac{7}{15}\)

b, \(\dfrac{5^6+2^2.25^3+2^3.125^2}{26.5^6}\)

 = \(\dfrac{5^6+4.5^6+8.5^6}{26.5^6}\)

= \(\dfrac{5^6.\left(1+4+8\right)}{26.5^6}\)

= \(\dfrac{1}{2}\)

a, (-0,2)2 $\times$ 5 - 213×27346×9546×95213×273​

= 0,04 $\times$ 5 - 213×39212×310212×310213×39​

= 0,2 - 2332​

= 210102​ - 2332​

=  - 715157​

b, 56+22.253+23.125226.5626.5656+22.253+23.1252​

 = 56+4.56+8.5626.5626.5656+4.56+8.56​

= 56.(1+4+8)26.5626.5656.(1+4+8)​

= 1221​
 

Ta có: A = 2 + 2² + 2³ + 2⁴ + ... + 2⁹⁹ + 2¹⁰⁰

A = (2 + 2²) + (2³ + 2⁴) + ... + (2⁹⁹ + 2¹⁰⁰)

A = 6 + 2²(2 + 2²) + .... + 2⁹⁸(2 + 2²)

A = 6 + 2².6 + ... + 2⁹⁸.6

A = 6.(1 + 2² + ... + 2⁹⁸) ⋮6
Em lớp 5, sai thì bỏ qua cho em nhé ^^!

\(A=2+2^2+2^3+...+2^{100}\)

\(A=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{99}+2^{100}\right)\)

\(A=\left(2+2^2\right)+2^2\left(2+2^2\right)+...+2^{98}\left(2+2^2\right)\)

\(A=6+2^2.6+...+2^{98}.6\)

\(A=6\left(1+2^2+...+2^{98}\right)\)

Mà \(A=6\left(1+2^2+...+2^{98}\right)⋮6\)

\(\Rightarrow A⋮6\)

\(\frac{A}{2}=1+2+2^2+2^3+...+2^{99}\)

\(A-\frac{A}{2}=\frac{A}{2}=2^{100}-1\)suy ra      \(A=2^{101}-2\)

\(\dfrac{2^6.9^3}{6^8}=\dfrac{2^6.3^6}{2^8.3^8}=\dfrac{1}{2^2.3^2}=\dfrac{1}{36}\)

632

7⁵:7²+4⁶:4³+225

=7³+4³+225

=343+64+225

=407+225

=632

7^5:7^2+4^6:4^3+225

=343+64+225

=632

a, 2^3=8, 2^4=16,2^5=32, 2^6=64, 2^7=128, 2^8=256, 2^9=512, 2^10=1024

b, 3^2=9, 3^3=27, 3^4=81, 3^5=243

c, 4^2=16, 4^3=64, 4^4=256

d, 5^2=25, 5^3=125, 5^4=625

e, 6^2=36, 6^3=216, 6^4= 1296

\(\Leftrightarrow x:3+367\cdot\left(-2\right)=-60\)

=>x:3=674

hay x=2022

x= 2022