\(A=2219.2221.2226-2218.2223.2225\)

\(A=2219.(2223-2).2226-2218.2223.2225\)

\(A=2219.2223.2226-2.2219.2226-2218.2223.2225\)

\(A=2223.(2219.2216-2218.2225)-2.2219.2216\)

\(A=2223.\left\{(2218+1).(2215+1)-2218.2225\right\}-2.2219.2216\)

\(A=2223.(2218+2225+1)-2219.2226-2219.2226\)

\(A=2223.2219+2223.2225-2219.2226-2219.2226\)

\(A=(2223.2219-2219.2226)+2223.2225-2219.2225-2219\)

\(A=2219.(-3)+2225.4-2219\)

\(A=2219.(-4)+2225.4\)

\(A=4.(2225-2219)\)

\(A=4.6\)

\(A=24\)

\(B=3004.2999.2997-3003.2996.3001\)

\(B=3004.2999.(3001-4)-3003.2996.3001\)

\(B=(3003+1).2999.3001-3004.2999.4-3003.2996.3001\)

\(B=3003.(2996+3).3001+2999.3001-3004.2999.4-3003.2996.3001\)

\(B=3003.2996.3001+3.3003.3001-3.3004.2999+2999.3001-3004.2999-3003.2996.3001\)

\(B=3.(3003.3001-3004.2999)+2999.(3001-3004)\)

\(B=3.\left\{\left(3004-1\right).\left(2999+2\right)-3004.2999\right\}-3.2999\)

\(B=3.\left(3004.2999+2.3004-2999-2-3004.2999\right)-3.2999\)

\(B=3.(2.3003-2999)-3.2999\)

\(B=6.3003-6.2999\)

\(B=6.(3003-2999)\)

\(B=6.4\)

\(B=24\)

Mà \(A=24\) , \(B=24\)

\(\Rightarrow A=B\)

A=2219*(2223-2)*2226 - 2218*2223*2225

=2219*2223*2226 - 2*2219*2226 - 2218*2223*2225

=2223*(2219*2226 - 2218*2225) - 2*2219*2226

=2223*[(2218+1)*(2225+1) - 2218*2225] - 2*2219*2226

=2223*(2218+2215+1) - 2*2219*2226

=2223*2219+2223*2225 - 2219*2226 - 2219*2226

=(2223*2219 - 2219*2226) +2223*2225 - 2219*2225 - 2219

=2219*(-3) + 2225*4 - 2219

=2219*(-4) + 2225*4 = 4*(2225-2219) = 4*6 = 24

B=3004*2999*(3001-4) - 3003*2996*3001

=(3003+1)*2999*3001 - 3004*2999*4 - 3003*2996*3001

=3003*(2996+3)*3001 +2999*3001 - 3004*2999*4 - 3003*2996*3001

=3003*2996*3001+3*3003*3001 +2999*3001 - 3*3004*2999 - 3004*2999 - 3003*2996*3001

=3*(3003*3001 - 3004*2999) + 2999*(3001-3004)

=3*[(3004-1)*(2999+2) - 3004*2999] - 3*2999

=3*(3004*2999+2*3004 - 2999 - 2 - 3004*2999) - 3*2999

=3*(2*3003-2999) - 3*2999

=6*3003 - 6*2999 = 6*(3003-2999) = 6*4 = 24

===> A=B (=24)

3009 x 101 - 3009

= 3009 x 101 - 3009 - 1

= 3009 x (101 - 1)

= 3009 x 100

= 300900

$3009\times101-3009$

$=3009\times101-3009\times1$

$=3009\times(101-1)$

$=3009\times100$

$=300900$

3009 x 101 - 3009

=3009 x101 - 3009 x 1

=3009 x (101 -1)

=3009 x 100

=300900

3009 x 101 - 3009

= 3009 x 101 - 3009 x 1

= 3009 x (101 - 1)

= 3009 x 100

= 300900

Đặt \(x^{1003}=a;y^{1003}=b;1003=c\). Khi đó điều kiện đã cho 

\(\Leftrightarrow\left\{{}\begin{matrix}a+b=c\\a^2+b^2=2c\end{matrix}\right.\)

Ta có \(a^2+b^2=2c\Leftrightarrow\left(a+b\right)^2=2c+2ab\) \(\Leftrightarrow c^2-2c=2ab\) \(\Leftrightarrow ab=\dfrac{c^2-2c}{2}\)

Từ đó \(x^{3009}+y^{3009}=a^3+b^3=\left(a+b\right)\left(a^2+b^2-ab\right)\) \(=c\left(2c-\dfrac{c^2-2c}{2}\right)\) \(=\dfrac{6c^2-c^3}{2}\) \(=\dfrac{6.1003^2-1003^3}{2}=-501495486,5\)

(mình tính đúng luôn nhé)

e cảm ơn

\(3009+186+421\)

\(=\left(3009+421\right)+186\)

\(=3430+186\)

\(=3616\)

3009 + 186 + 421 = 3616

\(\text{3009+186+421}\)

\(=\left(3009+421\right)+186\)

\(=3430+186\)

\(=3616\)

\(A=1-4+7-10+...+2995-2998+3001\)

\(A=1+3+3+...+3+3\)

Từ 4\(\rightarrow\)3001 có: \(\left(3001-4\right):3+1=1000\)

Tổng từ \(1\)\(\rightarrow3001\): \(1+3.1000=3001\)

Vậy \(A=3001\)

A = x(x – 2009) – y(2009 – x)

ó A = x(x – 2009) + y(x – 2009)

ó A = (x + y)(x – 2009)

Với x =3009 và y = 1991, giá trị của biểu thức là:

A = (3009 + 1991)(3009 – 2009) = 5000.1000 = 5000000

Đáp án cần chọn là:A

(3x - 3009) + 72 = 72

3x - 3009 = 72 - 72

3x - 3009 = 0

3x = 3009

x = 1003

(3x - 3009) + 72 = 72

          3x - 3009 = 72 - 72

           3x - 3009 = 0

                      3x = 0 + 3009

                       3x = 3009

                          x = 3009 : 9

                           x= 1003

Chúc bạn học tốt!

(3x-3009)+72=72

(3x-3009)      =72-72

3x-3009        =0

3x                 = 0+3009

3x                 = 3009

  x                 =3009:3

  x                 = 1003

vậy x=1003