15498118,75

Tính máy tính là ra

a) \(5x-65=5.3^2 \\ 5x-65=45\\5x=45+65\\5x=110\\x=22\)

b) \(200-(2x+6)=4^3\\2x+6=200-4^3\\2x+6=136\\2x=130\\x=65\)

c) \(2(x-51)=2.2^3+20\\2(x-51)=16+20\\2(x-51)=36\\x-51=18\\x=51+18=69\)

d) \(135-5(x+4)=35\\5(x+4)=135-45\\5(x-4)=90\\x-4=18\\x=18+4=22\)

e) \((2x-4)(15-3x)=0\\2(x-2).3(5-x)=0\\(x-2)(5-x)=0\\ \left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right. \\ \left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)

f) \(2^{x+1} . 2^{2014}=2^{2016} \\ (2^{x+1} . 2^{2014}):2^{2014}=2^{2016} :2^{2014} \\ 2^{x=1}=2^{2016-2014} \\2^{x+1}=2^2\\x+1=2\\x=1\)

g) \(15+(x-1)^3=43\\(x-1)^3=15-42\\(x-1)^3=-27\\(x-1)^3=(-3)^3\\x-1=-3\\x=-2\)

h) \(15-x=17+(-9)\\15-x=17-9\\15-x=8\\x=15-8\\x=7\)

i) \(|x-5|=|-7|+|-4|\\|x-5|=7+4\\|x-5|=11\\ \left[ \begin{array}{l}x-5=11\\x-5=-11\end{array} \right. \\ \left[ \begin{array}{l}x=16\\x=-6\end{array} \right.\)

k) \(|x-3|-12=-9+|-7|\\|x-3|-12=-9+7\\|x-3|-12=-2\\|x-3|=10 \\ \left[ \begin{array}{l}x-3=10\\x-3=-10\end{array} \right. \\ \left[ \begin{array}{l}x=13\\x=-7\end{array} \right.\)

Lời giải:

1. $(x+2)-2=0$

$x+2=2$

$x=0$

2.

$(x+3)+1=7$

$x+3=7-1=6$

$x=6-3=3$

3.

$(3x-4)+4=12$

$3x-4+4=12$

$3x=12$

$x=12:3=4$

4.

$(5x+4)-1=13$

$5x+4=13+1=14$

$5x=14-4=10$

$x=10:5=2$

5.

$(4x-8)-3=5$

$4x-8=5+3=8$

$4x=8+8=16$

$x=16:4=4$

6.

$3+(x-5)=7$

$x-5=7-3=4$

$x=4+5=9$

7.

$8-(2x-4)=2$

$2x-4=8-2=6$

$2x=6+4=10$

$x=10:2=5$

8.

$7+(5x+2)=14$

$5x+2=14-7=7$

$5x=7-2=5$

$x=5:5=1$

9.

$5-(3x-11)=1$

$3x-11=5-1=4$

$3x=11+4=15$

$x=15:3=5$

10.

$16-(8x+2)=6$

$8x+2=16-6=10$

$8x=10-2=8$

$x=8:8=1$

\(a,-13-\left(-15\right)=-13+15=2\)

\(b,43-\left(56-43\right)+\left(56-12\right)=43-13+44=30+44=74\)

\(c,4^4:2^8+\left[13-\left(-5\right)\right]\cdot\left(-3\right)=256:256+\left(13+5\right)\cdot\left(-3\right)\)\(=1+18\cdot\left(-3\right)=1+\left(-54\right)=-53\)

\(d,135\cdot\left(13-37\right)+37\cdot\left(135-13\right)=135\cdot\left(-24\right)+37\cdot122\)\(=-3240+4514=1274\)

a, -13-(-15)=-13+15=2

b, 43-(56-43)+(56-12)=43-13+44=30+44=74

c, 4^4:2^8+[13-(-5)].(-3)=256:256+(13+5).(-3)=1+18.(-3)=1+(-54)=-53

d, 135.(13-37)+37.(135-13)=135.(-24)+37.122=-3240+4514=1274

a)-13-(-15)=-13+15=2

b)43-(56-43)+(56-12)=43-56+43+56-12=43+(56-56)-12=43+0-12=43-12=31

c)=256:256+13+5.(-3)=1+18.(-3)=19.(-3)=-57

d)135.(13-37)+37.(135-13)=135.13-135.37+(37.135-37.13)=(135.13-37.135)+(135.37-37.13)=135.37-13+37.

a. \(\frac{3}{4}\times x+\frac{5}{6}\times x-\frac{5}{2}=7\)

\(x\times\left(\frac{3}{4}+\frac{5}{6}\right)=7+\frac{5}{2}\)

\(x\times\left(\frac{9}{12}+\frac{10}{12}\right)=\frac{14}{2}+\frac{5}{2}\)

\(x\times\frac{19}{12}=\frac{19}{2}\)

\(x=\frac{19}{2}\div\frac{19}{12}\)

\(x=\frac{19}{2}\times\frac{12}{19}\)

\(x=6\)

b) \(12\times x-12\times84=0\)

\(12\times x=12\times84\)

\(x=84\)

Bài 3: 

Gọi số nhóm là x

Theo đề, ta có: \(x\in\left\{1;2;3;4;6;9;12;18;36\right\}\)

mà 2<x<6

nên \(x\in\left\{3;4\right\}\)

Vậy: Có 2 cách chia nhóm

a) 25 - x = 12 + 6  =18

x=25-18=7 Vậy x=7

b) 7 + 2 x ( x -3 ) = 11   

2.(x-3)=11-7=4

x-3=4:2=2

x=3+2=5                          

c) 102 : ( 2.x + 13) : 4) = 6   

(2.x+13):4=102:6=17

2.x+13=17.4=68

2.x=68-13=55

x=27,5 Vậy x=27,5

Bài 3: 

Gọi số nhóm là x

Theo đề, ta có: 

mà 2<x<6

nên 

Vậy: Có 2 cách chia nhóm

còn bài 1 chắc bn làm đc nha tick mk nha

b) -26 - ( x - 7 ) = 0

               x - 7   = -26 - 0

                x - 7  = -26

                x        = -26 + 7

                 x       = -19

Bài 2 :

a) 3 - ( 17 - x ) = -12

          ( 17 - x ) = 3 - ( -12 )

          ( 17 - x ) = 15

                    x  = 17 - 15

                    x  = 2

b) -26 - ( x - 7)=0

             x - 7 = -26 -0

            x - 7 = -26

              x = -26 + 7

             x = -19

\(a,\)\(\left(5x-15\right)\div5=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

\(b,\)\(84-4\left(2x+1\right)=48\)

\(\Rightarrow84-8x-4=48\)

\(\Rightarrow8x=32\)

\(\Rightarrow x=4\)

\(\left(5\times x-15\right):5=0\)

=> \(5\times x-15=0\)

=> \(5\times x=15\)

=> \(x=3\)

\(84-4\times\left(2\times x+1\right)=48\)

=> \(4\times\left(2\times x+1\right)=84-48\)

=> \(4\times\left(2\times x+1\right)=36\)

=> \(2\times x+1=9\)

=> \(2\times x=9-1\)

=>  \(2\times x=8\)

=> \(x=4\)