7.(x-3)-5.(3-x)=11x-5
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7(x-3)-5(3-x)=11x-5
7(x-9)-5(6-x)=-6+11x
7(x-3)-5(3-x)=11x-5
<=>7(x-3)+5(x-3)-11x+5=0
<=>12(x-3)-11x+5=0
<=>12x-36-11x+5=0
<=>x-31=0
<=>x=31
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7(x-9)-5(6-x)=-6+11x
7(x-3)-5(3-x)=11x-5
a, => 7x-63-30+5x=11x-6
=> 12x-93=11x-6
=> 12x=11x-6+93 = 11x+87
=> 12x-11x=87
=> x=87
b, => 7x-21-15+5x=11x-5
=> 12x-36=11x-5
=> 12x=11x-5+36 = 11x+31
=> 12x-11x=31
=> x=31
Tk mk nha
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a) -12+(x-9)<0 tìm x thuộc Z
b)x-(13-x)=-24+(-7+x)
c) (x - 7)+( 5-x)=12-(-8+x)
d)5(x-6)-2(x+3)=12
e)3(x-4)-(8-x)=12
f) 7(x-3)-5(3-x)=11x-5
g) 7(x-9)-5(6-x)=-6+11x
a) -12+(x-9)<0 tìm x thuộc Z
b)x-(13-x)=-24+(-7+x)
c) (x - 7)+( 5-x)=12-(-8+x)
d)5(x-6)-2(x+3)=12
e)3(x-4)-(8-x)=12
f) 7(x-3)-5(3-x)=11x-5
g) 7(x-9)-5(6-x)=-6+11x
7.(x-3)-5.(3-x) = 11x-5
\(7.\left(x-3\right)-5.\left(3-x\right)=11x-5\)
\(7x-21-15+5x=11x-5\)
\(12x-36=11x-5\)
\(12x-11x=-5+36\)
\(x=31\)
Vậy \(x=31\)
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\(7.\left(x-3\right)-5.\left(3-x\right)=11x-5\)
\(7x-7.3-5.3+5x=11x-5\)
\(7x-21-15+5x=11x-5\)
\(7x-\left(21+15\right)+5x=11x-5\)
\(7x-36+5x=11x-5\)
\(7x+5x-36=11x-5\)
\(12x-11x=\left(-5\right)+36\)
\(x=31\)
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7*(x - 3)-5*(3-x)=11x - 5
7 ( x – 3 ) – 5 ( 3 – x ) = 11x – 5
\(7\left(x-3\right)-5\left(3-x\right)=11x-5.\)
\(\left(7x-21\right)-\left(15-5x\right)=11x-5\)
\(7x-21-15+5x=11x-5\)
\(12x-36=11x-5\)
\(12x-11x=36-5\)
\(x=31\)
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7 (x - 3) - 5 (3 - x) = 11x - 5
7x - 7.3 - 5.3 - 5x = 11x - 5
7x - 5x - 21 -15 = 11x - 5
2x - (21 + 15) = 11x - 5
2x - 36 = 11x - 5
2x - 11x = 36 - 5
-9x = 31
x = 31:(-9)
x = \(\frac{-31}{9}\)
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Mik làm sai rồi, như bn Ahwi mới đúng
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a.7.(x-9)-5.(6-x)=-6x+11x
b.7.(x-3)-5.(3-x)=11-5x
a ) 7. ( x - 9 ) - 5( 6 - x ) = -6x + 11x
( 7x - 63 ) - ( 30 - 5x ) = 5x
7x - 63 - 30 + 5x = 5x
=> 7x - 63 - 30 = 0
=> 7x = 0 + 30 + 63
=> 7x = 93
=> x = 93/7
b ) 7 . ( x - 3 ) - 5 ( 3 - x ) = 11 - 5x
( 7x - 21 ) - ( 15 - 5x ) = 11 - 5x
7x - 21 - 15 + 5x = 11 - 5x
7x - ( 21 + 15 ) + 5x + 5x = 11
( 5x + 5x + 7x ) - 36 = 11
17x - 36 = 11
17x = 11 + 36
17x = 47
x = 47/17
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7.(x-3)-5.(3-x)=11x-5
giúp mk
7x - 21 -15 + 5x = 11x - 5
12x - 36 = 11x - 5
12x - 11x = - 5 + 36
x = 31
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TA có 7(x-3)-5(3-x)=11x-5
<=> 7x-21-15+5x=11x-5
<=> 12x-36=11x-5
<=>12x-11x=36-5
<=>x=31
Vậy x=31
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7 ( x - 5 ) - 5 ( 3 - x ) = 11x - 5
7x - 35 - 15 + 5x = 11x - 5
7x + 5x - 11x = 35 + 15 - 5
x = 45
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