\(7\left(x-3\right)-5\left(3-x\right)=11x-5\)
\(\Leftrightarrow7x-21-15+5x=11x-5\)
\(\Leftrightarrow7x+5x-11x=-5+15+21\)
\(\Leftrightarrow x=31\)
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7(x−3)−5(3−x)=11x−57(x−3)−5(3−x)=11x−5
⇔7x−21−15+5x=11x−5⇔7x−21−15+5x=11x−5
⇔7x+5x−11x=−5+15+21⇔7x+5x−11x=−5+15+21
⇔x=31
Vậy x=31
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