\((\dfrac{-1}{3}+\dfrac{5}{6}).11-7=\dfrac{3}{6}.11-7\)
mọi người giúp mình vs ai trả lời thì mình sẽ theo dõi nha
\(\dfrac{1}{3}\)+\(\dfrac{5}{6}\)*(x-\(\dfrac{11}{5}\))=\(\dfrac{3}{4}\).mọi ng cho mình lời giải chi tiết và cụ thể vs ạ. đây là bài tìm x ạ.
\(\dfrac{1}{3}+\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\cdot\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\cdot\dfrac{6}{5}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}\)
\(x=\dfrac{27}{10}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}:\dfrac{5}{6}\)
\(x-\dfrac{11}{5}=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}+\dfrac{11}{5}=\dfrac{27}{10}\)
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{1}{3}+\dfrac{5}{6}\times\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}\)
\(\dfrac{5}{6}\times\left(x-\dfrac{11}{5}\right)=\dfrac{3}{4}-\dfrac{1}{3}\)
\(\dfrac{5}{6}\times\left(x-\dfrac{11}{5}\right)=\dfrac{5}{12}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\div\dfrac{5}{6}\)
\(x-\dfrac{11}{5}=\dfrac{5}{12}\times\dfrac{6}{5}\)
\(x-\dfrac{11}{5}=\dfrac{6}{12}\)
\(x=\dfrac{6}{12}+\dfrac{11}{5}\)
\(x=\dfrac{27}{10}\)
Tính :
a) b)
\(\dfrac{\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}}{\dfrac{25}{7}+\dfrac{25}{7}+\dfrac{25}{11}}\) \(\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{1}{23}}\)
Mong mọi người sẽ trả lời nhanh ai nhanh mình sẽ cho 2 like luôn
dễ lắm bạn ơi bọn mình học rùi
bn lấy tử số của từng mỗi rồi chia cho mẫu của từng cái rồi rút gọn lafd ra
\(\dfrac{\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}}{\dfrac{25}{7}+\dfrac{25}{9}+\dfrac{25}{11}}\cdot\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{1}{23}}\)
=\(\dfrac{5\cdot\left(\dfrac{1}{7}+\dfrac{1}{9}+\dfrac{1}{11}\right)}{25\left(\dfrac{1}{7}+\dfrac{1}{9}+\dfrac{1}{11}\right)}\cdot\dfrac{4\left(1+\dfrac{1}{73}+\dfrac{1}{115}\right)}{5+\dfrac{5}{73}-\dfrac{5}{115}}\)
=\(\dfrac{5}{25}\cdot\dfrac{4\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}{5\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}\)
=\(\dfrac{1}{5}\cdot\dfrac{4}{5}\)=\(\dfrac{4}{25}\)
\(\dfrac{\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}}{\dfrac{25}{7}+\dfrac{25}{9}+\dfrac{25}{11}}\cdot\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{1}{23}}\)
\(=\dfrac{\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}}{5\left(\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}\right)}\cdot\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{5}{115}}\)
\(=\dfrac{1}{5}\cdot\dfrac{4\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}{5\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}\)
\(=\dfrac{1}{5}\cdot\dfrac{4}{5}=\dfrac{4}{25}\)
Giúp mình với:
a) A=\(\dfrac{1}{3}\)-\(\dfrac{3}{5}\)+\(\dfrac{5}{7}\)-\(\dfrac{7}{9}\)+\(\dfrac{9}{11}\)-\(\dfrac{11}{13}\)+\(\dfrac{13}{15}\)+\(\dfrac{11}{13}-\dfrac{9}{11}+\dfrac{7}{9}-\dfrac{5}{7}+\dfrac{3}{5}-\dfrac{1}{3}\)
b) B= \(\dfrac{1}{9.10}-\dfrac{1}{8.9}-\dfrac{1}{7.8}-...-\dfrac{1}{2.3}-\dfrac{1}{1.2}\)
a)A=\(\left(\dfrac{1}{3}-\dfrac{1}{3}\right)+\left(\dfrac{-3}{5}+\dfrac{3}{5}\right)+\left(\dfrac{5}{7}-\dfrac{5}{7}\right)+\left(\dfrac{-7}{9}+\dfrac{7}{9}\right)+\left(\dfrac{9}{11}-\dfrac{9}{11}\right)+\left(\dfrac{-11}{13}+\dfrac{11}{13}\right)+\dfrac{13}{15}\)
A=0+0+0+...+0+\(\dfrac{13}{15}\)
A=\(\dfrac{13}{15}\)
b) Ta có: \(-\dfrac{1}{9\cdot10}-\dfrac{1}{8\cdot9}-\dfrac{1}{7\cdot8}-...-\dfrac{1}{2\cdot3}-\dfrac{1}{1\cdot2}\)
\(=-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)\)
\(=-\left(1-\dfrac{1}{10}\right)=\dfrac{-9}{10}\)
a \(\dfrac{3}{4}+\dfrac{5}{6}\)=
b\(\dfrac{1}{2}+\dfrac{7}{12}\)=
c\(\dfrac{2}{3}\)x\(\dfrac{3}{4}\)=
d\(\dfrac{7}{4}:2\)=
ghi chi tiết giúp mình với ạ.Cảm ơn mọi người!
`3/4 + 5/6 = 9/12 + 10/12 = 19/12`
`1/2 + 7/12 = 6/12 + 7/12 = 13/12`
`2/3 xx 3/4 = 2/4 = 1/2`
`7/4 : 2 = 7/4 xx 1/2 = 7/8`
\(a,\dfrac{3}{4}+\dfrac{5}{6}=\dfrac{18}{24}+\dfrac{20}{24}=\dfrac{38}{24}=\dfrac{19}{12}\)
\(b,\dfrac{1}{2}+\dfrac{7}{12}=\dfrac{6}{12}+\dfrac{7}{12}=\dfrac{13}{12}\)
\(c,\dfrac{2}{3}x\dfrac{3}{4}=\dfrac{2}{4}\)
\(d,\dfrac{7}{4}:2=\dfrac{7}{4}x\dfrac{1}{2}=\dfrac{7}{8}\)
\(\dfrac{-2}{11}+\dfrac{-1}{6}+\dfrac{52}{264}+\dfrac{3}{22}+\dfrac{5}{24}+\dfrac{-7}{8}\) giúp với nha
\(\dfrac{-2}{11}+\dfrac{-1}{6}+\dfrac{52}{264}+\dfrac{3}{22}+\dfrac{5}{24}+\dfrac{-7}{8}=\dfrac{-15}{22}\)
E=\(\dfrac{98:\left(\dfrac{4}{5}.1,25\right)}{0,64-\dfrac{1}{25}}\) + \(\dfrac{\left(1.08-\dfrac{2}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{17}}\)
mọi người ơi giúp mình bài này vơi , ai làm đc mik tick cho
\(E=\dfrac{98:\left(\dfrac{4}{5}\cdot\dfrac{5}{4}\right)}{\dfrac{16}{25}-\dfrac{1}{25}}+\dfrac{\left(\dfrac{27}{25}-\dfrac{2}{25}\right)\cdot\dfrac{7}{4}}{\left(\dfrac{59}{9}-\dfrac{13}{4}\right)\cdot\dfrac{36}{17}}\\ E=\dfrac{98}{\dfrac{3}{5}}+\dfrac{\dfrac{7}{4}}{\dfrac{119}{36}\cdot\dfrac{36}{17}}\\ E=\dfrac{490}{3}+\dfrac{\dfrac{7}{4}}{7}=\dfrac{490}{3}+\dfrac{1}{4}=\dfrac{1963}{12}\)
Tìm y:
a) (y - \(\dfrac{1}{2}\) ) x \(\dfrac{5}{3}\) = \(\dfrac{7}{4}\) + \(\dfrac{1}{2}\) b) ( y + \(\dfrac{2}{5}\) ) : \(\dfrac{5}{3}\) = \(\dfrac{7}{5}\)
Nhớ giải chi tiết giúp mik nhé
Mình sẽ theo dõi
Giúp mình với mọi người \(x-3\dfrac{1}{2}x=-2\dfrac{6}{7}\)
\(x\left(1-3\dfrac{1}{2}\right)=\dfrac{-20}{7}\)
\(x\cdot-\dfrac{5}{2}=-\dfrac{20}{7}\)
\(x=-\dfrac{20}{7}:-\dfrac{5}{2}\)
\(x=\dfrac{50}{7}\)
Cho\(\dfrac{x}{7}\) = \(\dfrac{y}{3}\) = \(\dfrac{z}{11}\) và x + y + z = 42 . Tính x , y , z ?
Mọi người giúp mình với !
Áp dụng t/c dtsbn:
\(\dfrac{x}{7}=\dfrac{y}{3}=\dfrac{z}{11}=\dfrac{x+y+z}{3+7+11}=\dfrac{42}{21}=2\\ \Rightarrow\left\{{}\begin{matrix}x=14\\y=6\\z=22\end{matrix}\right.\)