Bỏ dấu ngoặc của biểu thức :

a) a+(b+c) = a+b+c

b) a+(-b+c) = a-b+c

c) a-(-b+c) = a+b-c

d) a-(-b-c) = a-b+c

kết quả với a=0, b=1, c=-2 thì theo mk nghĩ là bn đã tính đúng rồi nha

a) a+(b+c) = a+b+c

b) a+(-b+c)= a-b+c

c) a-(-b+c)= a+b-c

d) a-(-b-c)=a+b+c

mik la hsg toan dang nay mik hok r

a, a+b+b

b,a-b+c

c, a+b-c

d, a+b+c

ktra kq~

a, 0+1+-2=-1    và  0+(1+-2)=-1

...... Tự làm nhô ( cho tui 1 tym đi muwfkkk)

$A = (a + b) - (a + b) + (a - c) - (a + c)$

$A=a+b-a-b+a-c-a-c$

$A=-2c$

A = (a + b) - (a - b) + (a - c) - (a + c)
A = a + b - a + b + a - c - a - c
A = 2b

a)(a+b)-(a-b)+(a-c)-(a+c) 

=a+b-a+b+a-c-a-c

=2b-2c

b)(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

=a+b-c+a-b+c-b-c+a-a+b+c

=2a

Giải:

a) A=(a+b)-(a-b)+(a-c)-(a+c)

    A=a+b-a+b+a-c-a-c

    A=0+(a-a)-c-c

    A=0+0-c-c

    A=-c-c

b) B=(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

    B=a+b-c+a-b+c-b-c+a-a+b+c

    B=(a+a+a-a)+(b-b-b+b)+(-c+c-c+c)

    B=(a+a)+0+0

    B=a+a

Chúc bạn học tốt!

Làm lại:

a) A=(a+b)-(a-b)+(a-c)-(a+c)

    A=a+b-a+b+a-c-a-c

    A=(a-a+a-a)+(b+b)+(-c-c)

    A=(b+b)+(-c-c)

    A=2b-2c

Chúc bạn học tốt!

A=a+b-a+b+a-c-a-c=2b-2c

B=a+b-c+a-b+c-b+c-a-a+b+c=2c

\(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)

\(\Leftrightarrow A=a+b-a+b+a-c-a-c\)

\(\Leftrightarrow A=\left(a-a+a-a\right)+\left(b+b\right)-\left(c+c\right)\)

​\(\Leftrightarrow A=0+2b-2c\)​

\(\Leftrightarrow A=2b-2c\)

\(\Leftrightarrow A=2\left(b-c\right)\)

\(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b-c+a\right)-\left(a-b-c\right)\)

\(\Leftrightarrow B=a+b-c+a-b+c-b+c-a-a+b+c\)

\(\Leftrightarrow B=\left(a+a-a-a\right)+\left(b-b-b+b\right)-\left(c-c-c-c\right)\)

\(\Leftrightarrow B=0+0-\left(-2c\right)\)

\(\Leftrightarrow B=-\left(-2c\right)\)

\(\Leftrightarrow B=2c\)

a) A = ( a + b ) - ( a - b ) + ( a - c ) - ( a + c )

 = a + b - a + b + a - c - a - c

 = ( a - a + a - a ) + ( b + b ) + ( - c - c )

= 0 + 2b + 2(-c)[ - c - c = -c + ( -c )]

= 2b + 2(-c)

=2(b - c )(= 2 . [ b + ( - c ) ]  )

b) B = ( a + b - c ) + ( a - b + c )- ( b + c - a ) - ( a - b - c )

   B = a + b - c + a - b + c - b - c + a - a + b + c

   B = ( a + a + a - a ) + ( b - b - b + b ) + ( -c + c - c + c )

   B = 2a + 0 + 0

   B = 2a

a,A=a+b-a+b+a-c-a-c

=2b-2c-a

b,B=a+b-c+a-b+c-b-c+a-a+b+c

=2a+0b+0c

1: =a-b+c-a-c=-b

2: =a+b-b+a+c=2a+c

3: =-a-b+c+a-b-c=-2b

4: =ab+ac-ab-ad-ac+ad=0

a,(a+b)-(a-b)+(a-c)-(a+c)

=a+b-a+b+a-c-a-c

=2b+2(-c)

b,(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)

=a+b-c+a-b+c-b-c+a-a+b+c

=2a

a) a+b-a+b+a-c-a-c

=.........................bạn tự đơn giản biểu thức nhé

b) a+b-c+a-b+c-a-c+a-a+b+c

=.....................................

a) `A=(a+b)-(a-b)+(a-c)-(a+c)`

`=a+b-a+b+a-c-a-c`

`=2b-2c`

b) `B=(a+b-c)+(a-b+c)-(b+c-a)-(a-b-c)`

`=a+b-c+a-b+c-b-c+a-a+b+c`

`=2a`

\(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\)

\(A=a+b-a+b+a-c-a-c\)

\(A=2b-2c\)

\(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\)

\(B=a+b-c+a-b+c-b-c+a-a+b+c\)

\(B=2a\)

a) \(A=\left(a+b\right)-\left(a-b\right)+\left(a-c\right)-\left(a+c\right)\) 

\(A=a+b-a+b+a-c-a-c\) 

\(A=\left(a-a+a-a\right)+\left(b+b\right)+\left(-c-c\right)\) 

\(A=0+2b+-2c\) 

\(A=2b-2c\) 

b) \(B=\left(a+b-c\right)+\left(a-b+c\right)-\left(b+c-a\right)-\left(a-b-c\right)\) 

\(B=a+b-c+a-b+c-b-c+a-a+b+c\) 

\(B=\left(a+a+a-a\right)+\left(b-b-b+b\right)+\left(-c+c-c+c\right)\) 

\(B=2a+0+0\) 

\(B=2a\)