TK

a) (35 - 15).(-4) + 24.(-13 - 17)

= 20.(-4) + 24.(-30)

= (-80) + (-720)

b) (-13).(57 - 34) +57. (13 - 45)

= (-13).23 + 57.(-32)

= (-299) + (-1824) 

= -2123

1: =20*(-4)+24(-30)

=-80-720=-800

2: =-13*57+13*32+57*13-57*45

=13*32-57*45=-2149

3: =-12*8*125

=-12*1000=-12000

4: =(-134)(1-51+48)

=(-134)*(-2)=268

5: =(-24)(45-5)=40*(-24)=-960

a)126.(-43)+26.43=43(-126+26)=43(-100)=-4300

b)(-135)(-45)-35.45=-45(-135+35)=-45(-100)=4500

c)113(-27)+27.13=27(-113+13)=27(-100)=-2700

d)125(-35)-(-25).35=-35(125-25)=-35.100=-3500

\(a)126.\left(-43\right)+26.43\)

\(=\left(-126\right).43+26.43\)

\(=43\left(-126+26\right)\)

\(=43.\left(-100\right)\)

\(=-4300\)

\(b)\left(-135\right).\left(-45\right)-35.45\)

\(=135.45-35.45\)

\(=45\left(135-35\right)\)

\(=45.100\)

\(=4500\)

\(c)113.\left(-27\right)+27.13\)

\(=\left(-113\right).27+27.13\)

\(=27\left(-113+13\right)\)

\(=27.\left(-100\right)\)

\(=-2700\)

\(d)125.\left(-35\right)-\left(-25\right).35\)

\(=\left(-125\right).35-\left(-25\right).35\)

\(=35\left(-125+25\right)\)

\(=35.\left(-100\right)\)

\(=-3500\)

45 + 24 =69

35 + 13 = 48

75 - 33 = 42

95 - 45 = 50

45+24=69

35+13=48

75_33=42

95_45=50

45+24=69

35+13=48

75-33=42

95-45=50

a) = 10 . (-4) + 24. 4

    = 10.(-4) + 96

    = 56

Ở dưới mình nhầm nha hihi

= -800

- Ôi dễ vãi ~~

Ta có:

\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.\left(9.5\right)^{25}.13^{22}.\left(5.7\right)^{16}}{9^{26}.\left(5.13\right)^{22}.\left(7.4\right)^{17}.\left(5.5\right)^9}\)

\(=\frac{2^{35}.9^{25}.5^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.13^{22}.5^{22}.7^{17}.4^{17}.5^9.5^9}\)

\(=\frac{2^{35}.5^3}{9.4^{17}.5^2.7}\)

\(=\frac{2^{35}.5}{9.4^{17}.7}\)

\(=\frac{2^{35}.5}{9.2^{34}.7}\)

\(=\frac{2.5}{9.7}\)

\(=\frac{10}{63}\)

p/s: - Ko chắc ~

\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.5^{25}.9^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.5^{22}.13^{22}.4^{17}.7^{17}.5^9.5^9}=\frac{2^{35}.5^3.5^7}{9.\left(2^2\right)^{17}.7.5^9}=\frac{2^{35}.5^3}{9.2^{34}.7.5^2}=\frac{2.5}{9.7}=\frac{10}{63}\)

\(A=\dfrac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\dfrac{2^{35}.3^{50}.5^{25}.13^{22}.5^{16}.7^{16}}{3^{52}.13^{22}.5^{22}.2^{34}.7^{17}.5^{18}}\)

\(=\dfrac{2.5^3}{3^2.5^2.7}=\dfrac{2.5}{3^2.7}=\dfrac{10}{63}\)

a, 18.(-24) +  35.42 - 18.76  + 35.(-142)

=  [ 18.(-24) - 18.76] + (35.42 + 35(-142)]

= -18.[ 24 + 76]  - 35.( 142 - 42)

= -18.100  - 35. 100

= - 100.(18 + 35)

= - 100. 53

= - 5300

h,   104 : (-13) - [56 - 220 : (-4)]

  = 104 : (-13)  - [ 56 + 55]

= -8 - 111

= - 119 

j; 1010 : {2500 : [550 - (4.53 - 23.25)]}

 = 1010 : {2500 : [550 - (212 - 575)]}

= 1010 : {2500 : [550 + 363]

= 1010 : { 2500 : 913}

= 1010 : \(\dfrac{2500}{913}\)

= 1010 x \(\dfrac{913}{2500}\)

= 368,852

5(2-x)=35

2-x= 35: 5

2-x= 7

x= 2-7

x=-5

29x-13=45

29x = 45+13

29x = 58

x= 58 : 29

x= 2

* 5(2 - x) = 35

2 - x = 35 : 5

2 - x = 7

x = 2 - 7

x = -5

* 29x - 13 = 45

29x = 45 + 13

29x = 58

x = 58 : 29

x = 2

5(2-x)=35

(2-x)=35:5

(2-x)=5

x =5-2

x = 3

29x-13=45

29x = 45+13

29x = 58

x =58:29

x =2