(19x +2.5^ ) :14 = (13 -8) ^ -4^
(19x+2.5^2):14=(13-8)^2-4^2
\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)
=>19x+50=126
=>x=4
(19x- 2.5^2)/14 = (13-8)^2-4^2
(19x+2.5^2):14=(13-8)^2-4^2
(19x+2.5^2):14=(13-8)^2-4^2
(19x+2.25):14=5^2-16
(19x+50):14=25-16
(19x+50):14=9
19x+50=126
19x=76
x=4
(19x+2.5^2):14=(13-8)^2-4^2
=>(19x+2.25):14=5^2-4^2
=>(19x+50):14=(5-4).(5+4)
=>19x+50=1.9.14=126
=>19x=126-50=76
=>x=76:19=4
k nha
tìm x biết : ( 19x + 2.5^2 ) : 14 = ( 13 - 8 ) ^ 2 - 4 ^2
( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2
( 19x + 2.52 ) : 14 = 52- 4 2
( 19x + 2.52 ) : 14 = 25- 16
( 19x + 2.52 ) : 14 =9
( 19x + 50 ) : 14 =9
19x + 50=9 . 14
19x + 50=126
19x=126-50
19x=76
x=76:19
x=4
gan gon hon nha
(19x+2*5^2)/14=(13-8)^2-4^
(19x+2*25)/14=(13-8)^2-16
(19x+2.25)/14=5^-16
(19x+2.25)/14=25-16
(19+2.25)=9*14
19X=126+50
x=76/19
x=4
(19x + 2.5 ^d) : 14 = (13-8) ^2 + 4^2
Meme :>
(19x+2.52):14=(13-82)-42
(19x+2.52) :14= (13-8)2 - 42
tìm x
(19x+2.52):14-=(13-8)2-4
Ta có : \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4\)
\(\Leftrightarrow\left(19x+2\cdot25\right):14=5^2-4\)
\(\Leftrightarrow\left(19x+50\right)=21\cdot14\)
\(\Leftrightarrow19x+50=294
\)
\(\Leftrightarrow19x=294-50\)
\(\Leftrightarrow x=\frac{244}{19}=12\frac{16}{19}\)
( 19x + 2 . 5\(^2\)) : 14 = ( 13 - 8 )\(^2\) - 4
( 19x + 2 . 25 ) : 14 = 5\(^2\)- 4
( 19x + 50 ) : 14 = 25 - 4
( 19x + 50 ) : 14 = 21
19x + 50 = 21 . 14
19x + 50 = 294
19x = 294 - 50
19x = \(\frac{244}{19}\)
giúp mình với mình tích đúng cho
(19x+2.5 mũ 2 ) : 14 = ( 13 - 8 ) mũ 2 - 4 mũ 2
( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2
( 19x + 2.52 ) : 14 = 52- 4 2
( 19x + 2.52 ) : 14 = 25- 16
( 19x + 2.52 ) : 14 =9
( 19x + 50 ) : 14 =9
19x + 50=9 . 14
19x + 50=126
19x=126-50
19x=76
x=76:19
x=4
(19x + 2.5²) : 14 = (13 - 8)² - 4²
(19x + 2.25) : 14 = 5² - 16
(19x + 50) : 14 = 25 - 16
(19x + 50) : 14 = 9
19x + 50 = 9 . 14
19x + 50 = 126
19x = 126 - 50
19x = 76
x = 76 : 19
x = 4