chịu

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}+2^{11}\cdot3^{11}}=\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot7}=\dfrac{4}{7}\)

\(=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}+2^{11}.3^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(-2.3+1\right)}=\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.\left(-5\right)}=\frac{2.6}{3.\left(-5\right)}=-\frac{4}{5}\)

\(1.a)\dfrac{2^3+3.26-4^3}{2^3.3^2}\)

\(=\dfrac{2^3.3.2.13-\left(2^2\right)^3}{2^3.3^2}\)

\(=\dfrac{2^4.3.13-2^6}{2^3.3^2}\)

\(=\dfrac{2^3\left(2.3.13-2^3\right)}{2^3.3^2}\)

\(=\dfrac{78-8}{9}\)

\(=\dfrac{70}{9}\)

\(b)\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)

\(=\dfrac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^4.3.5}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)

\(=\dfrac{2^{12}.3^{10}+2^{13}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=\dfrac{2^{12}.3^{10}\left(1+2.5\right)}{2^{11}.3^{11}\left(2.3\right)}\)

\(=\dfrac{2.11}{3.6}\)

\(=\dfrac{11}{9}\)

\(2.3^{x-1}-3^{x+1}=90\)

\(\Leftrightarrow3^x:3-3^x.3=90\)

\(\Leftrightarrow3^x\left(\dfrac{1}{3}-3\right)=90\)

\(\Leftrightarrow3^x.\dfrac{-8}{3}=90\)

\(\Leftrightarrow3^x=\dfrac{-135}{4}\)

\(\Leftrightarrow\) \(x\) không có giá trị nào để thỏa mãn đề bài.

Vậy \(x\in\varnothing\)

2:

\(3^{x-1}-3^{x+1}=90\)

\(\Rightarrow3^{x-2}-3^x=30\)

\(\Rightarrow3^x.3^{-2}-3^x=30\)

\(\Rightarrow3^x.\left(\dfrac{1}{9}-1\right)=30\)

\(\Rightarrow3^x.\dfrac{-8}{9}=30\)

\(\Rightarrow3^x=\dfrac{-135}{4}\)

\(\Rightarrow x=log_3\dfrac{-135}{4}\)

câu 2) là \(3^{x+1}-3^{x-1}=90\)

Đáp án ở đây

https://giaibaitapvenha.blogspot.com/

a: \(=\dfrac{\left(5^3\right)^3\cdot4^4}{5^{12}}=\dfrac{1}{5^3}\cdot4^4=\dfrac{4^4}{5^3}\)

b: \(=\dfrac{3^6}{\left[3^3\cdot2\right]^2}=\dfrac{1}{2^2}=\dfrac{1}{4}\)

c: \(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)

\(=\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot5}=\dfrac{4}{5}\)

\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot5}=\dfrac{2}{3}\cdot\dfrac{6}{5}=\dfrac{4}{5}\)