a) A=1-2-3+4+5-6-7+.....+1996+1997-1998-1999+2000

=(1-2-3+4)+(5-6-7+8)+...+(1997-1998-1999+2000)

=0

b) B=1-3+5-7+....+2001-2003+2005

=(1-3)+(5-7)+...+(2001-2003)+2005

=-2.501+2005

=-1002+2005

=1003

c) C=1-2-3+4+5-6-7+8+.....+1993-1994-1995+1996+1997

=(1-2-3+4)+(5-6-7+8)+...+(1993-1994-1995+1996)+1997

=1997

d) D=1000+998+996+......+10-999-997-995-...-11

=(1000-999)+(998-997)+(996-995)+....+(12-11)+10

=1.495+10

=595

\(a,\dfrac{2}{7}+\dfrac{5}{7}.\dfrac{7}{10}-\dfrac{1}{14}\)

\(=\dfrac{1}{7}.2+\dfrac{1}{7}.5.\dfrac{7}{10}-\dfrac{1}{7}.\dfrac{1}{2}\)

\(=\dfrac{1}{7}.\left(2+\dfrac{35}{10}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.\left(\dfrac{4}{2}+\dfrac{7}{2}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.5=\dfrac{5}{7}\)

\(b,\left(3\dfrac{1}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\left(\dfrac{7}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{7}{34}.\dfrac{5}{7}\)

\(=\dfrac{7}{34}.\left(\dfrac{17}{6}-\dfrac{5}{7}\right)\)

\(=\dfrac{7}{34}.\dfrac{89}{42}=\dfrac{89}{204}\)

a: =2/7-1/14+5/10

=2/7-1/14+1/2

=4/14-1/14+7/14

=10/14=5/7

b: =(7/2-2/3)*7/34-5/34

\(=\dfrac{21-4}{6}\cdot\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\dfrac{7}{6}\cdot\dfrac{1}{2}-\dfrac{5}{34}=\dfrac{7}{12}-\dfrac{5}{34}=\dfrac{89}{204}\)

a) 4/5(3/7+4/7)=4/5

câu b,c cũng dễ

a) 4/5 x 3/7 + 4/5 x 4/7

= 4/5 x ( 3/7 + 4/7 )

= 4/5 x 1

= 4/5

a) 4/5 x ( 3/7 + 4/7 )

= 4/5 x 1

= 4/5

b) 20 x 45 + 55 x 20 : 35 x 1996 - 1991 x 35

= 20 x ( 45 + 55 ) : 35 x ( 1996 - 1991 )

= 20 x 100 : 35 x 5

= 5 x 4 x 100 : 35 x 5

= 5 x 400 : 35 x 5

= \(\frac{5\cdot400}{35\cdot5}\Rightarrow=\frac{400}{35}.\)

[1-2-3+4]+........+[1997-1998-1999+2000]+2001

=0+0+....+0+2001

=2001

[1-2-3+4]+........+[1997-1998-1999+2000]+2001

=0+0+....+0+2001

=2001

b) \(\frac{1}{5}:\frac{1}{3}\cdot\frac{\frac{1}{3}}{\frac{1}{5}}+1996\)

\(=\frac{3}{5}\cdot\left(\frac{1}{3}:\frac{1}{5}\right)+1996\)

\(=\frac{3}{5}\cdot\frac{5}{3}+1996\)

\(=1+1996=1997\)

a) \(\frac{2}{3}:\frac{5}{7}\cdot\frac{5}{7}\cdot\frac{2}{3}+1934\)

\(=\frac{2\cdot7}{5\cdot3}\cdot\frac{5\cdot2}{7\cdot3}+1934\)

\(=\frac{2\cdot7\cdot5\cdot2}{5\cdot3\cdot7\cdot3}+1996=\frac{4}{9}+1996\)

MỜI BẠN HỎI GIA ĐÌNH GOOGLE MÀ TRỢ GIÚP CHỨ ĐỪNG HỎI TỤI TÔI

bạn ơi viết sai đề bài của mk rồi giải lại hộ câu a với 

đề??

a) \(\dfrac{4}{5}-\left(\dfrac{1}{5}+\dfrac{1}{3}\right)=\dfrac{4}{5}-\left(\dfrac{3}{15}+\dfrac{5}{15}\right)=\dfrac{4}{5}-\dfrac{8}{15}=\dfrac{12}{15}-\dfrac{8}{15}=\dfrac{4}{15}\)

b) \(\dfrac{12}{7}-\left(\dfrac{3}{14}-1\right)=\dfrac{12}{7}-\left(-\dfrac{11}{14}\right)=\dfrac{12}{7}+\dfrac{11}{14}=\dfrac{5}{2}\)

c) \(\dfrac{11}{2}-9\cdot\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{11}{2}-9\cdot\dfrac{9}{10}=\dfrac{11}{2}-\dfrac{81}{10}=\dfrac{55}{10}-\dfrac{81}{10}=-\dfrac{13}{5}\)

d) \(3\times9\left(\dfrac{4}{7}+\dfrac{3}{5}\right)=27\times\dfrac{41}{35}=\dfrac{1107}{35}\)

e) \(\left(\dfrac{1}{3}-\dfrac{1}{5}\right):2=\left(\dfrac{5}{15}-\dfrac{3}{15}\right):2=\dfrac{2}{15}:2=\dfrac{2}{15}\times\dfrac{1}{2}=\dfrac{1}{15}\)

f) \(\dfrac{123}{34}:\dfrac{1}{17}-\dfrac{21}{34}:\dfrac{1}{17}=\left(\dfrac{123}{34}-\dfrac{21}{34}\right):\dfrac{1}{17}=3:\dfrac{1}{17}=3\times17=51\)