x^7+x^2+1
Những câu hỏi liên quan
a) x^3 + 1 (x + 1)(x^2 - x + 1) x^9 + x^7 - 3x^2 - 3 x^7(x^2 + 1) - 3(x^2 + 1) (x^2 + 1)(x^7 - 3).Điều kiện của x để giá trị của biểu thức Q xác định là x neq -1, x^7 neq 3, x neq -3, x neq 4.b) Q left[frac{x^7 -3}{x^3 + 1}.frac{(x - 1)(x + 1)(x^2 - x + 1)}{(x^7 - 3)(x^2 + 1)} + 1 - frac{2(x + 6)}{x^2 + 1}right].frac{(2x + 1)^2}{(x + 3)(4 - x)} left[frac{x^7 - 3}{x^3 + 1}.frac{(x - 1)(x^3 + 1)}{(x^7 - 3)(x^2 + 1)} + 1 - frac{2(x + 6)}{x^2 + 1}right].frac{(2x + 1)^2}{(x + 3)(4 - x)}
Đọc tiếp
a) \(x^3 + 1 = (x + 1)(x^2 - x + 1)\)
\(x^9 + x^7 - 3x^2 - 3 = x^7(x^2 + 1) - 3(x^2 + 1) = (x^2 + 1)(x^7 - 3)\).
Điều kiện của x để giá trị của biểu thức Q xác định là \(x \neq -1, x^7 \neq 3, x \neq -3, x \neq 4\).
b) \(Q = \left[\frac{x^7 -3}{x^3 + 1}.\frac{(x - 1)(x + 1)(x^2 - x + 1)}{(x^7 - 3)(x^2 + 1)} + 1 - \frac{2(x + 6)}{x^2 + 1}\right].\frac{(2x + 1)^2}{(x + 3)(4 - x)}\)
\(= \left[\frac{x^7 - 3}{x^3 + 1}.\frac{(x - 1)(x^3 + 1)}{(x^7 - 3)(x^2 + 1)} + 1 - \frac{2(x + 6)}{x^2 + 1}\right].\frac{(2x + 1)^2}{(x + 3)(4 - x)}\)
1) x+1/2=-5/3
2) 1/3-x=3/5
4) x-4/3=-7/9
5) x--7/3=5/6
6) x-1/5=9/10
7) x+5/12=3/8
8) x+5/4=7/6
9) x-2/7=1/35
10) x-2/7=-7/10
6: =>x=9/10+1/5=9/10+2/10=11/10
7: =>x=3/8-5/12=36/96-40/96=-1/24
8: =>x=7/6-5/4=14/12-15/12=-1/12
9: =>x=1/35+2/7=1/35+10/35=11/35
10: =>x=2/7-7/10=20/70-49/70=-29/70
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1, \(x=-\dfrac{5}{3}-\dfrac{1}{2}=-\dfrac{10}{6}-\dfrac{3}{6}=-\dfrac{13}{6}\)
2, \(x=\dfrac{1}{3}-\dfrac{3}{5}=\dfrac{5-9}{15}=-\dfrac{4}{15}\)
4, \(x=-\dfrac{7}{9}+\dfrac{4}{3}=\dfrac{-7+12}{9}=\dfrac{5}{9}\)
5, \(x=\dfrac{5}{6}-\dfrac{7}{3}=\dfrac{5-14}{6}=-\dfrac{9}{6}=-\dfrac{3}{2}\)
6, \(x=\dfrac{9}{10}+\dfrac{1}{5}=\dfrac{9+2}{10}=\dfrac{11}{10}\)
7, \(x=\dfrac{3}{8}-\dfrac{5}{12}=\dfrac{9-10}{12}=-\dfrac{1}{12}\)
8, \(x=\dfrac{7}{6}-\dfrac{5}{4}=\dfrac{14-15}{12}=-\dfrac{1}{12}\)
9, \(x=\dfrac{1}{35}+\dfrac{2}{7}=\dfrac{1+10}{35}=\dfrac{11}{35}\)
10, \(x=-\dfrac{7}{10}+\dfrac{2}{7}=\dfrac{-49+20}{70}=\dfrac{-29}{70}\)
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tìm x
a) X x 3/4 = 1/5 b) 3/7 x X = 2/5 c) 1/3 + 2/9 = 2/12 x X
d) 4/15 x X - 2/3 = 1/5 e) x : 1/7 = 2/3 f) 1/9 : x = 7/3 j) 1/4 + 5/12 = 8/3 : x
h) 7/4 : X - 1/2 = 1/5
a: x*3/4=1/5
=>x=1/5:3/4=1/5*4/3=4/15
b: x*3/7=2/5
=>x=2/5:3/7=2/5*7/3=14/15
c: 1/3+2/9=2/12x
=>1/6x=3/9+2/9=5/9
=>x=5/9*6=30/9=10/3
d: 4/15*x-2/3=1/5
=>4/15*x=2/3+1/5=10/15+3/15=13/15
=>4x=13
=>x=13/4
e: x:1/7=2/3
=>x=2/3*1/7=2/21
f: 1/9:x=7/3
=>x=1/9:7/3=1/9*3/7=3/63=1/21
j: 1/4+5/12=8/3:x
=>8/3:x=3/12+5/12=8/12=2/3
=>x=4
h: =>7/4:x=1/5+1/2=7/10
=>x=7/4:7/10=10/4=5/2
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1) x+1/2=-5/3
2) 1/3-x=3/5
4) x-4/3=-7/9
5) x--7/3=5/6
6) x-1/5=9/10
7) x+5/12=3/8
8) 5/4=7/6
9) x-2/7=1/35
10) x-2/7=-7/10
cả phép tính nữa nha
1: =>x=-5/3-1/2=-13/6
2: =>x=1/3-3/5=-4/15
4: =>x=-7/9+4/3=-7/9+12/9=5/9
5: =>x=5/6-7/3=5/6-14/6=-9/6=-3/2
6: =>x=9/10+1/5=11/10
7: =>x=3/8-5/12=36/96-40/96=-1/24
8: Đề sai rồi bạn
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Viết các biểu thức sau dưới dạng một lũy thừa:
6, 3/2 x 9/4 x 81/16
7, (1/2)^7 x 8 x 32 x 2^8
8, (-1/7)^4 x 125 x 5
9, 4 x 32 : (2^3 x 1/16)
10, (1/7)^2 x 1/7 x 49
6:=(3/2)*(3/2)^2*(3/2)^4=(3/2)^7
7: =(1/2)^7*2^3*2^5*2^8=2^9
8: =(-1/7)^4*5^4=(-5/7)^4
9: =2^2*2^5:(2^3/2^4)
=2^7/2=2^6
10: =(1/7)^3*7^2=1/7
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7.3x *(x+1)^2 -5x^3(x+1)+7(x+1)
8.(2x+1)^2-(x-1)^2
9.(x+5)^2-(x-7)^2
10.9 (x+5)^2-(x-7)^2
tìm x
2/9 + 7/9 : x = 1/18
x x 7/5 - 2/5 = 2/15
4/7 x ( x - 1/2 ) = 3/14
2/5 x x + 3/10 x x - x : 5 = 7/10
a: =>7/9:x=1/18-2/9=1/18-4/18=-3/18=-1/6
=>x=-7/9:1/6=-7/9*6=-42/9=-14/3
b: =>x*7/5=2/15+2/5=8/15
=>x=8/15:7/5=8/21
c: =>x-1/2=3/14:4/7=3/8
=>x=3/8+4/8=7/8
d: =>0,4x+0,3x-0,2x=0,7
=>0,5x=0,7
=>x=1,4
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MG42E3RSDáidsdPDIOHSA8DR0RYE9FHEUCnd09f7eqg03
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Xem thêm câu trả lời
1 Tìm x:
a) 5.(1-x)-6.(1+x)=7.(3-x)
b) 2.(x+5)-3.(3x+7)=6.(1-x)+8x
c) x-2+3.(x-4)=5.(x-6)+7
d) x+2+3.(1-x)-5.(2-x)=6.(1-x)+7.(3x)
giờ làm vẫn đc đúng ko bạn
1/ x + 1/2 = -5/3 6/ x - 1/5 = 9/10
2/ 1/3 - x = 3/5 7/ x + 5/12 = 3/8
3/ 3-4 + x = 7/2 8/ x + 5/4 = 7/6
4/ x - 4/3 = -7/9 9/ x - 2/7 = 1/35
5/ x - -7/3 = 5/6 10/ x - 1/5 = -7/10
\(1,\\ x+\dfrac{1}{2}=-\dfrac{5}{3}\\ x=-\dfrac{5}{3}-\dfrac{1}{2}\\ x=-\dfrac{13}{6}\\ Vậyx=-\dfrac{13}{6}\)
\(2,\\ \dfrac{1}{3}-x=\dfrac{3}{5}\\ x=\dfrac{1}{3}-\dfrac{3}{5}\\ x=-\dfrac{4}{15}\\ Vậyx=-\dfrac{4}{15}\)
\(3,\\ 3-4+x=\dfrac{7}{2}\\ -1+x=\dfrac{7}{2}\\ x=\dfrac{7}{2}+1\\ x=\dfrac{9}{2}\\ Vậyx=\dfrac{9}{2}\)
\(4,\\ x-\dfrac{4}{3}=-\dfrac{7}{9}\\ x=-\dfrac{7}{9}+\dfrac{4}{3}\\ x=\dfrac{15}{27}\\ Vậyx=\dfrac{15}{27}\)
\(5,\\ x-\left(-\dfrac{7}{3}\right)=\dfrac{5}{6}\\ x=\dfrac{5}{6}-\dfrac{7}{3}\\ x=-\dfrac{27}{18}\\ Vậyx=-\dfrac{27}{18}\)
\(6,\\ x-\dfrac{1}{5}=\dfrac{9}{10}\\ x=\dfrac{9}{10}+\dfrac{1}{5}\\ x=\dfrac{11}{10}\\ Vậyx=\dfrac{11}{10}\)
\(7,\\ x+\dfrac{5}{12}=\dfrac{3}{8}\\ x=\dfrac{3}{8}-\dfrac{5}{12}\\ x=-\dfrac{1}{24}\\ Vậyx=-\dfrac{1}{24}\)
\(8,\\ x+\dfrac{5}{4}=\dfrac{7}{6}\\ x=\dfrac{7}{6}-\dfrac{5}{4}\\ x=-\dfrac{9}{24}\\ Vậyx=-\dfrac{9}{24}\)
\(9,\\ x-\dfrac{2}{7}=\dfrac{1}{35}\\ x=\dfrac{1}{35}+\dfrac{2}{7}\\ x=\dfrac{11}{35}\\ Vậyx=\dfrac{11}{35}\\ 10,\\ x-\dfrac{1}{5}=-\dfrac{7}{10}\\ x=-\dfrac{7}{10}+\dfrac{1}{5}\\ x=-\dfrac{1}{2}\\ Vậyx=-\dfrac{1}{2}\)
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tìm x biết:
a) (x-3)2-4=0
b) x2-2x=24
c) (x+4)2-(x+1)(x-1)=16
d) (2x+1)2-4(x-1)2=9
e) (x+3)2-(x-4)(x+8)=1
f) (2x-1)2+(x+3)2-5(x+7)(x-7)=0
g) 3(x+2)2+(2x-1)2-7(x+3)(x-3)=36
- Gửi lẻ câu hỏi ra nha bạn 2 3 câu 1 lần thôi .
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a) (x-3)2-4=0
⇒ (x-3)2=4
⇒ hoặc x-3=2⇒x=5
hoặc x-3=-2⇒x=1
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c) (x+4)2-(x+1)(x-1)=16
⇒ x2+8x+16-x2+1=16
⇒ 8x+17=16
⇒ 8x=-1
⇒ x=-1/8
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