a) ax - 2x - a² + 2a

= ( ax - 2x ) - ( a² - 2a )

= x ( a - 2 ) - a ( a - 2 )

= ( a - 2 ) ( x - a )

b) x² + x - ax - a

= ( x² + x ) - ( ax + a )

= x ( x + 1 ) - a ( x + 1 )

= ( x + 1 ) ( x - a )

Hok Tốt!!!

a) ax -2x- a²+ 2a

= (ax -2x ) -(a² -2a )

= x(a-2) -a ( a-2 )

= (x-a) (a-2)

b) x² +x -ax -a

=( x² +x ) - ( ax +a )

= x( x+1 ) -a ( x+1 )

= ( x-a ) (x+ 1)

c) 2x² +4ax +x +2a

=( 2x² + 4ax )  + ( x+ 2a )

= 2x ( x+ 2a ) + ( x+2a )

= ( 2x +1 ) (x+2a )

d) 2xy -ax +x² - 2ay

= (2xy -2ay ) + (  -ax + x² )

= 2y( x-a ) + x ( x-a)

= ( 2y +x ) ( x -a )

a)  \(ax-2x-a^2+2a=\left(ax-2x\right)-\left(a^2-2a\right)\)

\(=x\left(a-2\right)-a\left(a-2\right)=\left(x-a\right)\left(a-2\right)\)

b)    \(x^2+x-ax-a=\left(x^2+x\right)-\left(ax+a\right)\)

\(=x\left(x+1\right)-a\left(x+1\right)=\left(x-a\right)\left(x+1\right)\)

c) \(2x^2+4ax+x+2a=\left(2x^2+x\right)+\left(4ax+2a\right)\)

\(=x\left(2x+1\right)+2a\left(2x+1\right)=\left(x+2a\right)\left(2x+1\right)\)

d)  \(2xy-ax+x^2-2ay=\left(2xy-2ay\right)+\left(x^2-ax\right)\)

\(=2y\left(x-a\right)+x\left(x-a\right)=\left(2y-x\right)\left(x-a\right)\)

Hok tốt

a: 2x+4=2(x+2)

b: \(x^2+2xy+y^2-9=\left(x+y-3\right)\left(x+y+3\right)\)

2x^5-6x^4-2a^2x^3-6ax^3

 =(2x^5-2a^2x^3)-(6x^4+6ax^3)

 =2x^3(x^2-a^2)-6x^3(x+a)

 =2x^3(x-a)(x+a)-6x^3(x+a)

 =(x+a)(2x^4-2x^3a-6x^3)

 =(x+a) 2x^3 (x-a-3)

ax - 2x - a² + 2a

= x(a - 2) - a(a - 2) 

= (x - a)(a - 2)

\(ax-2x-a^2+2a\)

\(=\left(ax-2x\right)-\left(a^2-2a\right)\)

\(=x\left(a-2\right)-a\left(a-2\right)\)

\(=\left(a-2\right)\left(x-a\right)\)

Trả lời:

ax - 2x - a² + 2a

= ( ax - 2x ) - ( a² - 2a )

= x ( a - 2 ) - a ( a - 2 )

= ( x - a ) ( a - 2 )

\(x^2-4y^2-2x+1=\left(x-1\right)^2-4y^2=\left(x-1-2y\right)\left(x-1+2y\right)\)

giúp mình câu cuối với

x²+2x+1+2ax+2a

<=> (x²+2x+1)+(2ax+2a)

<=> (x+1)² + 2a(x+1)

<=> (x+1) (x+1+2a)

#)Giải :

\(x^3-2x-4\)

\(=x^3+2x^2-2x^2+2x-4x-4\)

\(=x^3+2x^2+2x-2x^2-4x-4\)

\(=x\left(x^2+2x+2\right)-2\left(x^2+2x+2\right)\)

\(=\left(x-2\right)\left(x^2+2x+2\right)\)

\(x^4+2x^3+5x^2+4x-12\)

\(=x^4+x^3+6x^2+x^3+x^2+6x-2x^2-2x-12\)

\(=x^2\left(x^2+x+6\right)+x\left(x^2+x+6\right)-2\left(x^2+x+6\right)\)

\(=\left(x^2+x+6\right)\left(x^2+x-2\right)\)

\(=\left(x^2+x+6\right)\left(x-1\right)\left(x+2\right)\)

Câu 1.

Đoán được nghiệm là 2.Ta giải như sau:

\(x^3-2x-4\)

\(=x^3-2x^2+2x^2-4x+2x-4\)

\(=x^2\left(x-2\right)+2x\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x-2\right)\left(x^2+2x+2\right)\)

cảm ơn nha!

\(1,=x\left(x^2-2x+1-y^2\right)=x\left[\left(x-1\right)^2-y^2\right]=x\left(x-y-1\right)\left(x+y-1\right)\\ 2,=\left(x+y\right)^3\\ 3,=\left(2y-z\right)\left(4x+7y\right)\\ 4,=\left(x+2\right)^2\\ 5,Sửa:x\left(x-2\right)-x+2=0\\ \Leftrightarrow\left(x-2\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

`a^2 + ab + 2a + 2b = a(a+2) + b(a+2) = (a+b)(a+2)`