1.PTDTTNT
a, 2xy+3z +6y + xz
b, 9x - x^3
c, xz + yz -5 * ( x+y)
d, x^2 + 4x - y^2 +4
e, x^2 - 2xy + y^2 - z^2 + 27t - t^2
f, x^64 + x^32 +1
g a^10 + a^5 +1
PP nhóm
1)2xy+3z+6y+xz
2)x^4-9x^3+x^2-9x
3)x^2-xy+x-y
4)xz+yz-5(x+y)
5)3x^2-3xy-5x+5y
6)x^2+4x-y^2+4
7)3x^2+6xy+3y^2-3z^2
8)x^2-2xy+y^2-z^2+2zt-t^2
1)2xy+3z+6y+xz
= x(2y + z) + 3(z + 2y)
= (x + 3)(2y + z)
2)x^4-9x^3+x^2-9x
= x^2(x^2 + 1) - 9x(x^2 + 1)
= (x^2 + 1)(x^2 - 9x)
= x(x - 9)(x^2 + 1)
3)x^2-xy+x-y
= x(x - y) + (x - y)
= (x + 1)(x - y)
4)xz+yz-5(x+y)
= z(x + y) - 5(x + y)
= (z - 5)(x + y)
5)3x^2-3xy-5x+5y
= 3x(x - y) - 5(x - y)
= (3x - 5)(x - y)
6)x^2+4x-y^2+4y
= (x - y)(x + y) + 4(x + y)
= (x - y + 4)(x + y)
1) Phân tích đa thức thành nhân tử
a) (2x+1)^2 - 2(2x+1) (x-3) + (x-3)^2
b) xy +xz + 3y +3z
c) xy - xz + y -z
d) x^2 - xy - 8x + 8y
e) x^2 + 2xy + y^2 - xz - yz
f) 25 - 4x^2 - 4xy - y^2
a, \(\left(2x+1\right)^2-2\left(2x+1\right)\left(x-3\right)+\left(x-3\right)^2\)
\(=\left(2x+1-x+3\right)^2=\left(x+4\right)^2\)
b, \(xy+xz+3y+3z=x\left(y+z\right)+3\left(y+z\right)=\left(x+3\right)\left(y+z\right)\)
c, \(xy-xz+y-z=x\left(y-z\right)+\left(y-z\right)=\left(x+1\right)\left(y-z\right)\)
d, \(x^2-xy-8x+8y=\left(x^2-xy\right)-\left(8x-8y\right)\)
\(=x\left(x-y\right)-8\left(x-y\right)=\left(x-8\right)\left(x-y\right)\)
e, \(x^2+2xy+y^2-xz-yz=\left(x^2+2xy+y^2\right)-\left(xz+yz\right)\)
\(=\left(x+y\right)^2-z\left(x+y\right)=\left(x+y+z\right)\left(x+y\right)\)
f, \(25-4x^2-4xy-y^2=25-\left(4x^2+4xy+y^2\right)\)
\(=5^2-\left(2x+y\right)^2=\left(5-2x-y\right)\left(5+2x+y\right)\)
1,
a, (2x + 1- x + 3)2 = (x+4)2
b,\(x\left(y+z\right)+3\left(y+z\right)=\left(y+z\right)\left(x+3\right)\)
c, \(x\left(y-z\right)+\left(y-z\right)=\left(y-z\right)\left(x+1\right)\)
d,\(x\left(x-y\right)+8\left(y-x\right)\)=\(\left(x-y\right)\left(x-8\right)\)
e,\(\left(x+y\right)^2-z\left(x+y\right)\)=\(\left(x+y\right)\left(x+y-z\right)\)
f,\(25-\left(4x^2+4xy+y^2\right)=5^2-\left(2x+y\right)^2\)
\(=\left(5+2x+y\right)\left(5-2x-y\right)\)
Chúc các bn hc tốt
a) 2xy + 3z +6y + xz
b) 4x^2 - 4xy - 9t^2 + y^2
c) x^4 - 9x^3 + x^2 - 9x
d) x^3 - 3x^2y + 3xy^2 - y^3 - z^3
a) \(2xy+3z+6y+xz\)
\(=2xy+2.3y\)
\(=2y\left(x+3\right)+3z+xz\)
\(=2y\left(x+3\right)+z\left(x+3\right)\)
\(=\left(x+3\right)\left(2y+z\right)\)
c) \(x^4-9x^3+x^2-9x\)
\(=x\left(x^3-9x^2+x-9\right)\)
\(=x\left(x-9\right)\left(x^2+1\right)\)
1/ PTDTTNT:
a) x² +6x–y² +9
b) 2x² –4x +2
c)2xy +3z +6y +xz
d)x² +4x –2xy –4y +y²
e)x² +2x +1 –16y²
d/ \(x^2+4x-2xy-4y+y^2=\left(x-y\right)^2+4\left(x-y\right)=\left(x-y\right)\left(x-y+4\right)\)
e/ \(x^2+2x+1-16y^2=\left(x+1\right)^2-\left(4y\right)^2=\left(x+1-4y\right)\left(x+1+4y\right)\)
Phân tích đa thức thành nhân tử
1: ax+ay-4x-4y
2: x^2+ab+ax+bx
3: ax+a-bx-b+cx+c
4: ab(x^2+y^2)+xy(a^2+b^2)
5: ab(x^2+1)+x(a^2+b^2)
6: x^2-2xy+y^2-4
7: x^2-y^2+4x+4
8: x^2-2xy+y^2-1
9: 9-x^2-2xy-x^2
10: 25-x^2+4xy-4y^2
11: x^2+xy+xz-x-y-z
12: x^2-2xy+3xz+x-2y+3z
13: 4x^2-9y^2-4x-6y
14: x^3-y^3+2x^2-2y^2
15: x^2+y^2+2xy+yz+zx
16: x^3+y^3+x^2y+xy^2+xz^2+yz^2
Mọi người vào giải hộ em với, em đang cần gấp ạ :))
1: \(=a\left(x+y\right)-4\left(x+y\right)=\left(x+y\right)\left(a-4\right)\)
2: \(=x\left(x+b\right)+a\left(x+b\right)=\left(x+b\right)\left(x+q\right)\)
3: \(=a\left(x+1\right)-b\left(x+1\right)+c\left(x+1\right)\)
\(=\left(x+1\right)\left(a-b+c\right)\)
6: \(=\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)
A.5x^2y^3-25x^3y^4+10x^3y^3
B.12x^2y-18xy^2-30y^2
C.5(x-y)-y(x-y)
D.y(x-z)+7(z-x)
E.27x^2(y-1)-9x^3(1-y)
F.36-12x+x^2
G.x^2+2xy+y^2-xz-yz
H.x^4+64
I.27x^2(y-1)-9x^3(1-y)
K.36-12x+x^2
M.-4x^2+4x-1
N.x^2+5x+6
P.x^2-x-6
Q.x^4-5x^2+4
Chọn đáp án đúng
\({ (x^{3}+3x^{2}y+3xy^{2}+y^{3}-z^{3}):(x+y-z) }\)
\(A. { x^{2}+y^{2}+z^{2}+2xy+xz+yz }\)
\(B. { x^{2}+y^{2}+z^{2}+2xy-xz-yz } \)
\(D. { x^{2}+y^{2}-z^{2}+2xy-xz-yz } \)
\(\left(x^3+3x^2y+3xy^2+y^3-z^3\right):\left(x+y-z\right)\\ =\left[\left(x+y\right)^3-z^3\right]:\left(x+y-z\right)\\ =\left(x+y-z\right)\left[\left(x+y\right)^2+z\left(x+y\right)+z^2\right]:\left(x+y-z\right)\\ =x^2+2xy+y^2+xz+yz+z^2\)
Vậy chọn A
a) 3x 2 (2x 3 – x + 5)
b) (4xy + 3y – 5x)x 2 y
c) (3x 2 y – 6xy + 9x)(- 3
4
xy)
d) - 3
1
xz(- 9xy + 15yz) + 3x 2 (2yz 2 – yz)
e) (x 3 + 5x 2 – 2x + 1)(x – 7)
f) (2x 2 – 3xy + y 2 )(x + y)
g) (x – 2)(x 2 – 5x + 1) – x(x 2 + 11)
h) [(x 2 – 2xy + 2y 2 )(x + 2y) - (x 2 + 4y 2 )(x – y)] 2xy
Mọi người giúp em với ạ
Đề bài là gì sao không ghi rõ??
bài 1 phân tích
a,xy+xz+3x+3z
b,xy-xz+y-x
c,11x+11y-x^2-xy
d,x^2-xy-8x+8y
Bài 2phaan tích
a,x^2-6x-y^2+9
b,25-4x^2-4xy-y^2
c,x^2+2xy+y62-xz-yz
d,x^2-4xy+4y^2-z^2+4zt-4t^2
Bài 3 tìm x
a,x(x-5)-4x+20=0
b,x(x+6)-7x-42=0
c,x^3-5x^2+x-5=0
B3) a) x(x-5)-4(x-5)=0
<=> (x-4)(x-5)=0
TH1 :x-4=0
<=.x=4
TH2 : x-5=0
<=>x=5
b) x(x-6)-7x-42=0
<=>x(x+6)-7(x+6)=0
<=>(x-7)(x+6)=0
th1;x-7=0
<=>x=7
th2; x+6=0
<=>x=-6
c)x^3-5x^2+x-5=0
<=> x(x^2+1)-5(x^2+1)=0
<=> (x-5)(x^2+1)=0
th1:x-5=0
<=>x=5
TH2 : x^2+1=0
<=> x^2=-1 ( vo li )
=> th2 ko tồn tại
nho thick nha
Bài 3
a, x(x-5)-4(x-5)=0
(x-4)(x-5)=0
=>\(\orbr{\begin{cases}x-4=0\\x-5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4\\x=5\end{cases}}\)
b,x(x+6)-7(x+6)=0
(x-7)(x+6)=0\(\Rightarrow\orbr{\begin{cases}x-7=0\\x+6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=7\\x=-6\end{cases}}\)
c,x^2(x-5)+(x-5)=0
(x^2+1)(x-5)=0
\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\x-5=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x\in\Phi\\x=5\end{cases}}\)