1) $(-35)\cdot18+28\cdot35$

$=35\cdot(-18)+28\cdot35$

$=35\cdot(-18+28)$

$=35\cdot10$

$=350$

2) $53\cdot29-47\cdot(-29)$

$=53\cdot29-47\cdot(-1)\cdot29$

$=53\cdot29+47\cdot29$

$=29\cdot(53+47)$

$=29\cdot100$

$=2900$

3) $125\cdot(-24)+24\cdot225$

$=(-125)\cdot24+24\cdot225$

$=24\cdot(-125+225)$

$=24\cdot100$

$=2400$

4) $26\cdot(-121)-121\cdot(-36)$

$=-121\cdot[26+(-36)]$

$=-121\cdot(26-36)$

$=-121\cdot(-10)$

$=121\cdot10$

$=1210$

5) $65\cdot(-25)+25\cdot(-23)$

$=-65\cdot25+25\cdot(-23)$

$=25\cdot(-65-23)$

$=25\cdot(-88)$

$=-2200$

6) $237\cdot(-26)+26\cdot137$

$=-237\cdot26+26\cdot137$

$=26\cdot(-237+137)$

$=26\cdot(-100)$

$=-2600$

7) $30\cdot(-125)+25\cdot30$

$=30\cdot(-125+25)$

$=30\cdot(-100)$

$=-3000$

8) $(-37)\cdot69+(-31)\cdot37$

$=37\cdot(-69)+37\cdot(-31)$

$=37\cdot(-69-31)$

$=37\cdot(-100)$

$=-3700$

9) $31\cdot72-31\cdot70-31\cdot2$

$=31\cdot(72-70-2)$

$=31\cdot(2-2)$

$=31\cdot0$

$=0$

10) $(-12)\cdot47+(-12)\cdot52+(-12)$

$=-12\cdot(47+52+1)$

$=-12\cdot100$

$=-1200$

$\text{#}Toru$

lớp 1 mà cậu

4.24.5²-(3³.18+3³.12)

=4.24.25-[27.(18+12)]

=(4.25).24-[27.30]

=100.24-810

=2400-810

=1590

4.24.5^2-(3^3.18+3^3.12)

31.15.7^2.4-31.49.40

1+2+3+4+5+6+7+8+9+10

1+3+5+7+9+11+13+15+19

2+6+10+14+22+23+26+34

5+8+11+14+17+20+23+26+29

1+6+11+16+21+26+31+36+41+47+51

10+13+16+19+22+25+28+31+34+37+40

5+7+9+11+13+15+17+3+8+13+18+23+28

4+7+10+13+16+19+5+9+13+17+21+25 = 1590

#HT#

E=760

F=796

=>796>760=>F>E

Ta có : \(E=25\cdot30+10\)

           \(E=750+10\Rightarrow E=760\)

\(F=31\cdot26-10\)

\(F=806-10\Rightarrow F=796\)

Do 760 < 796 nên E < F hoặc \(E=25\cdot30+10< F=31\cdot26-10\)

E=25*30+10

E=22500+10

E=22510

và

F=31*26-10

F=806-10

F=796

vậy 22510>796 hoặc E>F

cho hỏi đề bài

so sánh

k)(-37)+14+26+37

=(-37)+37+14+26

=0+14+26

=40

l)15+23+(-25)+(-23)

=15+(-25)+23+(-23)

=-10+0

=-10

n)25+37-48-25-37

=25-25+37-37-48

=0+0-48

=-48

o)24.(16-5)-16.(24-5)

=24.16-24.5-16.24-16.5

=0-24.5-16.5

=0-(24-16).5

=0-8.5

=0-40

=-40

p)31.(-18)+31.(-81)-31

=31.(-18)+31.(-81)+31.(-1)

=31.[-18+(-81)+(-1)]

=31.(-100)

=-3100

q)-48+48.(-78)+48.(-21)

=48.(-1)+48.(-78)+48.(-21)

=48.[(-1)+(-78)+(-21)]

=48.(-100)

=-4800

r)(7.3-3):(-6)

=(7.3-1.3):(-6)

=(6.3):(-6)

=-3

s)-3.7-4.(-5)+1

=-21-(-20)+1

=-20-(-20)

=0

t(6.8-10:5)+3.(-7)

=(48-2)+(-21)

=46+(-21)

=25

Viết mỏi cả tay rồi.tick đi nhé

a=815 

b=816 

vậy thì a<b

k cho tớ nha tớ nha nhanh nhất đó 

kết bạn cho tớ nha

Ta có :

A = 25 x 33 - 10 = 25 x ( 31 + 2 ) - 10 = 25 x 31 + 50 - 10 = 25 x 31 + 40 ( 1 )

B = 31 x 26 + 10 = 31 x ( 25 + 1 ) + 10 = 31 x 25 + 31 + 10 = 31 x 25 + 41= 25 x 31 + 41 ( 2 )

Từ ( 1 ) ; ( 2 ) suy ra A < B

Cách 2 : :v

A = 25 x 33 - 10

A = 825 - 10 = 815 ( 1 )

B = 31 x 26 + 10

B = 806 + 10 = 816 ( 2)

Từ ( 1 ) ; ( 2 ) suy ra A < B

mk cũng hỏi câu này nek

`A=2^{0}+2^{1}+2^{2}+....+2^{99}`

`=(1+2+2^{2}+2^{3}+2^{4})+(2^{5}+2^{6}+2^{7}+2^{8}+2^{9})+......+(2^{95}+2^{96}+2^{97}+2^{97}+2^{99})`

`=(1+2+2^{2}+2^{3}+2^{4})+2^{5}(1+2+2^{2}+2^{3}+2^{4})+.....+2^{95}(1+2+2^{2}+2^{3}+2^{4})`

`=31+2^{5}.31+....+2^{95}.31`

`=31(1+2^{5}+....+2^{95})\vdots 31`

\(A=2^0+2^1+2^2+2^3+2^4+2^5+2^6+...+2^{99}\)

\(=\left(2^0+2^1+2^2+2^3+2^4\right)+2^5\left(2^0+2^1+2^2+2^3+2^4\right)+...+2^{95}\left(2^0+2^1+2^2+2^3+2^4\right)=31+31.2^5+...+31.2^{95}=31\left(1+2^5+...+2^{95}\right)⋮31\)

wow! mù mắt. Ido tính toán có khác!

C2:(32+1)x32:2=528

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