\(\dfrac{3}{8}+\dfrac{9}{2}\times\dfrac{12}{16}-\dfrac{9}{4}:3\)

= \(\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{9}{2}\times\dfrac{3}{4}-\dfrac{3}{4}\times3:3\)

= \(\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{9}{2}\times\dfrac{3}{4}-\dfrac{3}{4}\times1\)

= \(\dfrac{3}{4}\times\left(\dfrac{1}{2}+\dfrac{9}{2}-1\right)\)

= \(\dfrac{3}{4}\times\left(5-1\right)\)

= \(\dfrac{3}{4}\times4\)

= 3

`1,2×15/4+16/7×-85/8-1,2 × 5 3/4 - 16/7 × -71/8`

`=6/5xx15/4+16/7xx(-85)/8-6/5xx23/4-16/7xx(-71)/8`

`=6/5xx(15/4-23/4)+16/7xx[(-85/8)-(-71/8)]`

`=6/5xx(-8/4)+16/7xx(-14/8)`

`=-32/5`

( 625² + 3 ).( 5⁸ - 3 )  - 5¹⁶ + 10

= [ ( 5⁴ )² + 3 ).(  5⁸ - 3 )  - 5¹⁶ + 10

= ( 5⁸ + 3 ).( 5⁸ - 3 ) - 5¹⁶ + 10

=  5¹⁶ -9 - 5¹⁶ + 10

= 1

\(\frac{5}{8}+\frac{2}{9}-\frac{2}{5}+\frac{3}{8}+\frac{4}{9}+\frac{1}{3}-\frac{3}{5}\)

\(=\frac{5}{8}+\frac{2}{9}-\frac{2}{5}+\frac{3}{8}+\frac{4}{9}+\frac{3}{9}-\frac{3}{5}\)

\(=\left(\frac{5}{8}+\frac{3}{8}\right)+\left(\frac{2}{9}+\frac{4}{9}+\frac{3}{9}\right)-\left(\frac{2}{5}+\frac{3}{5}\right)\)

\(=\frac{8}{8}+\frac{9}{9}-\frac{5}{5}\)

\(=1+1-1\)

\(=2-1\)

\(=1\)

\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\\ =\dfrac{38}{11}+\dfrac{16}{13}+\dfrac{6}{11}\\ =\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\\ =\dfrac{44}{11}+\dfrac{16}{13}\\ =4+\dfrac{16}{13}\\ =\dfrac{52}{13}+\dfrac{16}{13}\\ =\dfrac{68}{13}\\ \dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\\ =\dfrac{3}{4}\times\dfrac{5}{3}-\dfrac{1}{5}\\ =\dfrac{5}{4}-\dfrac{1}{5}\\ =\dfrac{25-4}{20}\\ =\dfrac{21}{20}\)

Phép tính 1:

\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\)

\(=\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\)

\(=4+\dfrac{16}{13}=\dfrac{4\cdot13+16}{13}\)(Dấu "." trong phép tính là dấu nhân)

\(=\dfrac{68}{13}\)

Phép tính 2:

\(\dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\)

\(=\dfrac{3}{4}\cdot\dfrac{5}{3}-\dfrac{1}{5}\)

\(=\dfrac{\left(3\cdot5\right):3\cdot5}{\left(4\cdot3\right):3\cdot5}-\dfrac{1\cdot4}{5\cdot4}\)

\(=\dfrac{25}{20}-\dfrac{4}{20}\)

\(=\dfrac{21}{20}\)

Gọi biểu thức trên là A, ta có:

A = \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)

A x 2 - A = \(\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}\)

A x 2 - A = A x 1 = A = \(1-\frac{1}{16}=\frac{15}{16}\)

B = 1.3/2.2 . 2.4/3.3 . 3.5/4.4 . ...... . 9.11/10.10

   = 1.2.3 . ..... . 9/2.3.4 . ..... . 10   .   3.4.5 . ...... . 11/2.3.4 . ..... . 10

   = 1/10 . 11/2

   = 11/20

Tk mk nha

\(B=\frac{3}{4}.\frac{8}{9}...\frac{99}{100}\)

\(B=\frac{1\cdot3}{2^2}.\frac{2\cdot4}{3^3}...\frac{9\cdot11}{10^2}\)

\(B=\frac{1.3.2.4...9.11}{2^2.3^3...10^2}\)

\(B=\frac{11}{2.10}\)

\(B=\frac{11}{20}\)

\(\begin{array}{l}1,2.\frac{{15}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} - 1,2.5\frac{3}{4} - \frac{{16}}{7}.\frac{{ - 71}}{8}\\ =(1,2.\frac{{15}}{4} - 1,2.5\frac{3}{4}) +( \frac{{16}}{7}.\frac{{ - 85}}{8}- \frac{{16}}{7}.\frac{{ - 71}}{8}) \\= \frac{{12}}{{10}}.\frac{{15}}{4} - \frac{{12}}{{10}}.\frac{{23}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} - \frac{{16}}{7}.\frac{{ - 71}}{8}\\ = \frac{6}{5}.\frac{{15}}{4} - \frac{6}{5}.\frac{{23}}{4} + \frac{{16}}{7}.\frac{{ - 85}}{8} + \frac{{16}}{7}.\frac{{71}}{8}\\ = \frac{6}{5}.(\frac{{15}}{4} - \frac{{23}}{4}) + \frac{{16}}{7}.(\frac{{ - 85}}{8} + \frac{{71}}{8})\\ = \frac{6}{5}.\frac{{ - 8}}{4} + \frac{{16}}{7}.\frac{{ - 14}}{8}\\ = \frac{6}{5}.( - 2) + ( - 4)\\ = \frac{{ - 12}}{5} + \frac{{ - 20}}{5}\\ = \frac{{ - 32}}{5}\end{array}\)

Chú ý: Nếu phân số chưa tối giản, ta nên tối giản phân số trước để việc tính toán được thuận tiện hơn.