\(\left[\left(-0,5\right)^3\right]^x=\dfrac{1}{64}\)

\(\Rightarrow\left(-\dfrac{1}{8}\right)^x=\left(-\dfrac{1}{8}\right)^2\)

\(\Rightarrow x=2\)

Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)

\(\Leftrightarrow\left(\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)

\(\Leftrightarrow3x=6\)

hay x=2

64:0,5 + 64:0,25 + 64\(\times4\)

= 64 \(\times\) 2 + 64 \(\times\) 4 +  64 \(\times\) 4

= 64 \(\times\) ( 2 + 4 + 4)

= 64 \(\times\) 10

= 640 

[(-0.5)³]^x = \(\frac{1}{64}\)

<=> \(\left(-\frac{1}{8}\right)^x\)= \(\left(-\frac{1}{8}\right)^2\)

<=> x = 2

\(\left[-\frac{1}{8}\right]^x=\frac{1}{64}\)

\(\frac{-1^x}{8^x}=\frac{1}{8^2}\)

\(\Rightarrow x=2\)

Vậy,........

Ta có \(\left[\left(-0,5\right)^3\right]^x=\frac{1}{64}\)

\(\Rightarrow\left(\left(\frac{-1}{2}\right)^3\right)^x=\frac{1}{64}\)

\(\Rightarrow\left(-\frac{1}{8}\right)^x=\left(-\frac{1}{8}\right)^{-2}\)

\(\Rightarrow x=-2\)

Câu hỏi là gì bn

Ta có: \(\left[\left(-0.5\right)^3\right]^x=\dfrac{1}{64}\)

\(\Leftrightarrow\left(-\dfrac{1}{2}\right)^{3x}=\dfrac{1}{64}\)

\(\Leftrightarrow3x=6\)

hay x=2

\(8,64\times93+8,64:0,5+8,64:0,25+8,64\)

\(=8,64\times93+8,64\times2+8,64\times4+8,64\times1\)

\(=8,64\times\left(92+4+2+1\right)\)

\(=8,64\times100\)

\(=864\)

giúp mh với mh đang cần gấp 

hứa mh sẽ tích

\(a,\Rightarrow\left[{}\begin{matrix}5x+1=\dfrac{6}{7}\\5x+1=-\dfrac{6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}5x=\dfrac{1}{7}\\5x=-\dfrac{13}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{35}\\x=-\dfrac{13}{35}\end{matrix}\right.\\ b,\Rightarrow\left(-\dfrac{1}{8}\right)^x=\dfrac{1}{64}=\left(-\dfrac{1}{8}\right)^2\Rightarrow x=2\\ c,\Rightarrow\left(x-2\right)\left(2x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-\dfrac{3}{2}\end{matrix}\right.\\ d,\Rightarrow\left(x+1\right)^{x+10}-\left(x+1\right)^{x+4}=0\\ \Rightarrow\left(x+1\right)^{x+4}\left[\left(x+1\right)^6-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\\left(x+1\right)^6=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x+1=1\\x+1=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=0\\x=-2\end{matrix}\right.\\ e,\Rightarrow\dfrac{3}{4}\sqrt{x}=\dfrac{5}{6}\left(x\ge0\right)\\ \Rightarrow\sqrt{x}=\dfrac{10}{9}\Rightarrow x=\dfrac{100}{81}\)

a)9200

9200

6400

b)50

50

19,5

c)128

128

60

a)    92 : 0,01 = 9200          92 x 100 = 9200        64 : 0,01= 6400

b)    25 : 0,5 = 50           25 x 2 = 50           39 : 0,5 = 78
c)    32 : 0,25 = 128         32 x 4 = 128          15 : 0,25 = 60

a)92 : 0,01 = 9200      92 x 100 = 9200          64 : 0,01 = 6400
b)25 : 0,5 = 50            25 x 2 = 50                  39 : 0,5 = 78
c)32 : 0,25 = 128        32 x 4 = 128                 15 x 0,25 = 60

a. x² - 1/4 = 0 

x² = 1/4

x² = (1/2)²

=>x=1/2

b. x² + 16 = 0

=>x²= -16 (vô lí)

=>ko tồn tại x tm~

c. x³ + 27 =  0

x³= -27

x³= (-3)³

=>x= -3

d. 2x³ - 16 = 0

x³ - 8 = 0

x³=8=2³

=>x=2

e.[( - 0,5)³] = 1/64   =>????

h. (2ⁿ)² = 64 

2²ⁿ=2⁶

=>2n=6  => n=3

a) x = 1/2 hoặc x = -1/2

b) Ko có giá trị của x thỏa mãn

c) x = -3

d) x = 2 hoặc x = -2

e) Ko thấy x thì sao giải đc

h) n = 3