x¹²

k đi

x⁷ .x.x⁴ = x.x.x.x.x.x.x.x.x.x.x.x = x¹²

ko bt đúng hay sai nhưng ... thôi kệ !

= \(x^{12}\)

a) 3³ . 3⁴ = 3⁷

b) 5² . 5⁷ = 5⁹

c) 7⁵ . 7 = 7⁶

a) \(3^3.3^4=3^{3+4}=3^7\)

b) \(5^2.5^7=5^{2+7}=5^9\)

c) \(7^5.7=7^{5+1}=7^6\)

\(3^3.3^4=3^{3+4}=3^7\)

\(5^2.5^7=5^{2+7}=5^9\)

\(7^5+7=7^{5+1}=7^6\)

Sao chẳng có ai T mik z bất công quá

4^16

nhớ k cho mình nha

\(4^8.8^4=\left(2^2\right)^8.\left(2^3\right)^4=2^{2.8}.2^{3.4}=2^{16}.2^{12}=2^{16+12}=2^{28}\)

4^8.8^4=4^8.(4.2)^4=4^8.4^4.2^4=4^16

1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)

b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)

c) \(10^8\div10^3=10^{8-3}=10^5\)

d) \(a^7\div a^2=a^{7-2}=a^5\)

2.

\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)

\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)

\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)

còn bài 2

\(\begin{array}{l}a){( - 2)^3}.{( - 2)^4} = {( - 2)^{3 + 4}} = {( - 2)^7}\\b){(0,25)^7}:{(0,25)^3} = {(0,25)^{7 - 3}} = {(0,25)^4}\end{array}\)

\(3^3.3^4=2187\)

\(5^2.5^7=1953125\)

\(7^{5.7}=7^{35}\)

3^3.3^4=3^7=2187

5^2.5^7=5^9=1953125

7^5.7=7^6=117649

bn k mik nhoa!

\(3^3.3^4=3^7\)

\(5^2.5^7=5^9\)

\(7^{5.7}=7^{35}\)

\(x^{12}\)

\(\left(x^4\right)^3\)

\(=x^{4.3}\)

\(=x^{12}\)

x^12

5^177

7^2000

16^136

\(5^{200}:5^{23}=5^{200-23}=5^{177}\)

\(7^{2001}:7=7^{2001-1}=7^{2000}\)

\(16^{137}:4^2=16^{137}:16=16^{137-1}=16^{136}\)

5²⁰⁰ : 5²³ = 5 ^{(200 - 23) =} 5¹⁷⁷

7^{2001 : 7 =} 7^{(2001 - 1) =} 7²⁰⁰⁰

16¹³⁷ : 4² = ( 4²)¹³⁷ : 4² = 4²⁷⁴ : 4² = 4^(274-2) = 4²⁷²