a) 5x = 120 : 2

5x = 60

x = 60 : 5

x = 12

b) 3x + 27 = 45

3x = 45 - 27

3x = 18

x = 18 : 3

x = 6

c) 73 + x - 122 = 234 : 2

73 + x - 122 = 117

73 + x = 117 + 122

73 + x = 239

x = 239 - 73

x = 166

d) 32 - 2(x - 1) = 12

2(x - 1) = 32 - 12

2(x - 1) = 20

x - 1 = 20 : 2

x - 1 = 10

x = 10 + 1

x = 11

e) 3(x + 1) - 15 = 36

3(x + 1) = 36 + 15

3(x + 1) = 51

x + 1 = 51 : 3

x + 1 = 17

x = 17 - 1

x = 16

f) 21 - (4x - 16) = 21

4x - 16 = 21 - 21

4x - 16 = 0

4x = 0 + 16

4x = 16

x = 16 : 4

x = 4

g) 13x - 3x = 500

10x = 500

x = 500 : 10

x = 50

h) 9x + x - 35 = 65

10x - 35 = 65

10x = 65 + 35

10x = 100

x = 100 : 10

x = 10

Bài 6:

\(21,251+6,058+0,749+1,042\)

\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)

\(=22+7,1\)

\(=29,1\)

___________________

\(1,53+5,309+12,47+5,691\)

\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)

\(=14+11\)

\(=25\)

5:

a: =>x/17=5/17

=>x=5

b; =>6+x=7/11*33=21

=>x=15

c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)

=>3x+36=86-2x

=>5x=50

=>x=10

d: \(\dfrac{x}{5}< \dfrac{3}{7}\)

=>x<3/7*5

=>x<15/7

f: 15/26+x/16=46/52

=>x/16=23/26-15/26=8/26=4/13

=>x=4/13*16=64/13

1) 5x = 120 : 2

5x = 60

x = 60 : 5

x = 12.

2) 3x + 27 = 45

3x = 45 - 27

3x = 18

x = 18 : 3

x = 6.

3) 73 + x - 122 = 234 : 2

73 + x - 122 = 117

73 + x = 117 + 122

73 + x = 239

x = 239 - 73

x = 166.

4) 32 - 2 ( x - 1 ) = 12

2 ( x - 1 ) = 32 - 12

2 ( x - 1 ) = 20

x - 1 = 20 : 2

x - 1 = 10

x = 10 + 1

x = 11.

5) 3 ( x + 1 ) - 15 = 36

3 ( x + 1 ) = 36 + 15

3 ( x + 1 ) = 51

x + 1 = 51 : 3

x + 1 = 17

x = 17 - 1

x = 16.

6) 32 - ( 4x - 16 ) = 21

4x - 16 = 32 - 21

4x - 16 = 11

4x = 11 + 16

4x = 27

x = 27 : 4

x = 6,75.

7) 13x - 3x = 500

( 13 - 3 )x = 500

10x = 500

x = 500 : 10

x = 50.

8) 9x + x - 35 = 68

9x + 1x - 35 = 68

9x + 1x = 68 + 35

9x + 1x = 103

( 9 + 1 )x = 103

10x = 103

x = 103 : 10

x = 10,3.

1) 5x = 120 : 2

5x = 60

x = 60 : 5

x = 12.

2) 3x + 27 = 45

3x = 45 - 27

3x = 18

x = 18 : 3

x = 6.

3) 73 + x - 122 = 234 : 2

73 + x - 122 = 117

73 + x = 117 + 122

73 + x = 239

x = 239 - 73

x = 166.

4) 32 - 2 ( x - 1 ) = 12

2 ( x - 1 ) = 32 - 12

2 ( x - 1 ) = 20

x - 1 = 20 : 2

x - 1 = 10

x = 10 + 1

x = 11.

5) 3 ( x + 1 ) - 15 = 36

3 ( x + 1 ) = 36 + 15

3 ( x + 1 ) = 51

x + 1 = 51 : 3

x + 1 = 17

x = 17 - 1

x = 16.

6) 32 - ( 4x - 16 ) = 21

4x - 16 = 32 - 21

4x - 16 = 11

4x = 11 + 16

4x = 27

x = 27 : 4

x = 6,75.

7) 13x - 3x = 500

( 13 - 3 )x = 500

10x = 500

x = 500 : 10

x = 50.

8) 9x + x - 35 = 68

9x + 1x - 35 = 68

9x + 1x = 68 + 35

9x + 1x = 103

( 9 + 1 )x = 103

10x = 103

x = 103 : 10

x = 10,3.

Lời giải:

a. $21-2(x+6)=15$

$2(x+6)=21-15=6$

$x+6=6:2=3$

$x=3-6=-3$

b.

$3^{x+1}=27=3^3$

$\Rightarrow x+1=3$

$\Rightarrow x=2$

c.

$14-x=36$

$x=14-36=-22$

d.

$-3x+25=-2$

$-3x=-2-25=-27$

$x=(-27):(-3)=9$

e.

$37-2(x+6)=29$

$2(x+6)=37-29=8$

$x+6=8:2=4$

$x=4-6=-2$

h.

$2^{x-1}=16=2^4$

$x-1=4$

$x=4+1=5$

\(a,\)( sửa lại xíu đề cho đúng nhé )

\(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=-\frac{2x}{x^2+x+1}\)

\(\Rightarrow\frac{x^2+x+1}{\left(x-1\right)\left(x^2+x+1\right)}-\frac{3x^2}{\left(x-1\right)\left(x^2+x+1\right)}=-\frac{2x\left(x-1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(\Rightarrow x^2+x+1-3x^2=-2x^2+2x\)

\(\Rightarrow x=1\)

\(g,\)\(\left(x+2\right)\left(x+4\right)\left(x+6\right)\left(x+8\right)=-16\)

\(\Rightarrow\left(x^2+10x+16\right)\left(x^2+10x+24\right)=-16\)

Đặt \(x^2+10x+16=a\)

\(\Rightarrow a\left(a+8\right)=-16\)

\(\Rightarrow a^2+8a+16=0\)

\(\Rightarrow\left(a+4\right)^2=0\)

\(\Leftrightarrow\left(x^2+10x+20\right)^2=0\)

\(\Rightarrow x^2+10x+25-25=0\)

\(\Rightarrow\left(x+5\right)^2-\left(\sqrt{5}\right)^2=0\)

\(\Rightarrow\left(x+5-\sqrt{5}\right)\left(x+5+\sqrt{5}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=-5+\sqrt{5}\\x=-5-\sqrt{5}\end{cases}}\)

\(h,\)\(x^3+3x^2+3x+2=0\)

\(\Rightarrow x^3+2x^2+x^2+2x+x+2=0\)

\(\Rightarrow x^2\left(x+2\right)+x\left(x+2\right)+\left(x+2\right)=0\)

\(\Rightarrow\left(x+2\right)\left(x^2+x+1\right)=0\)

Vì \(x^2+x+1=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}>0\)

\(\Rightarrow x+2=0\Leftrightarrow x=-2\)