Cho f(x)=x^7-90x^6+90x^5-90x^4+...+90x+1928
Tính f(89)
Cho f(x)=x^7-90x^6+90x^5-90x^4+...+90x+1928
Tính f(89)
x=89 nên x+1=90
\(f\left(x\right)=x^7-x^6\left(x+1\right)+x^5\left(x+1\right)-x^4\left(x+1\right)+...+x\left(x+1\right)+1928\)
\(=x^7-x^7-x^6+x^6-...+x^2+x+1928\)
=x+1928=89+1928=2017
Tính: \(90x-6750+90x=75x-x^2\)
\(90x-6750=75x-x^2\)
\(\Leftrightarrow180x-6750=75x-x^2\)
\(\Leftrightarrow x^2+105x-6750=0\)
\(\Leftrightarrow x^2-45x+150x-6750=0\)
\(\Leftrightarrow\left(x-45\right)\left(x+150\right)=0
\)
\(\Leftrightarrow\left[{}\begin{matrix}x-45=0\\x+150=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=45\\x=-150\end{matrix}\right.\)
Vậy x=45 hoặc x=-150
Tìm x
a, (x+2)^3 - x(x^2+6x-3)=0
b,(x+4)^3 - x(x+6)^2=7
c, (x-1)^3 - x(x^2-3x-2)=0
d,1000x^3+90x(10x+3)+27=0
e,125x^3+15x(5x+1)= -1
f, 27x^3+45x(3x+5)+133=0
a, \(\left(x+2\right)^3-x\left(x^2+6x-3\right)=0\Leftrightarrow x^3+4x^2+4x+2x^2+8x+8-x^3-6x^2+3x=0\)
\(\Leftrightarrow15x+8=0\Leftrightarrow x=-\frac{8}{15}\)
b, \(\left(x+4\right)^3-x\left(x+6\right)^2=7\Leftrightarrow12x+64=0\Leftrightarrow x=-\frac{19}{4}\)làm tắt:P
Tự làm nốt nhé
Bài 1:
a) (x-y+4)^2-(2x+3y-1)^2
b) x^6+y^6
c) x^16-1
d) x^36-64
e) 9x^2+90x+225-(x-7)^2
f) 49.(y-4)^2-9y^2-36y-36
Giúp mình với -.-
dễ vãi lol ra bn ngu vãi đái
a, \(\left(x-y+4\right)^2-\left(2x+3y-1\right)^2=\left(x-y+4+2x+3y-1\right)\left(x-y+4-2x-3y+1\right)\)
\(=\left(3x+2y+3\right)\left(-x-4y+5\right)\)
b, \(x^6+y^6=\left(x^2\right)^3+\left(y^2\right)^3=\left(x^2+y^2\right)\left(x^4-x^2y^2+y^4\right)\)
c, \(x^{16}-1=\left(x^2\right)^8-1=\left[\left(x^2\right)^4\right]^2-1=\left(x^8-1\right)\left(x^8+1\right)\)
Phân tích à :)
a) ( x - y + 4 )2 - ( 2x + 3y - 1 )2
= [ ( x - y + 4 ) - ( 2x + 3y - 1 ) ][ ( x - y + 4 ) + ( 2x + 3y - 1 ) ]
= ( x - y + 4 - 2x - 3y + 1 )( x - y + 4 + 2x + 3y - 1 )
= ( -x - 4y + 5 )( 3x + 2y + 3 )
b) x6 + y6 = ( x2 )3 + ( y2 )3 = ( x2 + y2 )( x4 - x2y2 + y4 )
c) x16 - 1 = ( x8 )2 - 12 = ( x8 - 1 )( x8 + 1 )
= ( x4 - 1 )( x4 + 1 )( x8 + 1 )
= ( x2 - 1 )( x2 + 1 )( x4 + 1 )( x8 + 1 )
= ( x - 1 )( x + 1 )( x2 + 1 )( x4 + 1 )( x8 + 1 )
d) x36 - 64 = ( x18 )2 - 82
= ( x18 - 8 )( x18 + 8 )
= ( x6 - 2 )( x12 + 2x + 4 )( x6 + 2 )( x12 - 2x + 4 )
e) 9x2 + 90x + 225 - ( x - 7 )2
= ( 3x + 15 )2 - ( x - 7 )2
= ( 3x + 15 - x + 7 )( 3x + 15 + x - 7 )
= ( 2x + 22 )( 2x - 8 )
= 2( x + 11 ).2( x - 4 )
= 4( x + 11 )( x - 4 )
f) 49( y - 4 )2 - 9y2 - 36y - 36
= 72( y - 4 )2 - ( 9y2 + 36y + 36 )
= ( 7y - 28 )2 - ( 3y + 6 )2
= ( 7y - 28 - 3y - 6 )( 7y - 28 + 3y + 6 )
= ( 4y - 34 )( 10y - 22 )
= 2( 2y - 17 ).2( 5y - 11 )
= 4( 2y - 17 )( 5y - 11 )
1x+90x^2 -18x + 20 = 10 .Hãy tìm x
phân tích đa thức thành nhân tử dùng hằng đẳng thức
a/ (x^2+y^2 - 5)^2 - 4(xy-2)^2
b/ (9x^2 + 90x + 225) - (x - 7)^2
a) =( x2+y2-5)2-[2(xy-2)]2
=( x2+y2-5)2- (2xy-4)2
=(x2+y2-5+2xy-4)(x2+y2-5-2xy+4)
=[(x+y)2-9][(x-y)2-1]
phân tích tiếp HĐT 2 ở 2 thừa số
phân tích đa thức thành nhân tử : 9x2+90x+225-(x-7)2
\(=\left(3x+15\right)^2-\left(x-7\right)^2=\left(4x+8\right)\left(2x+22\right)=8\left(x+2\right)\left(x+11\right)\)
(x-7)^2 = x^2-14x+49
<=> 9x^2+90x+225 -x^2+14x-49
= 8x^2+104x+176
= 8(x^2+13+22)
<=> 8(x+2)(x+11)
Phân tích đa thức thành nhân tử:
9x2 + 90x + 225 - ( x - 7)2
9x2+90x+225-(x-7)2
=(3x+15)2-(x-7)2
=(3x+15-x+7)(3x+15+x-7)
=(2x+22)(4x+8)
=2 (x+11)4 (x+2)
=8 (x+11)(x+2)
Phân tích đa thức thành nhân tử
A = x4 -90x2 + 91x - 90
\(=x^4-9x^3+9x^3-81x^2-9x^2+81x+10x-90\)
\(=\left(x-9\right)\left(x^3+9x^2-9x+10\right)\)
\(=\left(x-9\right)\left(x^3+10x^2-x^2-10x+x+10\right)\)
\(=\left(x-9\right)\left(x+10\right)\left(x^2-x+1\right)\)