tim x biet :
x-128 = \(\left(4\frac{20}{21}-5\right):\left(\frac{4141}{4242}-1\right):\left(\frac{636363}{646464}-1\right)\)
Những câu hỏi liên quan
\(x-128=\left(4\frac{20}{11}-5\right):\left(\frac{4141}{4242}-1\right):\left(\frac{636363}{646464}-1\right)\)
x-128=\(\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
=>x-128=(104/21-5):(41/42-1):(63/64-1)
=>\(x-128=\dfrac{-1}{21}:\dfrac{-1}{42}:\dfrac{-1}{64}=\dfrac{-42\cdot64}{21}=-2\cdot64=-128\)
=>x=0
Đúng 0
Bình luận (0)
Tìm x biết :
x-128=\(\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
x - 128 = \(\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
⇔ x - 128 = \(\left(\dfrac{104}{21}-5\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)\)
⇔ x - 128 = \(\left(\dfrac{-1}{21}\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)\)
⇔ x - 128 = -128
⇔ x = -128 + 128
⇔ x = 0
Vậy x = 0
Đúng 0
Bình luận (0)
\(x-128=\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
\(\Rightarrow x-128=\left(-\dfrac{1}{21}\right):\left(-\dfrac{1}{42}\right):\left(-\dfrac{1}{64}\right)\)
\(\Rightarrow x-128=2:\left(-\dfrac{1}{64}\right)\)
\(\Rightarrow x-128=-128\)
\(\Rightarrow x=\left(-128\right)+128\)
\(\Rightarrow x=0\)
Đúng 0
Bình luận (0)
tìmx e Q
x-180=\(\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
\(x-180=\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)\)
\(\Rightarrow x-180=\left(\dfrac{104}{21}-5\right):-\dfrac{1}{42}:-\dfrac{1}{64}\)
\(\Rightarrow x-180=-\dfrac{1}{21}:-\dfrac{1}{42}:-\dfrac{1}{64}\)
\(\Rightarrow x-180=-\dfrac{1}{21}\cdot-42:-\dfrac{1}{64}\)
\(\Rightarrow x-180=2\cdot-64\)
\(\Rightarrow x-180=-128\)
\(\Rightarrow x=-128+180\)
\(\Rightarrow x=52\)
Đúng 2
Bình luận (0)
Bài 1;Tínhfrac{-7}{4}.left(frac{33}{12}+frac{3333}{2020}+frac{333333}{303030}+frac{33333333}{42424242}right)Bài 2;Tìm x,biết:x-128left(4frac{20}{21}-5right):left(frac{4141}{4242}-1right):left(frac{636363}{646464}-1right)Bài 3;Với giá trị nào của x thì :a,Aleft(x-frac{3}{4}right).left(x+frac{1}{2}right)là số dương b,Bfrac{x-0,5}{x+1}là số âmBài 4:Tìm cặp số (x,y) thuộc Z để:Bfrac{1}{x-y}:frac{x+2}{2.left(x-yright)}là số nguyên
Đọc tiếp
Bài 1;Tính
\(\frac{-7}{4}.\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
Bài 2;Tìm x,biết:
\(x-128=\left(4\frac{20}{21}-5\right):\left(\frac{4141}{4242}-1\right):\left(\frac{636363}{646464}-1\right)\)
Bài 3;Với giá trị nào của x thì :
a,\(A=\left(x-\frac{3}{4}\right).\left(x+\frac{1}{2}\right)\)là số dương b,\(B=\frac{x-0,5}{x+1}\)là số âm
Bài 4:Tìm cặp số (x,y) thuộc Z để:
\(B=\frac{1}{x-y}:\frac{x+2}{2.\left(x-y\right)}\)là số nguyên
x-128=( 4+20/21 -5) : ( 4141/4242 -1) : (636363/646464-1)
4+20/21 là hỗn số nha
tìm x
x - 128 =(\(4\frac{20}{21}\)\(-\)5) \(\div\)(\(\frac{4141}{4141}\)- 1) \(\div\)(\(\frac{636363}{646464}\)- 1)
<=> x - 128 = -25/21 : (-1/64)
<=> x - 128 = 1600/21
<=> x = 128 + 1600/21
=> x = 4288/21
Đúng 0
Bình luận (0)
a, x - 128 = ( 4\(\frac{20}{21}\) - 5 ) : ( \(\frac{4141}{4242}\) - 1 ) : ( \(\frac{636363}{646464}\) - 1)
b, A= \(\frac{-7}{4}\) . ( \(\frac{33}{12}\) + \(\frac{3333}{2020}\) + \(\frac{333333}{303030}\) + \(\frac{33333333}{42424242}\) )
Ta có : \(x-128=\left(4\frac{20}{21}-5\right)\left(\frac{4141}{4242}-1\right):\left(\frac{636363}{646464}-1\right)\\ =>x-128=\left(-\frac{1}{21}\right):\left(-\frac{1}{42}\right):\left(-\frac{1}{64}\right)\\ =>x-128=-128\\ =>x=0\)
Đúng 0
Bình luận (1)
a, Ta có x - 128 =( \(4\frac{20}{21}-5\)):\(\left(\frac{4141}{4242}-1\right):\left(\frac{636363}{646464}-1\right)\)
\(\Rightarrow\)x-128= \(\left(\frac{104}{21}-5\right):\left(\frac{41.101}{42.101}-1\right):\left(\frac{63.10101}{64.10101}-1\right)\)
\(\Rightarrow\)x-128=\(\left(\frac{-1}{21}\right):\left(\frac{-1}{42}\right):\left(\frac{-1}{64}\right)\)
\(\Rightarrow x-128=-128\)
\(\Rightarrow x=\left(-128\right)+128\)
\(\Rightarrow x=0\)
Đúng 0
Bình luận (0)
Tim x biet
a/ \(20\left(\frac{x-2}{x+1}\right)^2-5\left(\frac{x+2}{x-1}\right)^2+48\left(\frac{x^2-4}{x^2-1}\right)=0\)
b/ \(\left(2x-1\right)^{2012}=\left(2x-1\right)^{2010}\)
\(b)\) \(\left(2x-1\right)^{2012}=\left(2x-1\right)^{2010}\)
\(\Leftrightarrow\)\(\left(2x-1\right)^{2010}.\left(2x-1\right)^2=\left(2x-1\right)^{2010}\)
\(\Leftrightarrow\)\(\left(2x-1\right)^2=1\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}2x-1=1\\2x-1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=2\\2x=0\end{cases}}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{2}{2}\\x=\frac{0}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}}\)
Vậy \(x=0\) hoặc \(x=1\)
Chúc bạn học tốt ~
Đúng 0
Bình luận (0)