15/x-1/3=28/51
2 . Tìm xeZ
a) x - 3/4 = 1/7
b) 15/x - 1/3 = 28/51
\(a,x-\frac{3}{4}=\frac{1}{7}\)
\(x=\frac{1}{7}+\frac{3}{4}=\frac{25}{28}\)
\(b,\frac{15}{x}-\frac{1}{3}=\frac{28}{51}\)
\(\frac{15}{x}=\frac{28}{51}-\frac{1}{3}=\frac{15}{17}\)
\(\Rightarrow x=17\)
học tốt ~~~
\(x-\frac{3}{4}=\frac{1}{7}\)
\(x\) \(=\frac{1}{7}+\frac{3}{4}\)
\(x\) \(=\frac{4}{28}+\frac{21}{28}\)
\(x\) \(=\frac{4+21}{28}\)
\(x\) \(=\frac{25}{28}\)
a) x - 3/4 = 1/7
x = 1/7 +3/4
x = 4/28 + 21/28
x = 25/28
b) 15/x - 1/3 = 28/51
15/x = 28/51 + 1/3
15x = 28/51 + 17/51
15/x = 15/17
x = 15 : 15/17
x = 17
2 . Tìm xeZ
a) x - 3/4 = 1/7
b) 15/x - 1/3 = 28/51
a) x - 3/4 = 1/7
x = 1/7 + 3/4
x = 25/28
b) 15/x - 1/3 = 28/51
15/x = 28/51 + 1/3
15/x = 45/51
x = 15.51/45
x = 17
Tính hợp lý nếu có thể:
a) -52 x (-2)2 + (-3)3
b) (-19 - 46) : (-13) - (-52) x (-22)
c) (135 - 35) x (-47) + 53 x (-48 - 52)
d) [(-3)13 : 95 - 73] : (-52) - |-14|
e) -105 : (-15) - 21 - 9 x (-2)3
g) (-51) x (-29) - 131 x 51 + |-102|
h) (83 - 107 - 854) - (107 - 554) + 117
k) (-5)2 x 32 x 53 x (-17) x (-1)2n, n thuộc N
n) -28 x (-19) - (-64) x 28 x 17 x |-28|
m) 73 x (28 - 56) - 28 x (73 + 56)
a: \(=-25\cdot4-27=-100-27=-127\)
b: \(=-65:\left(-13\right)-25\cdot4=5-100=-95\)
c: \(=100\cdot\left(-47\right)+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
d: \(=\left[\left(-3\right)^{13}:3^{10}-73\right]:\left(-5\right)^2-14\)
\(=\left(-100\right):25-14=-4-14=-18\)
a) -3/ 5:15 /18 b) -5 / 1:( -4) c)-28 : -7 / 25 d) 51/8 :-2/10
giúp mình nhanh nha ,cảm ơn
\(a,\dfrac{-3}{5}:\dfrac{15}{18}=\dfrac{-3}{5}\times\dfrac{18}{15}=\dfrac{-3}{5}\times\dfrac{6}{5}=\dfrac{-18}{25}\\ b,\dfrac{-5}{1}:\left(-4\right)=\left(-5\right):\left(-4\right)=\dfrac{5}{4}\\ c,-28:\dfrac{-7}{25}=-28\times\dfrac{25}{-7}=100\\ d,\dfrac{51}{8}:\dfrac{-2}{10}=\dfrac{51}{8}\times\dfrac{10}{-2}=\dfrac{51}{8}\times\left(-5\right)=\dfrac{-255}{8}\)
\(a)-3/5*18/15=-18/25\)
\(b)-5*1/-4=5/4\)
\(c)-28*25/-7=-100\)
\(d)51/8*10/-2=-255/8\)
Tính hợp lý nếu có thể:
a) -52 x (-2)2 + (-3)3
b) (-19 - 46) : (-13) - (-52) x (-22)
c) (135 - 35) x (-47) + 53 x (-48 - 52)
d) [(-3)13 : 95 - 73] : (-52) - |-14|
e) -105 : (-15) - 21 - 9 x (-2)3
g) (-51) x (-29) - 131 x 51 + |-102|
h) (83 - 107 - 854) - (107 - 554) + 117
k) (-5)2 x 32 x 53 x (-17) x (-1)2n, n thuộc N
n) -28 x (-19) - (-64) x 28 x 17 x |-28|
m) 73 x (28 - 56) - 28 x (73 + 56)
15/16: .../4=3/28
12/51÷ .../17=4
15/16: 35/4=3/28
12/51÷ 1/17=4
\(\frac{15}{16}:\frac{35}{4}=\frac{3}{28}\) \(\frac{12}{51}:\frac{1}{17}=4\)
chúc bạn học tốt!
\(\frac{15}{16}\div\frac{...}{4}=\frac{3}{28}\)
\(\Rightarrow\frac{15}{16}\div\frac{3}{28}=\frac{35}{4}\)
\(\Rightarrow\)số điền vào chỗ chấm là 35
\(\frac{12}{51}\div\frac{...}{17}=4\)
\(\Rightarrow\frac{12}{51}:4=\frac{1}{17}\)
\(\Rightarrow\)số điền vào chỗ chấm là 1
Thực hiện phép tính:
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
C) ( -2/3 + 3/7 ) : 4/5 + (-1/3 + 4/7 ) : 4/5
D) 5/9 : ( 1/11 -5/22 ) + 5/9 : ( 1/15 - 2/3 )
E) 3/14 : 1/28 -13/21 : 1/28 + 29/42 : 1/28 - 8
F) ( -40/51 x 0,32 x17/20) : 64/75
Đây là dấu x ( là nhân ) mọi người nhé
mong mn giúp em ạ
A) 7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11
=7/38.(9/11+4/11-2/11)
=7/38
B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20
=5/31.(21/25-7/10-9/20)
=5/31.(-31/100)
=-1/20
Tính:
a) \(\dfrac{17}{8}:\left(\dfrac{27}{8}+\dfrac{11}{2}\right);\)
b) \(\dfrac{28}{15}\cdot\dfrac{1}{4^2}.3+\left(\dfrac{8}{15}-\dfrac{69}{60}\cdot\dfrac{5}{23}\right):\dfrac{51}{54}.\)
\(a.\)
\(\dfrac{17}{8}:\left(\dfrac{27}{8}+\dfrac{11}{2}\right)\)
\(=\dfrac{17}{8}:\left(\dfrac{27+44}{8}\right)=\dfrac{17}{8}:\dfrac{71}{8}=\dfrac{17}{8}\cdot\dfrac{8}{71}=\dfrac{17}{71}\)
\(b.\)
\(\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8}{15}-\dfrac{69}{60}\cdot\dfrac{5}{23}\right):\dfrac{51}{54}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8}{15}-\dfrac{1}{4}\right):\dfrac{51}{54}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8\cdot4-15}{60}\right):\dfrac{51}{54}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\dfrac{17}{60}:\dfrac{51}{54}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{16}\cdot3+\dfrac{17}{60}\cdot\dfrac{54}{51}\)
\(=\dfrac{7}{20}+\dfrac{3}{10}\)
\(=\dfrac{7+3\cdot2}{20}=\dfrac{13}{20}\)
Bài 1.Tính
a)\(\dfrac{4}{28}\)+\(\dfrac{12}{36}\) b)\(\dfrac{-12}{18}\)+\(\dfrac{15}{-21}\) c)\(\dfrac{14}{28}\)-\(\dfrac{-16}{32}\)-\(\dfrac{17}{51}\)
\(a,\dfrac{1}{7}+\dfrac{1}{3}=\dfrac{3}{21}+\dfrac{7}{21}=\dfrac{10}{21}\\ b,\dfrac{-2}{3}+\dfrac{-5}{7}=\dfrac{-14+\left(-15\right)}{21}=\dfrac{-29}{21}\\ c,\dfrac{1}{2}-\dfrac{-1}{2}-\dfrac{1}{3}=\dfrac{3+3-2}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(a.\dfrac{4}{28}+\dfrac{12}{36}=\dfrac{1}{7}+\dfrac{1}{3}=\dfrac{3}{21}+\dfrac{7}{21}=\dfrac{10}{21}\\ b.\dfrac{-12}{18}+\dfrac{-15}{21}=\dfrac{-2}{3}+\dfrac{-5}{7}=\dfrac{-14}{21}+\dfrac{-15}{21}=\dfrac{-29}{21}\\ c.\dfrac{14}{28}+\dfrac{16}{32}-\dfrac{17}{51}=\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{17}{51}=1-\dfrac{17}{51}=\dfrac{2}{3}\)
\(\dfrac{4}{28}+\dfrac{12}{36}=\dfrac{144}{1008}+\dfrac{336}{1008}=\\ \dfrac{480}{1008}=\dfrac{10}{21}\)
Câu b và c em làm tương tự.