a)xy(x²+2y)=xy.x²+xy.2y

                  =x³y+2xy²

b)-4(6x²-xy)=-4.6x²+4.xy

                   =-24x²+4xy

c)4x[x²+6x-1/2]

=4x.x²+4x.6x-4x.1/2

=4x³+24x²-2x

a) \(xy\times\left(x^2+2y\right)=x^3y+2xy^2\)

b) \(-4\times\left(6x^2-xy\right)=-24x^2+4xy\)

c)\(4x\times\left(x^2+6x-\frac{1}{2}\right)=4x^3+24x^2-2x\)

- Rút gọn đơn thức

a) 2x.(x^2 + 3x) - 2 (x^3 - 4 + 3x^2)

\(=2x^3+6x^2-2x^3+8-6x^2\)

\(=\left(2x^3-2x^3\right)+\left(6x^2-6x^2\right)-2x^3+8\)

\(=-2x^3+8\)

b) 2x.(5x + 2) - (10x^2 + 4x + 1)

Cách làm tương tự

a ) Ta có : \(\frac{-1}{4x+2}< 0\)

Mà \(-1< 0\) nên \(4x+2< 0\)

\(\Leftrightarrow4x< -2\)

\(\Leftrightarrow x< \frac{-1}{2}\)

a) Ta có: \(48-3\left(x+5\right)=24\)

\(\Leftrightarrow48-3x-15-24=0\)

\(\Leftrightarrow9-3x=0\)

\(\Leftrightarrow3x=9\)

hay x=3

Vậy: x=3

b) Ta có: \(9x-2x=7^8:7^6\)

\(\Leftrightarrow7x=7^2\)

\(\Leftrightarrow x=7\)

Vậy: x=7

<>?/[;b[]rwel;u];53pjkjnlgkljtreylkeuro;uwqr[i5uiwehhwwejokejoiyufljukneghnmknbfvhdbg.elkgiwr;iewqirluoyeiwhtgo

tớ chịu.

hi hi.

1. 41/7 - x = 25/9

=> x = 41/7 - 25/9

=> x = 194/63

2. 3x = 12,8

=> x = 12,8 : 3

=> x = 64/15

3. 41/2 x = 5

=> x = 5: 41/2

=> x = 10/41

4. 3/4 x = 1

=> x = 1: 3/4

=> x = 3/4

5. 4/5 : x = 3

=> x = 4/5 : 3

=> x = 4/15

6. 12/x = 4

=> x = 12/4

=> x = 3

7. 4/7 : x = 4/7

=> x = 4/7 : 4/7

=> x = 1

8. 2x - 3/4 = 7/8

=> 2x = 7/8 + 3/4

=> 2x = 13/8

=> x = 13/8 : 2

=> x =13/16

Ruby Chan :))

1, \(4\frac{1}{7}-x=2\frac{5}{9}\)

\(\frac{4\times7+1}{7}-x=\frac{2\times9+5}{9}\)

\(\frac{29}{7}-x=\frac{23}{9}\)

\(x=\frac{29}{7}-\frac{23}{9}\)

\(x=\frac{261}{63}-\frac{161}{63}\)

\(x=\frac{100}{63}\)

2, \(3\times x=12,18\)

\(x=12,18\div3\)

\(x=4,06\)

3, \(4\frac{1}{2}\times x=5\)

\(\frac{4\times2+1}{2}\times x=5\)

\(\frac{9}{2}\times x=5\)

\(x=5\div\frac{9}{2}\)

\(x=\frac{5\times2}{9}=\frac{10}{9}\)

4, \(\frac{3}{4}\times x=1\)

\(x=1\div\frac{3}{4}\)

\(x=\frac{1\times4}{3}=\frac{4}{3}\)

5, \(\frac{4}{5}\div x=3\)

\(x=\frac{4}{5}\div3\)

\(x=\frac{4}{5\times3}=\frac{4}{15}\)

6,\(\frac{12}{x}=4\)

\(x=12\div4\)

\(x=3\)

7, \(\frac{4}{7}\div x=\frac{4}{7}\)

\(x=\frac{4}{7}\div\frac{4}{7}\)

\(x=1\)

8, \(2x-\frac{3}{4}=\frac{7}{8}\)

\(2x=\frac{7}{8}+\frac{3}{4}\)

\(2x=\frac{7}{8}+\frac{6}{8}\)

\(2x=\frac{13}{8}\)

\(x=\frac{13}{8}\div2\)

\(x=\frac{13}{8\times2}=\frac{13}{16}\)

là giải pt nha m.n

dễ mà bạn

mọi người giải cho m.n vs ạ

Làm ngắn gọn thôi nhé :v

\(A=\frac{2x}{x^2-3x}+\frac{2x}{x^2-4x+3}+\frac{x}{x-1}\)

\(A=\frac{x^5-3x^4-3x^3+11x^2-6x}{x^5-8x^2+22x^2-24x+9}\)

\(A=\frac{x^4-3x^3-3x^2+11x-6}{x^4-8x^3+22x^2-24x+9}\)

\(A=\frac{\left(x-1\right)\left(x-1\right)\left(x+2\right)\left(x-3\right)}{\left(x-1\right)\left(x-1\right)\left(x-3\right)\left(x-3\right)}\)

\(A=\frac{x+2}{x-3}\)

\(B=\frac{x}{x+2}+\frac{2}{x-2}-\frac{4x}{4-x^2}\)

\(B=\frac{-x^4-4x^3+16x+16}{-x^4+8x^2-16}\)

\(B=\frac{\left(-x-2\right)\left(x+2\right)\left(x+2\right)\left(x-2\right)}{\left(-x-2\right)\left(x-2\right)\left(x+2\right)\left(x-2\right)}\)

\(B=\frac{x+2}{x-2}\)

\(C=\frac{1+x}{3-x}-\frac{1-2x}{3+x}-\frac{x\left(1-x\right)}{9-x^2}\)

\(C=\frac{1+x}{3-x}-\left(\frac{1-2x}{3+x}\right)-\frac{x\left(1-x\right)}{9-x^2}\)

\(C=\frac{10x}{-x^2+9}\)

\(D=\frac{5}{2x^2+6x}-\frac{4-3x^2}{x^2-9}-3\)

\(D=\frac{5}{2x^2+6x}-\left(\frac{4-3x^2}{x^2-9}\right)-3\)

\(D=\frac{51x^2+138x-45}{2x^4+6x^2-18x^2-54x}\)

\(D=\frac{3\left(17x-5\right)\left(x+3\right)}{2x\left(x+3\right)\left(x+3\right)\left(x-2\right)}\)

\(D=\frac{51x-15}{2x^3-18x}\)

\(E=\frac{3x+2}{x^2-2x+1}-\frac{6}{x^2-1}-\frac{3x-2}{x^2+2x+1}\)

\(E=\frac{3x+2}{x^2-2x+1}-\frac{6}{x^2-1}-\left(\frac{3x-2}{x^2+2x+1}\right)\)

\(E=\frac{10x^4-10}{x^6-3x^4+3x^2-1}\)

\(E=\frac{10\left(x^2+1\right)\left(x+1\right)\left(x-1\right)}{\left(x+1\right)\left(x+1\right)\left(x+1\right)\left(x-1\right)\left(x-1\right)\left(x-1\right)}\)

\(E=\frac{10x^2+10}{x^4-2x+1}\)