a) \(x^4+324\)

\(=\left(x^2\right)^2+18^2+2.x^2.18-36x^2\)

\(=\left(x^2-18\right)^2-\left(6x\right)^2\)

\(=\left(x^2+18+6x\right)\left(x^2+18-6x\right)\)

b) \(64a^2+b^8\)

\(=\left(8a^2\right)^2+\left(b^4\right)^2+2.8a^2.4b^4-16a^2b^4\)

\(=\left(8a^2+b^4\right)^2-\left(ab^2\right)^2\)

\(=\left(8a^2+b^4+4ab^2\right)\left(8a^2+b^4-4ab^2\right)\)

\(a.\)

\(x^4+324\)

\(=\left(x^2\right)^2+18^2\)

\(=\left(x^2+18\right)\left(x^2_{ }-18\right)\)

\(b.\)

\(64a^2+b^8\)

\(=\left(8a^2\right)+\left(b^3\right)^2\)

\(\left(8a-b^3\right)\left(8a+b^3\right)\)

câu hỏi hay......nhưng tui xin nhường cho các bn khác

Hãy tích đúng cho tui nha

THANKS

x⁴ + 64 = (x⁴ +  16x² + 64) - 16x² = (x² + 8)² - (4x)² = (x² - 4x + 8).(x² + 4x + 8)

Ta có

x⁴ + 64

= (x⁴ +  16x² + 64) - 16x² 

= (x² + 8)² - (4x)² 

= (x² - 4x + 8).(x² + 4x + 8)

hok tốt

Ta có: 
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8 
= (x² + 8)² - (4x)² 
= (x² - 4x + 8)(x² + 4x + 8) 

Ta có: 
x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8 
= (x² + 8)² - (4x)² 
= (x² - 4x + 8)(x² + 4x + 8) 

Ta có: 

x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8 

= (x² + 8)² - (4x)² 

= (x² - 4x + 8)(x² + 4x + 8) 

k nhoa

Ta có: 

x^4 + 64 = (x²)² + 8² + 2x².8 - 2.x².8 

= (x² + 8)² - (4x)² 

= (x² - 4x + 8)(x² + 4x + 8) 

k nhoa

\(x^4+64=\left(x^2\right)^2+8^2=\left(x^2+8\right)\left(x^2-8\right)\)

hdt thức nha bạn

~~~~~~~~~~~~~

^_^

\(x^4+64\)

\(=\left(x^2\right)^2+8^2+2x^2.8-2x^2.8\)

\(=\left(x^2+8\right)^2-\left(4x^2\right)\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

\(x^4+64\)

\(=\left(x^4+16x^2+64\right)-16x^2\)

\(=\left(x^2+8\right)^2-\left(4x\right)^2\)

\(=\left(x^2-4x+8\right)\left(x^2+4x+8\right)\)

x⁴ + 64

= x⁴ + 16x² + 64 - 16x²

= (x² + 8)² - (4x)²

= (x² - 4x + 8)(x² + 4x + 8)

4x⁴ + 1

= 4x⁴ + 4x² + 1 - 4x²

= (2x² + 1) - (2x)²

= (2x² - 2x + 1)(2x² + 2x + 1)

64x⁴ + 1

= 64x⁴ + 16x² + 1 - 16x²

= (8x² + 1)² - (4x)²

= (8x² - 4x + 1)(8x² + 4x + 1)

a: \(x^4+x^2+2x+6\)

\(=x^4-2x^3+3x^2+2x^3-4x^2+6x+2x^2-4x+6\)

\(=\left(x^2-2x+3\right)\left(x^2+2x+2\right)\)