\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.1}=\dfrac{\left(-15\right).40.64}{135.\left(-2\right)^{14}}=\dfrac{\left(-5\right).3.5.8.64}{15.9.\left(-2\right)^{14}}=\dfrac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}=\dfrac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\dfrac{5}{9.\left(-2\right)^5}\)

\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\frac{\left(-5\right)^3.40.4^3}{5.27.4^7}=\frac{\left(-5\right)^3.2}{3^3.4^3}=\frac{\left(-5\right)^3}{3^3.2^5}\)

có gì sai bỏ qua

\(\dfrac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(100\right)^0}=\dfrac{\left(-5\right)^3.2^3.5.2^6}{3^2.5.2^{14}}\)

* giải thích : \(100^0\)= 1 nên mik ko viết nữa

\(\left(-2\right)^{14}=\left(2\right)^{14}\)

ta có : \(\dfrac{\left(-5\right)^3.2^9.5}{3^2.2^{14}.5}=\dfrac{-125}{9.32}=\dfrac{-125}{288}\)

tik mik nhé

a) = -320000/2211840 = -125/864

= ((-5)^3 . 5 . 2^3 . 2^6] / ( 5. 3^3 . 2^14 .1)

= ( (-5

\(\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}.\left(-100\right)^0}=\frac{\left(-5\right)^3.40.4^3}{135.\left(-2\right)^{14}}=\frac{40.\left(-15\right).64}{135.\left(-2\right)^{14}}=\frac{5.8.3.\left(-5\right).64}{15.9.\left(-2\right)^{14}}=\frac{8.\left(-5\right).\left(-2\right)^6}{9.\left(-2\right)^{14}}=\frac{\left(-2\right)^3.5}{9.\left(-2\right)^8}=\frac{5}{9.\left(-2\right)^5}\)

b) \(\dfrac{6\cdot9-2\cdot17}{63\cdot3-119}\)

\(=\dfrac{2\left(3\cdot9-17\right)}{7\cdot\left(3\cdot9-17\right)}\)

\(=\dfrac{2}{7}\)