1.Tính
x-6=11
\(\dfrac{254.399-145}{254+399.253}\)
\(\dfrac{254.399-145}{254+399.253}\)
\(\dfrac{254.399-145}{254+399.253}=\dfrac{101346-145}{254+100947}=1\)
TICK cho mình với nhé các bạn
\(\dfrac{254.399-145}{254+399.253}\)=\(\dfrac{101346-145}{254+100947}\)=\(\dfrac{101201}{101201}\)=1
\(\dfrac{254.399+145}{254+399.253}\)
\(=\dfrac{\left(253+1\right).399-145}{254+399.253}\)
\(=\dfrac{253.399+399-145}{254+399.253}\)
=\(\dfrac{399.253+254}{254+399.253}=1\)
Đề k sai đâu Lê Gia Bảo! Mk gặp đề nỳ rùi!
Tính hợp lý
\(\frac{254.399-145}{254+399.253}\)
đặt biểu thức trên là A
xét A- 1 = \(\frac{254.399-253.399-145-254}{254+399.253}=\frac{399-399}{254+399.253}=0;\) => A= 1
\(\frac{254.399-145}{254+399.253}\)
\(=\)\(\frac{\left(253+1\right).399-145}{254+399.253}\)
\(=\)\(\frac{253.399+399-145}{254+399.253}\)
\(=\)\(\frac{253.399+254}{254+399.253}\)
\(=\)\(1\)
tính hợp lý
\(\frac{41.61+34.41}{3+7+11+...+79}\)
\(\frac{1997.1996-1}{1995.1997+1996}\)
\(\frac{254.399-145}{254+399.253}\)
Bài 6: Tính nhanh:
a) \(\dfrac{254x399-145}{254+399x253}\) ( x ở trong bài này là nhân ạ)
b) \(\dfrac{5932+6001x5931}{5932x6001-69}\)
c) \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\)
a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)
\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)
b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)
\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)
c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)
\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)
Bài 1 : a. Tính nhanh, tính hợp lí :
254x399-145/254+399x253
b.Tìm x :
x nhân x - 1/6 = 5/18
A)\(\frac{254\cdot399-145}{254+399\cdot253}\)
\(=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+1\cdot399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)
\(=\frac{253\cdot399+254}{254+399\cdot253}\Rightarrow=1\)
B) X x X - 1/6 = 5/18
x2 = 5/18 + 1/6
x2 = 8/18 = 4/9
x= \(\sqrt{\frac{4}{9}}\) \(=\frac{2}{3}\)
bài 1 tính nhanh
254 x 399 - 145 / 254 + 399 x 253
\(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}=\frac{253.399+399-145}{254+399.253}=\frac{253.399+254}{254+399.253}=1\)
bài 1 tính nhanh
254 x 399 - 145 / 254 + 399 x 253
ghép đầu cuối dăt chung 399 ra ngoài
kq vẫn như cũ chắc chắn 100%
202292.4291
254.399-145/254.399.253
5932+6001.5931/5932.6001-69
Giải nhanh hộ mình nha!!!!