\(a,x=\dfrac{1}{5}+\dfrac{-3}{7}\)

   \(x=\dfrac{7}{35}+\dfrac{-15}{35}\)

   \(x=-\dfrac{8}{35}\)

\(b,\dfrac{3}{5}-\dfrac{4}{7}:x=\dfrac{-9}{10}\)

           \(\dfrac{4}{7}:x=\dfrac{3}{5}-\dfrac{-9}{10}\)

           \(\dfrac{4}{7}:x=\dfrac{3}{2}\)

                 \(x=\dfrac{4}{7}:\dfrac{3}{2}\)

                 \(x=\dfrac{4}{7}\times\dfrac{2}{3}\)

                 \(x=\dfrac{8}{21}\)

\(c,x-\left(\dfrac{-3}{4}\right)=\dfrac{-2}{3}-\dfrac{1}{2}\)

   \(x+\dfrac{3}{4}=\dfrac{-4}{6}-\dfrac{3}{6}\)

   \(x+\dfrac{3}{4}=-\dfrac{7}{6}\)

           \(x=-\dfrac{7}{6}-\dfrac{3}{4}\)

           \(x=-\dfrac{23}{12}\)

\(d,\dfrac{-5}{9}-x=\dfrac{1}{3}+\dfrac{7}{18}\)

    \(\dfrac{-5}{9}-x=\dfrac{6}{18}+\dfrac{7}{18}\)

     \(\dfrac{-5}{9}-x=\dfrac{13}{18}\)

                \(x=\dfrac{-5}{9}-\dfrac{13}{18}\)

                \(x=\dfrac{-10}{18}-\dfrac{13}{18}\)

                \(x=-\dfrac{23}{18}\)

Lời giải:
a.

$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$

b.

$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$

c.

$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$

$x=(-1).\frac{-8}{9}=\frac{8}{9}$

1A

2C

a, A

b, C

A,C

a)\(\dfrac{x}{60}=-\dfrac{3}{4}\)

\(\Rightarrow x\cdot4=60\cdot\left(-3\right)\)

   \(x\cdot4=-180\)

  x=45

b)\(\dfrac{2}{5}=\dfrac{12}{x}\)

   \(\Rightarrow2x=5\cdot12\)

      \(2x=60\)

       x=30

c)\(x-\dfrac{5}{7}=\dfrac{6}{21}\)

      \(x=\dfrac{2}{7}+\dfrac{5}{7}\)

      x=1

d)\(x+\dfrac{7}{8}=\dfrac{63}{24}\)

     \(x=\dfrac{21}{8}-\dfrac{7}{8}\)

     \(\dfrac{14}{8}\)

a)\(\dfrac{x}{60}=\dfrac{-3}{4}\Rightarrow x=\dfrac{-3.60}{4}=-45\)

b)\(\dfrac{2}{5}=\dfrac{12}{x}\Rightarrow x=\dfrac{5.12}{2}=30\)

BÀI 1: 

\(a,x^2-2x-1\)

\(=x^2-2x+1-2\)

\(=\left(x-1\right)^2-2\)

Vì: \(\left(x-1\right)^2\ge0\forall x\)

\(\Rightarrow\left(x-1\right)^2-2\ge-2\forall x\)

Dấu = xảy ra khi : \(\left(x-1\right)^2=0\Rightarrow x=1\)

Vậy: GTNN của bt là -2 tại x=1

\(b,4x^2+4x-5\)

\(=4x^2+4x+1-6\)

\(=\left(2x+1\right)^2-6\)

Vì: \(\left(2x+1\right)^2\ge0\forall x\)

\(\Rightarrow\left(2x+1\right)^2-6\ge-6\forall x\)

Dấu = xảy ra khi \(\left(2x+1\right)^2=0\Rightarrow x=-\frac{1}{2}\)

VậyGTNN của bt là -6 tại x=-1/2

BÀI 2:

\(a,2x-x^2-4\)

\(=-x^2+2x-4\)

\(=-x^2+2x-1-3\)

\(=-\left(x^2-2x+1\right)-3\)

\(=-\left(x-1\right)^2-3\)

Vì: \(-\left(x-1\right)^2\le0\forall x\)

\(\Rightarrow-\left(x-1\right)^2-3\le-3\forall x\)

Dấu = xảy ra khi : \(-\left(x-1\right)^2=0\Rightarrow x=1\)

Vậy GTLN của bt là -3 tại x=1

b,mk chưa nghĩ ra,lúc nào mk nghĩ ra sẽ gửi lời giải cho bn

1)

a) Đặt \(A=x^2-2x+1\) 

\(\Rightarrow A=x^2-2x-1=\left(x^2-2.x.1+1^2\right)-2=\left(x-1\right)^2-2\)

Ta có: \(\left(x-1\right)^2\ge0\forall x\Rightarrow\left(x-1\right)^2-2\ge2\forall x\)

\(A=2\Leftrightarrow\left(x-1\right)^2=0\Leftrightarrow x-1=0\Leftrightarrow x=1\)

Vậy \(A_{min}=2\Leftrightarrow x=1\)

Câu b tương tự

2)

a) Đặt \(B=2x-x^2-4\)

 \(B=2x-x^2-4=-\left(x^2-2x+1\right)-3=-\left(x-1\right)^2-3\)

Ta có: \(\left(x-1\right)^2\ge0\forall x\Rightarrow-\left(x-1\right)^2\le0\forall x\Rightarrow-\left(x-1\right)^2-3\le-3\forall x\)

\(B=-3\Leftrightarrow-\left(x-1\right)^2=0\Leftrightarrow x-1=0\Leftrightarrow x=1\)

Vậy\(B_{max}=-3\Leftrightarrow x=1\)

b) Đặt \(C=-x^2-4\)

Ta có: \(x^2\ge0\forall x\Rightarrow-x^2\ge0\forall x\Rightarrow-x^2-4\le-4\forall x\)

\(C=-4\Leftrightarrow-x^2=0\Leftrightarrow x=0\)

Vậy \(C_{max}=-4\Leftrightarrow x=0\)

thôi bn tham khảo bài của bn kudo shinichi đi, bn ấy lm đúng rồi

a. \(x-\frac{3}{7}:\frac{9}{14}=-\frac{7}{6}\Rightarrow x-\frac{2}{3}=-\frac{7}{6}\Rightarrow x=-\frac{1}{2}\)

b. \(\frac{3}{4}+\frac{1}{4}x=\frac{5}{8}\Rightarrow\frac{1}{4}x=-\frac{1}{8}\Rightarrow x=-\frac{1}{2}\)

c. \(\left|4x-1\right|-\frac{1}{2}=3\Rightarrow\left|4x-1\right|=\frac{7}{2}\Leftrightarrow\orbr{\begin{cases}4x-1=\frac{7}{2}\\4x-1=-\frac{7}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{9}{8}\\x=-\frac{5}{8}\end{cases}}}\)

d. \(25\%x+x=-1,25\Rightarrow125\%x=-1,25\Rightarrow\frac{5}{4}x=-\frac{5}{4}\Rightarrow x=-1\)

BN ƠI CÂU D 125% Ở ĐÂU DZẠ

a, \(x-\frac{3}{7}:\frac{9}{14}=-\frac{7}{6}\Leftrightarrow x-\frac{2}{3}=-\frac{7}{6}\Leftrightarrow x=-\frac{1}{2}\)

b, \(\frac{3}{4}+\frac{1}{4}x=\frac{5}{8}\Leftrightarrow\frac{1}{4}x=-\frac{1}{8}\Leftrightarrow x=-\frac{1}{2}\)

c, \(\left|4x-1\right|-\frac{1}{2}=3\Leftrightarrow\left|4x-1\right|=\frac{7}{2}\)

\(\Leftrightarrow\orbr{\begin{cases}4x-1=\frac{7}{2}\\4x-1=-\frac{7}{2}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{9}{8}\\x=-\frac{5}{8}\end{cases}}}\)

d, \(25\%x+x=-1,25\Leftrightarrow\frac{1}{4}+x=-\frac{5}{4}\Leftrightarrow x=-\frac{3}{2}\)

B1:

A.1+1=2

B.6+2+5=13

C.6+4+6+2+7=25

D.6+4+7+8=25

B2:

A.x+2=3

x=3-2

x=1

B.x+5=4+6

x+5=10

x=10-5

x=5

C.7=4+x

x=7-4

x=3

D.4+x={3+5+7}+{3+5}

4+x=15+8

4+x=23

x=23-4

x=19

Bài 1 :

A.1+1=2

B.6+2+5=13

C.6+4+6+2+7=25

D.6+4+7+8=25

Bài 2 :

A.x+2=3

x=3-2

x=1

B.x+5=4+6

x+5=10

x=10-5

x=5

C.7=4+x

x=7-4

x=3

D.4+x={3+5+7}+{3+5}

4+x=15+8

4+x=23

x=23-4

x=19

Chúc bạn học tốt nha ~_~

8741418+54846852+65268478418654985897485+485495974549548941+95+556874418745985+989797594                                                                                                                                                                                 449859745264857897+5-5954567454187+97456415641874654+56454854564+48564165487-566555541++564564868456556486846589-6564644848654659898595985958948888555555.                         ...................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

a) \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Rightarrow5x=10\)

\(\Leftrightarrow x=2\)

Vậy x = 2

b) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Rightarrow-3x=-48\)

\(\Leftrightarrow x=16\)

Vậy x = 16

c) \(\dfrac{1}{9}=\dfrac{-2x}{10}\)

\(\Rightarrow-18x=10\)

\(\Leftrightarrow x=-\dfrac{5}{9}\)

Vậy \(x=-\dfrac{5}{9}\)

d) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{x}-5=\dfrac{-9}{x}+2\)

\(\Leftrightarrow\dfrac{3-5x}{x}=\dfrac{-9+2x}{x}\)

\(\Rightarrow3-5x=-9+2x\)

\(\Leftrightarrow7x=12\)

\(\Leftrightarrow x=\dfrac{12}{7}\)

Vậy \(x=\dfrac{12}{7}\)

e) ĐKXĐ: \(x\ne0\)

 \(\dfrac{x}{-2}=\dfrac{-8}{x}\)

\(\Rightarrow x^2=16\)

\(\Leftrightarrow x=\pm4\)

Vậy \(x=\pm4\)

a) Ta có: \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Leftrightarrow x=\dfrac{2\cdot5}{5}=2\)

Vậy: x=2

b) Ta có: \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Leftrightarrow-x=\dfrac{6\cdot\left(-8\right)}{3}=-16\)

hay x=16

Vậy: x=16