\(=x^2-\left(y-4\right)^2\)

\(=\left(x-y+4\right)\left(x+y-4\right)\)

\(=x^2-\left(y^2-8y+16\right)=x^2-\left(y-4\right)^2=\left(x-y+4\right)\left(x+y-4\right)\)

Đa thức này không phân tích được nhé bạn

Đề sai.

5x² + 10xy - 4x - 8y

= 5x(x + 2y) - 2(x - 2y)

= (5x - 2)(x + 2y)

=(5x² + 10xy) - (4x + 8y) = 5x.(x + 2y) - 4.(x + 2y) = (5x - 4).(x + 2y)

\(5x^2+10xy-4x-8y=\left(5x^2+10xy\right)-\left(4x+8y\right)=5x\left(x+2y\right)-4\left(x+2y\right)=\left(5x-4\right)\left(x+2y\right)\)

D = x² - 4x - y² - 8y - 12 

= (x² - 4x + 4) - (y² + 8y + 16) 

= (x - 2)² - (y + 4)²

= (x + y + 2)(x - y - 6) 

\(D=x^2-4x-y^2-8y-12\)

\(=x^2-4x-y^2-8y+4-16\)

\(=\left(x^2-4x+4\right)-\left(y^2+8y+16\right)\)

\(=\left(x-2\right)^2-\left(y+4\right)^2\)

\(=\left(x-2-y-4\right)\left(x-2+y+4\right)\)

\(=\left(x-y-6\right)\left(x+y+2\right)\)

\(12x-9-4x^2=-\left(2x-3\right)^2\\ Sửa:x^3-6x^2y+12xy^2-8y^3=\left(x-2y\right)^3\)

c: \(x^2-4+3\left(x-2\right)^2\)

\(=\left(x-2\right)\left(x+2\right)+\left(x-2\right)\left(3x-6\right)\)

\(=\left(x-2\right)\left(x+2+3x-6\right)\)

\(=\left(4x-4\right)\left(x-2\right)\)

\(=4\left(x-1\right)\left(x-2\right)\)

ghytyyj