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\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)

\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)

\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)

\(\dfrac{3}{4}-x=\dfrac{91}{66}\)

\(x=\dfrac{-83}{132}\)

a: Ta có: \(-\dfrac{12}{25}\cdot\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)

\(\Leftrightarrow x+\dfrac{83}{132}=0\)

hay \(x=-\dfrac{83}{132}\)

12 : x +5 = 3+ 5

12 : x +5 = 8

12: x = 8-5 

12:x = 3

x = 12 :3 

x= 4

5 x [ x + 19 ] = 170-50

5x [ x+ 19 ] = 120

x+ 19 = 120 : 5

x + 19 = 24

x = 24 -19

x = 5

       11 x ( x - 6 ) = 4 * x + 11

\(\rightarrow\)11 * x - 11 x 6 = 4 * x + 11

\(\rightarrow\)11 * x - 66 = 4 * x + 11

\(\rightarrow\)11 * x - 4 * x = 66 + 11 

\(\rightarrow\)( 11 - 4 ) * x = 77

\(\rightarrow\)     7   *   x = 77

\(\rightarrow\)              77 : 7

\(\rightarrow\)                 11

còn 2 bài trên làm như bạn nguyen ha anh 56789

\(x-\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)

\(x=\frac{3}{6}+\left(\frac{1}{9}-\frac{3}{5}\right)\)

\(x=\frac{3}{6}+\left(-\frac{22}{45}\right)\)

\(x=\frac{1}{90}\)

\(\frac{-12}{25}.\frac{3}{4}-x+\frac{6}{-11}-\frac{5}{6}=0\)

\(\frac{-9}{25}-x+\left(\frac{-91}{66}\right)=0\)

\(\frac{-9}{25}-x=0+\left(\frac{-91}{66}\right)\)

\(\frac{-9}{25}-x=\frac{-91}{66}\)

\(x=\left(\frac{-9}{25}\right)-\left(\frac{-91}{66}\right)\)

\(x=\frac{1681}{1650}\)

a) x = 15

b) x = 11

c) x = 68

d) x = 310

(x4)3=x6x19

a) x = 15.              b)      x = 11.        c) x = 68.              d) x = 310

Tìm xx biết:    \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19​

Trả lời: x=x=