a)\(3:2 = 1,5\,\,\,\,\,\,\,\,\,\,\,37:25 = 1,48\,\,\,\,\,\,\,\,5:3 = 1,666...\,\,\,\,\,\,1:9 = 0,111...\)

b) \(\frac{3}{2} = 1,5;\,\,\,\,\frac{{37}}{{25}} = 1,48;\,\,\,\,\frac{5}{3} = 1,666...;\,\,\,\frac{1}{9} = 0,111...\)

Chú ý: Các phép chia không bao giờ dừng ta viết ba chữ số thập phân sau dấu phẩy và sau đó thêm dấu ba chấm phía sau.

-3/18-12/9

=-1/6+-4/3

=-1/6+-8/6

=-9/6

=-3/2

-49/115:7/-115

=-49/115x-115/7

=7

a)   -3/18 -12/9

=  -1/6 - 4/3

=  -1/6 - 8/6

= -1-8/6

= -9/6

= -3/2

= -1/1/2 

Bài 3 :

a) \(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\cdot2\frac{2}{17}\right]\)

\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\cdot\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right)\cdot\frac{36}{17}\right]\)

\(=\left(-\frac{14}{25}\right)^2\cdot\frac{125}{49}+\left[\left(-\frac{119}{36}\right)\cdot\frac{36}{17}\right]\)

\(=-\frac{196}{625}\cdot\frac{125}{49}+\left(-7\right)=-\frac{4}{5}+\left(-7\right)=-\frac{39}{5}\)

Trả lời :

\(\left(\frac{1}{25}-0,6\right)^2\div\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right)\times2\frac{2}{17}\right]\)

\(=\left(\frac{1}{25}-\frac{3}{5}\right)^2\div\frac{49}{125}+\left[\frac{-119}{36}\times\frac{36}{17}\right]\)

\(=\left(\frac{-14}{25}\right)^2\div\frac{49}{125}-7\)

\(=\frac{4}{5}-7\)

\(=\frac{-31}{5}\)

\(\left(\frac{1}{25}-0,6\right)^2:\frac{49}{125}+\left[\left(3\frac{1}{4}-6\frac{5}{9}\right).2\frac{2}{17}\right]\)

\(=\left(-\frac{14}{25}\right)^2.\frac{125}{49}+\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)

\(=\frac{196}{625}.\frac{125}{49}+\left(-\frac{119}{36}.\frac{36}{17}\right)\)

\(=\frac{4}{5}+\left(-7\right)\)

\(=-\frac{31}{5}\)

a) \(=-\frac{91}{50}:4\)

   \(=-\frac{91}{200}\)

b) \(=\frac{5}{18}-\frac{26}{5}+\frac{18}{5}\)

   \(=-\frac{119}{90}\)

\(\left(\frac{9}{25}-2,18\right):\left(3\frac{4}{5}+0,2\right)\)

\(=\left(-1,82\right):4\)

\(=-0,455\)

\(a,\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)

\(=\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)

\(=\frac{31}{25}:\left(-\frac{29}{25}\right)\)

\(=\frac{31}{25}.\frac{-25}{29}\)

\(=-\frac{31}{29}\)

\(b,\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)

\(=\left[\frac{109}{6}-\left(\frac{3}{50}:\frac{15}{2}+\frac{17}{5}.\frac{19}{50}\right)\right]:\left(19-\frac{8}{3}.\frac{19}{4}\right)\)

\(=\left(\frac{109}{6}-\frac{13}{10}\right):\frac{19}{3}\)

\(=\frac{253}{15}.\frac{3}{19}\)

\(=\frac{253}{95}\)

Số to :v

a, 103

b, 6

c, 8

d,21

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