a) (x+3)² + (4+x)(4-x) = 10

x² + 6x + 9 + 16- x² = 10

6x + 25 = 10

6x = -15

x = -15/6

b) 9(x+1)² - (3x-2)(3x+2) = 10

9x² + 18x + 9 - 9x² + 4 =10

18x + 13 = 10

18x = -3

x = -1/6

a) ( x + 3 )² + ( 4 + x )( 4 - x ) = 10

⇔ x² + 6x + 9 + 16 - x² = 10

⇔ 6x + 25 = 10

⇔ 6x = -15

⇔ x = -15/6 = -5/2

b) 9( x + 1 )² - ( 3x - 2 )( 3x + 2 ) = 10

⇔ 9( x² + 2x + 1 ) - ( 9x² - 4 ) = 10

⇔ 9x² + 18x + 9 - 9x² + 4 = 10

⇔ 18x + 13 = 10

⇔ 18x = -3

⇔ x = -3/18 = -1/6

a) \(\left(x+3\right)^2+\left(4+x\right)\left(4-x\right)=10\)

\(x^2+6x+9+16-x^2=10\)

\(6x+25=10\)

\(6x=-15\)

\(x=-\frac{5}{2}\)

b) \(9.\left(x+1\right)^2-\left(3x-2\right)\left(3x+2\right)=10\)

\(9.\left(x^2+2x+1\right)-9x^2+4=10\)

\(9x^2+18x+9-9x^2+4=10\)

\(18x+13=10\)

\(18x=-3\)

\(x=-\frac{1}{6}\)

4x² + 3x - 4x² + 8x - 10 = 0

11x - 10 = 0

x = 10/11

\(3x\left(\dfrac{4}{3}x+1\right)-4x\left(x-2\right)=10\)

\(\Leftrightarrow4x^2+3x-4x^2+8x=10\)

\(\Leftrightarrow x=\dfrac{10}{11}\)

\(3x\left(\dfrac{4}{3}x+1\right)-4x\left(x-2\right)=10\\ \Leftrightarrow4x^2+3x-4x^2+8x=10\\ \Leftrightarrow11x=10\Leftrightarrow x=\dfrac{10}{11}\)

=>2(4-3x)=14

=>4-3x=7

=>3x=-3

hay x=-1

\(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x=-4\)

\(\Leftrightarrow2+6x=-4\)

\(\Leftrightarrow6x=-4-2\)

\(\Leftrightarrow6x=-6\)

\(\Leftrightarrow x=\frac{-6}{6}\)

\(\Leftrightarrow x=-1\)

\(\text{Vậy }x=-1\)

10 - 2(4 - 3x)= -4

=> 10 - 8 + 6x = -4

=> 6x = -4 + 8 -10

=> 6x = -6

=> x = -1.

Vậy x = -1

10 - 2( 4 - 3x ) = -4

=> 10 - 8 + 6x = -4

=> ( 10 - 8 + 4 ) = 6x

=> 6 = 6x => x = 1

\(0,\left(90\right)\)nhé bạn
 

\(4x^2+3x-\left(4x^2+8x\right)=10\)

\(4x^2+3x-4x^2-8x=10\)

\(-5x=10\)

\(x=10:\left(-5\right)=-2\)

a ) 10 x X - 1 - 3 - 5 - 7 - ... - 19 = 2 + 4 + 6 + ... + 20

10 x X - 1 - 3 - 5 - 7 - ... - 19 = 110

10 x X - ( 1 + 3 + 5 + 7 + ... + 19 ) = 110

10 x X - 100 = 110

10 x X = 110 + 100

10 x X = 210

       X = 210 : 10

       X = 21

a 10 x X-1-3-5-7-....-19 = 2+4+6+....+20

​10xX-1-3-5-7-....-19=110

​10xX=110+1+3+5+7+....+19

​10xX=210

​X=210:10

​X=21

b là 4

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=> 2(4-3x)=10-(-4)

=> 2(4-3x)=14

=> 4-3x=14:2

=> 4-3x=7

=> 3x=4-7

=> 3x=-3

=> x=(-3):3

=> x=(-1)

2(4-3x)=14

4-3x=7

3x=-3

x=-1

10-2(4-3x)=-4

2(4-3x)=10--4

2(4-3x)=14

4-3x=14:2

4-3x=7

3x=4-7

3x=-3

x=-3:3

x=-1

\(2\left(x-1\right)+3\left(3x-2\right)=x-4\)

\(2x-2+9x-6=x-4\)

\(2x+9x-x-2-6=-4\)

\(10x-2-6=-4\)

\(10x-2=2\)

\(10x=4\)

\(x=\frac{2}{5}\)

Vậy \(x=\frac{2}{5}\)

\(3\left(4-x\right)-2\left(x-1\right)=x+20\)

\(12-3x-2x+2=x+20\)

\(12-5x+2=x+20\)

\(12-5x-x+2=20\)

\(12-6x+2=20\)

\(12-6x=18\)

\(6x=-6\)

\(x=-1\)

Vậy \(x=-1.\)

\(4\left(2x+7\right)-3\left(3x-2\right)=24\)

\(8x+28-9x+6=24\)

\(8x-9x+28+6=24\)

\(-x+34=24\)
\(-x=-10\)

\(x=10\)

Vậy \(x=10\)

\(3\left(x-2\right)+2x=10\)

\(3x-6+2x=10\)

\(3x+2x-6=10\)
\(5x=16\)

\(x=\frac{16}{5}\)

Vậy \(x=\frac{16}{5}\)

2(x-1)+3(3x-2)=x-4

=>2x-2=9x-6-x+4=0

=>10x-4=0

=>x=\(\frac{2}{5}\)

3(4-x)-2(x-1)=x+20

=>12-3x-2x+2-x-20=0

=>-6x-6=0

=>-6(x-1)=0

=>x-1=0

=>x=1

4(x - 10) - (-3x + 4) = -2(x + 5) - (-4x +20)

=> 4x - 40 + 3x - 4 = -2x - 10 + 4x - 20

=> 7x - 44 = 2x - 30

=> 7x - 2x = -30 + 44

=> 5x = 14

=> x = 14 : 5

=> x = 14/5

\(4\left(x-10\right)-\left(-3x+4\right)=-2\left(x+5\right)-\left(-4x+20\right)\)

\(\Rightarrow4x-40+3x-4=-2x-10+4x-20\)

\(\Rightarrow4x+3x+2x-4x=-10-20+4+40\)

\(\Rightarrow5x=14\Rightarrow x=\frac{14}{5}\)

\(4(x-10)-(-3x+4)=-2(x+5)-(-4x+20)\)

\(\Rightarrow4x-40+3x-4=(-2)x-10+4x-20\)

\(\Rightarrow7x-44=2x-30\)

\(\Rightarrow7x-2x=44-30\)

\(\Rightarrow5x=14\)

\(\Rightarrow x=\frac{14}{5}\)

a)(4-x)²+15=40

   (4-x)²=40-15

   (4-x)²=25

    (4-x)²=5²

=>4-x=5

x=5-4

x=1

a) ( 4 - x )² + 15 = 40

( 4 - x )² = 40 - 15

( 4 - x )² = 25

( 4 - x )² = 5²

4 - x = 5

     x = 4 - 5

     x = ( - 1 )

b, ( 3x - 2 )¹⁰ = ( 3x - 2 )⁴

=> x \(\in\left\{0;1\right\}\)

c, X = 1 + 4 + 4² + ......... + 4²⁰¹⁷

4X = 4 + 4¹ + ......... + 4²⁰¹⁸

4X - X = ( 4 + 4¹ + ........ + 4²⁰¹⁸ ) - ( 1 + 4 + 4² + ......... + 4²⁰¹⁷ )

4X - X = 4 + 4¹ + ......... + 4²⁰¹⁸ - 1 - 4 - 4² - ......... - 4²⁰¹⁷

=> 3X = 4²⁰¹⁸ - 1

=> X = \(\frac{4^{2018}-1}{3}\)