\(\dfrac{10^3+5\cdot10^2+5^2}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot2^3+5\cdot2^2\cdot5^2+5^2}{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}\\ =\dfrac{5^3\left(2^3+2^2+1\right)}{3^3\left(2^3+2^2+1\right)}=\dfrac{5^3}{3^3}=\dfrac{125}{27}\)

4 (x-3)=3
x-3=3:4
x-3=0,75
x=0,75+3
x=3,75

b, 4 ( x - 3 ) = 3

x - 3 = \(\dfrac{3}{4}\) = 0,75 

x = 0,75 + 3 = 3,75

x=3:4+3=15/4

x/3=7/15+-1/5                             

x/3=2/15                                       

5x/15=2/15                                    

5x=2                                                  

x=2/5

x= 2/5

CHÚC BẠN HỌC TỐT 

\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)

12(x-1)=0

     (x-1)=0:12

      x-1=0

      x=0+1

      x= 1

Vậy x= 1

12 ( x - 1 ) = 0
       x - 1   = 0 : 12
       x - 1   = 0
=>   x        = 1

Tìm x:

5x + x = 150 : 2 + 3

x(5+1) = 75+3

6x=78

x=78:6

x=13

\(5x+x=150:2+3\)

\(\Leftrightarrow6x=75+3=78\)

\(\Leftrightarrow x=\frac{78}{6}\)

\(\Leftrightarrow x=13\)

a)\(\frac{3x}{7}=\frac{5x-1}{2}=>\frac{6x}{14}=\frac{35x-7}{14}\)

=>6x=35x-7

=>35x-6x=7

=>29x=7

=>\(x=\frac{7}{29}\)

b)\(\frac{2-5x}{3}=\frac{4+x}{5}=>\frac{10-25x}{15}=\frac{12+3x}{15}\)

=>10-25x=12+3x

=>25x+3x=10-12

=>28x=-2

=>\(x=\frac{-2}{28}=-\frac{1}{14}\)