phân tích đa thức sau thành nhân tử
8, x mũ 4 + 2x mũ 3 + x mũ 2 - y mũ 2
1
phân tích các đa thức sau thành nhân tử8
7, 49 y mũ 2 - x mũ 2 + 6x - 9
8, 25x mũ 2 - 4y mũ 2 - 4y - 9
9, 4x mũ 2 -- y mũ 2 + 8y - 16
Trả lời:
7, 49y2 - x2 + 6x - 9
= 49y2 - ( x2 - 6x + 9 )
= ( 7y )2 - ( x - 3 )2
= ( 7y - x + 3 ) ( 7y - x - 3 )
8, sửa đề: 25x2 - 4y2 - 4y - 1
= 25x2 - ( 4y2 + 4y + 1 )
= ( 5x )2 - ( 2y + 1 )
= ( 5x - 2y - 1 ) ( 5x + 2y + 1 )
9, 4x2 - y2 + 8y - 16
= 4x2 - ( y2 - 8y + 16 )
= ( 2x )2 - ( y - 4 )2
= ( 2x - y + 4 ) ( 2x + y - 4 )
a, \(49y^2-x^2+6x-9=49y^2-\left(x-3\right)^2=\left(7y-x+3\right)\left(7y+x-3\right)\)
b, đề sai rồi bạn
c, \(4x^2-y^2+8y-16=4x^2-\left(y-4\right)^2=\left(2x-y+4\right)\left(2x+y-4\right)\)
phân tích đa thức sau thành nhân tử
6, x mũ 4 - 4x mũ 3 - 8x mũ 2 + 8x
8, x mũ 4 + 2x mũ 3 + x mũ 2 - y mũ 2
10, 4x mũ 2 ( x + y ) -x - y
6, x mũ 4 - 4x mũ 3 - 8x mũ 2 + 8x =x (x+2) (x^2-6x+4)
8, x mũ 4 + 2x mũ 3 + x mũ 2 - y mũ 2 = -(y-x^2-x) (y+x^2+x)
10, 4x mũ 2 ( x + y ) -x - y = (2x-1) (2x+1) (y+x)
phân tích đa thức sau thành nhân tử
1, x mũ 2 - y mũ 2 + 4x + 4
2, x mũ 2 + 2x - 4y mũ 2 - 4y
3, 3x mũ 2 - 4y + 4x - 3y mũ 2
4, x mũ 4 - 6x mũ 3 + 54x - 81
phân tích đa thức sau thành nhân tử
t, x mũ 2 y - xy mũ 2 + x mũ 3 - y mũ 3
o, 4x mũ 2 - 25 + ( 2x + 7 )( 5 - 2x )
p, 5x mũ 2 - 5y mũ 2 - 10x + 10y
r, x mũ 2 - xy + 4x - 2y + 4
a)x²−2x−4y²−4ya)x²-2x-4y²-4y
=x²−2x−4y²−4y+2xy−2xy=x²-2x-4y²-4y+2xy-2xy
=(x²−2xy−2x)+(2xy−4y²−4y)=(x²-2xy-2x)+(2xy-4y²-4y)
=x(x−2y−2)+2y(x−2y−2)=x(x-2y-2)+2y(x-2y-2)
=(x+2y)(x−2y−2)=(x+2y)(x-2y-2)
b)x4+2x³−4x−4b)x4+2x³-4x-4
=x4+2x³+2x²−2x²−4x−4=x4+2x³+2x²-2x²-4x-4
=(x4+2x³+2x²)−(2x²+4x+4)=(x4+2x³+2x²)-(2x²+4x+4)
=x²(x²+2x+2)−2(x²+2x+2)=x²(x²+2x+2)-2(x²+2x+2)
=(x²−2)(x²+2x+2)=(x²-2)(x²+2x+2)
c)x³+2x²y−x−2yc)x³+2x²y-x-2y
=x²(x+2y)−(x+2y)=x²(x+2y)-(x+2y)
=(x²−1)(x+2y)=(x²-1)(x+2y)
=(x+1)(x−1)(x+2y)=(x+1)(x-1)(x+2y)
d)3x²−3y²−2(x−y)²d)3x²-3y²-2(x-y)²
=3(x²−y²)−2(x−y)²=3(x²-y²)-2(x-y)²
=3(x+y)(x−y)−2(x−y)²=3(x+y)(x-y)-2(x-y)²
=(x−y)[3(x+y)−2(x−y)]=(x-y)[3(x+y)-2(x-y)]
=(x−y)(3x+3y−2x+2y)=(x-y)(3x+3y-2x+2y)
=(x−y)(x+5y)=(x-y)(x+5y)
e)x³−4x²−9x+36e)x³-4x²-9x+36
=(x³−4x²)−(9x−36)=(x³-4x²)-(9x-36)
=x²(x−4)−9(x−4)=x²(x-4)-9(x-4)
=(x−4)(x²−9)=(x-4)(x²-9)
=(x−4)(x²−3²)=(x-4)(x²-3²)
=(x−4)(x+3)(x−3)=(x-4)(x+3)(x-3)
f)x²−y²−2x−2yf)x²-y²-2x-2y
=(x²−y²)−(2x+2y)=(x²-y²)-(2x+2y)
=(x+y)(x−y)−2(x+y)=(x+y)(x-y)-2(x+y)
=(x+y)(x−y−2)
hok tốt nhé
k đi
bài 2; phân tích đa thức sau thành nhân tử
a, x mũ 2 + 7x + 7y - y mũ 2
b, x mũ 2 - 2x - 9y mũ 2 + 6y
c, x mũ 2 - xy +x mũ 3 - 3x mũ 2 y + 3x mũ 2 y - y mũ 3
\(a,x^2+7x+7y-y^2\)
\(=x^2-y^2+7\left(x+y\right)\)
\(=\left(x-y\right)\left(x+y\right)+7\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y+7\right)\)
\(b,x^2-2x-9y^2+6y\)
\(=x^2-\left(3y\right)^2-2\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x+3y\right)-2\left(x-3y\right)\)
\(=\left(x-3y\right)\left(x+3y-2\right)\)
\(c,x^2-xy+x^3-3x^{2y}+3x^{2y}-y^3\)
\(=x\left(x-y\right)+\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=\left(x-y\right)\left(x+x^2+xy+y^2\right)\)
bài 2; phân tích các đa thức sau thành nhân tử
1, x mũ 2 - y mũ 2+ 4x 4
2, x mũ 2 + 2x - 4y mũ 2 - 4y
3, 3x mũ 2 - 4y + 4x - 3y mũ 2
4, x mũ 4 - 6x mũ 3 + 54x - 81
\(1,x^2-y^2+4x-4y\)
\(\left(x-y\right)\left(x+y\right)+4\left(x-y\right)\)
\(\left(x-y\right)\left(x+y+4\right)\)
\(x^2+2x-4y^2-4y\)
\(\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)\)
\(\left(x-2y\right)\left(x+2y+2\right)\)
\(3,3x^2-4y+4x-3y^2\)
\(3\left(x^2-y^2\right)-4\left(x-y\right)\)
\(3\left(x-y\right)\left(x+y\right)-4\left(x-y\right)\)
\(\left(x-y\right)\left(3x+3y-4\right)\)
\(x^4-6x^3+54x-81\)
\(x^4+3x^3-9x^3+27x^2-27x^2+81x-27x-81\)
\(\left(x^4+3x^3\right)-\left(9x^3+27x^2\right)+\left(27x^2+81x\right)-\left(27x+81\right)\)
\(x^3\left(x+3\right)-9x^2\left(x+3\right)+27x\left(x+3\right)-27\left(x+3\right)\)
\(\left(x+3\right)\left(x^3-9x^2+27x-27\right)\)
\(\left(x+3\right)\left(x-3\right)^3\)
Phân tích đa thức sau thành nhân tử
1. x mũ 2 - 4xy + 4y mũ 2 + xz - 2yz
2, (x - y) mũ 3 + (x+y) mũ 3
1) \(x^2-4xy+4y^2+xz-2yz\)
\(=\left(x^2-4xy+4y^2\right)+\left(xz-2yz\right)\)
\(=\left(x-2y\right)^2+z\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x-2y+z\right)\)
2) \(\left(x-y\right)^3+\left(x+y\right)^3\)
\(=\left[\left(x-y\right)+\left(x+y\right)\right]\left[\left(x-y\right)^2-\left(x-y\right)\left(x+y\right)+\left(x+y\right)^2\right]\)
\(=\left(x-y+x+y\right)\left(x^2-2xy+y^2-x^2+y^2+x^2+2xy+y^2\right)\)
\(=2x\left(x^2+3y^2\right)\)
bài 48; phân tích các đa thức sau thành nhân tử
5, x mũ 2 - y mũ 2 + 4x + 4
6, x mũ 2 + 2x - 4y mũ 2 - 4y
7, 3x mũ 2 - 4y + 4x - 3y mũ 2
8, x mũ 4 - 6x mũ 3 + 54x - 81
Trả lời:
5, x2 - y2 + 4x + 4
= ( x2 + 4x + 4 ) - y2
= ( x + 2 )2 - y2
= ( x + 2 - y ) ( x + 2 + y )
6, x2 + 2x - 4y2 - 4y
= ( x2 - 4y2 ) + ( 2x - 4y )
= ( x - 2y ) ( x + 2y ) + 2 ( x - 2y )
= ( x - 2y ) ( x + 2y + 2 )
7, 3x2 - 4y + 4x - 3y2
= ( 3x2 - 3y2 ) + ( 4x - 4y )
= 3 ( x2 - y2 ) + 4 ( x - y )
= 3 ( x - y ) ( x + y ) + 4 ( x - y )
= ( x - y ) [ 3 ( x + y ) + 4 ]
= ( x - y ) ( 3x + 3y + 4 )
8, x4 - 6x3 + 54x - 81
= ( x4 - 81 ) - ( 6x3 - 54x )
= ( x2 - 9 ) ( x2 + 9 ) - 6x ( x2 - 9 )
= ( x2 - 9 ) ( x2 + 9 - 6x )
= ( x - 3 ) ( x + 3 ) ( x - 3 )2
= ( x - 3 )3 ( x + 3 )
a, \(x^2-y^2+4x+4=\left(x+2\right)^2-y^2=\left(x+2-y\right)\left(x+2+y\right)\)
b, \(x^2+2x-4y^2-4y=\left(x-2y\right)\left(x+2y\right)+2\left(x-2y\right)=\left(x-2y\right)\left(x+2+2y\right)\)
c, \(3x^2-4y+4x-3y^2=3\left(x-y\right)\left(x+y\right)-4\left(y-x\right)=\left(x-y\right)\left(3x+3y+4\right)\)
d, \(x^4-6x^3+54x-81=\left(x^2+9\right)\left(x-3\right)\left(x+3\right)-6x\left(x^2-9\right)\)
\(=\left(x-3\right)\left(x+3\right)\left(x^2-6x+9\right)=\left(x-3\right)^3\left(x+3\right)\)
5, x2-y2+4x+4
=(x2+4x+4)-y2
=(x+2)2-y2
=(x+2-y)(x+2+y)
6, x2+2x-4y2-4y
=(x2-4y2)+(2x-4y)
=(x-2y)(x+2y)+2(x-2y)
=(x-2y)(x+2y+2)
7, 3x2-4y+4x-3y2
=(3x2-3y2)+(4x-4y)
=3(x2-y2)+4(x-y)
=3(x-y)(x+y)+4(x-y)
=(x-y)[3(x+y)+4]
=(x-y)(3x+3y+4)
8, x4-6x3+54x-81
=(x4-81)-(6x3-54x)
=(x2-9)(x2+9)-6x(x2-9)
=(x2-9)(x2+9-6x)
=(x+3)(x-3)(x-3)2
=(x+3)(x-3)3
#H
phân tích đa thức sau thành nhân tử
a, 81 - ( 3x + 2 ) mũ 2
b, ( 7x - 4 ) mũ 2 - ( 2x + 1 ) mũ 2
c, 9 ( x - 5y ) mũ 2 - 16 ( x + y ) mũ 2
a) \(81-\left(3x+2\right)^2=9^2-\left(3x+2\right)^2=\left(9-3x-2\right)\left(9+3x+2\right)=\left(7-3x\right)\left(11+3x\right)\)
b) \(\left(7x-4\right)^2-\left(2x+1\right)^2=\left(7x-4-2x-1\right)\left(7x-4+2x+1\right)\)
\(=\left(5x-5\right)\left(9x-3\right)=15\left(x-1\right)\left(3x-1\right)\)
c) \(9\left(x-5y\right)^2-16\left(x+y\right)^2=\left[3\left(x-5y\right)-4\left(x+y\right)\right]\left[3\left(x-5y\right)+4\left(x+y\right)\right]\)
\(=\left(-x-19y\right)\left(7x-11y\right)\)