36x^2 - 49=0 =>(6x-7)(6x+7)=0

6x-7=0 =>x=7/6

6x+7=0=>x=-7/6

\(\left(6x\right)^2=7^2\)

6x=+-7

\(x=+-\frac{7}{6}\)

a) \(\Leftrightarrow x^2-5x-2x+10=0\)

\(\Leftrightarrow x\left(x-5\right)-x\left(x-5\right)=0\)

\(\Leftrightarrow\left(x-5\right)\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\x-2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=2\end{cases}}}\)

Vậy \(x=5\)hoặc \(x=2\)

b) \(\Leftrightarrow\left(6x\right)^2-7^2=0\)

\(\Leftrightarrow\left(6x+7\right)\left(6x-7\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}6x=-7\\6x=7\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{-7}{6}\\x=\frac{7}{6}\end{cases}}\)

Vậy \(x=\frac{-7}{6}\)hoặc \(x=\frac{7}{6}\)

a, x²-7x+10=0

<=> x²-2x-5x+10=0

<=> x.(x-2)-5.(x-2)=0

<=> (x-2).(x-5)=0

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)

b, 36x²-49=0

<=> (6x)²-7²=0

<=> (6x-7).(6x+7)=0

\(\Leftrightarrow\orbr{\begin{cases}6x-7=0\\6x+7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{6}\\x=-\frac{7}{6}\end{cases}}\)

a)x²-7x+10=0

\(\Leftrightarrow x^2-2x-5x+10=0\)

\(\Rightarrow x\left(x-2\right)-5\left(x-2\right)=0\)

\(\Rightarrow\left(x-5\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-5=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=2\end{matrix}\right.\)

Vậy \(x=5\) hoặc \(x=2\)

b) 36x²-49=0

\(\Leftrightarrow\left(6x\right)^2-7^2=0\)

\(\Rightarrow\left(6x+7\right)\left(6x-7\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}6x+7=0\\6x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}6x=-7\\6x=7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-7}{6}\\x=\dfrac{7}{6}\end{matrix}\right.\)

Vậy \(x=\dfrac{-7}{6}\) hoặc \(x=\dfrac{7}{6}\)

a) x²-7x+10=0

=> x²-2x-5x+10=0

=> x(x-2)-5(x-2)=0

=> x(x-2)=0 -> hoặc x =0 hoặc x-2=0-> x=2

hoặc -5(x-2)=0 -> x=2

vậy x= 0 hoặc x= 2

b) 36x²-49=0

=> (6x)²-7²=0

=> (6x-7)(6x+7)=0

=>hoặc 6x-7=0 -> 6x=7 -> x=7:6

hoặc 6x+7=0->6x=-7-> x = 6:7

vậy x=7:6 hoặc x=6:7

\(36x^2-49=0\Leftrightarrow x^2=\frac{49}{36}\Leftrightarrow x=+-\frac{7}{6}\)

Vậy...

\(x^3-16x=0\Leftrightarrow x\left(x^2-16\right)=0\Leftrightarrow\orbr{\begin{cases}x=0\\x^2-16=0\Leftrightarrow x=+-4\end{cases}}\)

Vậy...

\(a,x^2-5x=0\)

\(x.\left(x-5\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-5=0\Rightarrow x=5\end{cases}}\)

vậy x=0 hay x=5

\(b,x^2-x=0\)

\(x.\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-1=0\Rightarrow x=1\end{cases}}\)

vậy x=0 hay x=1

\(c,36x^2-49=0\)

\(\Rightarrow36x^2=49\)

\(x^2=\frac{49}{36}=\frac{7^2}{6^2}=\frac{\left(-7\right)^2}{\left(-6\right)^2}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{7}{6}\\x=-\frac{7}{6}\end{cases}}\)

vậy x=\(\frac{7}{6}hayx=-\frac{7}{6}\)

a) 36x² - 49=0

(6x)² - 7² =0

(6x + 7)(6x - 7)=0

suy ra 6x + 7=0 hoặc 6x - 7=0

suy ra x =-7/6 hoặc x=7/6

1: =>(x+3)(x-5)=0

=>x=5 hoặc x=-3

2: =>(x-1)(5x-1)=0

=>x=1/5 hoặc x=1

5: =>(x-4)*x=0

=>x=0 hoặc x=4

10: =>(x+5)(x-3)=0

=>x=3 hoặc x=-5

9: =>(x-2)(x-4)=0

=>x=2 hoặc x=4

7: =>(x-6)(2x-1)=0

=>x=1/2 hoặc x=6

8: =>(2x-1)(3x-12)=0

=>x=4 hoặc x=1/2

\(1,x^2-x=0\)

\(\Leftrightarrow x\left(x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

\(2,\left(x+2\right)\left(x-3\right)-x-2=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-3\right)-\left(x+2\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-4\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+2=0\\x-4=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-2\\x=4\end{cases}}\)

\(3,36x^2-49=0\)

\(\Leftrightarrow\left(6x\right)^2-7^2=0\)

\(\Leftrightarrow\left(6x-7\right)\left(6x+7\right)=0\)

\(\Rightarrow\orbr{\begin{cases}6x-7=0\\6x+7=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-\frac{7}{6}\\x=\frac{7}{6}\end{cases}}\)

Chúc bn học giỏi nhoa!!!

Ta có : x² - x = 0

=> x(x - 1) = 0

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

Ta có : x² - x = 0

=> x(x - 1) = 0

=> x = 0 

     x - 1 = 0

=> x = 0;1