Tìm x,biết:
a)4-(27-3)=x-(13-4)
Tìm x, biết:
a. 3 x X + 27 - 2 x ( X - 4 ) = - 13 x 195 + 13 x 95
b. ( x - 1 ) + ( x - 2 ) + ... + ( x - 100 ) = 2750
c. -2 x ( X + 4 ) - 2^6 : 4^2 = 198
a: =>3x+27-2x+8=-13*100=-1300
=>x+35=-1300
=>x=-1335
b: =>100x-5050=2750
=>100x=2750+5050=7800
=>x=78
c: =>-2x-8-64:16=198
=>-2x=210
=>x=-105
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)
Bài 4. Tìm số nguyên x , biết:
a) |x - 2|= 0 b) |x + 3|= 1 c) -3 |4 - x|= -9 d) |2x + 1|= -2
Bài 5. Tìm số nguyên x, biết:
a) (x + 3)mũ 2 = 36 b) (x + 5)mũ 2 =100 c) (2x - 4)mũ 2 = 0 d) (x - 1)mũ 3 = 27
Tìm x biết:
a) x\(^3\)=343
b) (x-2.5)\(^4\)=(x-2.5)\(^2\)
c) \(\dfrac{x^8}{243}\)=27
`a)x^3=343=7^3`
`=>x=7`
Vậy `x=7`
`b)(x-2,5)^4=(x-2,5)^2`
`=>(x-2,5)^2[(x-2,5)^2-1]=0`
`+)(x-2,5)^2=0<=>x=2,5`
`+)(x-2,5)^2=1`
`TH1:x-2,5=1<=>x=3,5`
`th2:x-2,5=-1<=>x=1,5`
Vậy `x=0` hoặc `x=1,5` hoặc `x=3,5
`c)x^8/243=27`
`=>x^8=27.243`
`=>x^8=3^3*3^5=3^8`
`=>x=+-3`
Giải:
a) \(x^3=343\)
\(\Rightarrow x^3=7^3\)
\(\Rightarrow x=7\)
b) \(\left(x-2,5\right)^4=\left(x-2,5\right)^2\)
Vì có cùng cơ số nhưng lại khác mũ thì \(\left(x-2,5\right)\in\left\{0;1\right\}\)
TH1:
\(\Rightarrow x-2,5=0\)
\(\Rightarrow x=2,5\)
TH2:
\(\Rightarrow\left[{}\begin{matrix}x-2,5=1\\x-2,5=-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3,5\\x=1,5\end{matrix}\right.\)
c) \(\dfrac{x^8}{243}=27\)
\(\Rightarrow x^8=3^3.3^5\)
\(\Rightarrow x^8=3^8\)
\(\Rightarrow x=\pm3\)
Tìm m, biết:
A, m x 3 + m x 7 = 1530
B, m x 13 - 4 x m = 918
A, m x 3 + m x 7 = 1530
m x (3+7) = 1530
m x 10 = 1530
⇒ m = 153
B, m x 13 - 4 x m = 918
m x (13-4) = 918
m x 9 = 918
⇒ m = 102
a) m x (3+7)=1530
m x 10=1530
m=1530/10
m=153
b)m x (13-4)=918
m x 9=918
m=918/9
m=102
a) m x 3 + m x 7 = 1530
m x (3 + 7) = 1530
m x 10 = 1530
m= 1530 : 10
m= 153
b) m x 13 - 4 x m =918
m x (13 - 4)= 918
m x 9 = 918
m= 918 : 9
m= 102
Bài 4:tìm x,biết:
a)x + 7 = -12
b)x – 15 = -21
c)13 – x = 20
d)17 – (2 + x) = 3
a) x+7=-12
x=(-12)-7
x=-19
b)x-15=-21
x=(-21)+15
x=-6
c)13-x=20
x=13-20
x=-7
d)17-(2+x)=3
x=17-3
x=14
x=14-2
x=12
a,x+7=-12
=>x= -12-7
=>x= -19
b,x-15= -21
=>x= -21+15
=>x= -6
c,13-x=20
=>x=13-20
=>x= -7
d, 17-(2+x)=3
=>2+x=17-3
=>2+x=14
=>x=14-2
=>x=12
a) \(x+7=-12\)
\(x=-12-7\)
\(x=-19\)
b) \(x-15=-21\)
\(x=-21+15\)
\(x=-6\)
c) \(13-x=20\)
\(x=13-20\)
\(x=-7\)
d) \(17-\left(2+x\right)=3\)
\(2+x=17-3\)
\(2+x=14\)
\(x=14-2\)
\(x=12\)
Câu 9. Tìm y, biết:
a) (y – 24) : 28 = 20
b) 13 x (y – 6) = 4 x y - 6
c) y x 3 + y x 4 + y : 3 + y : 4 = 182
a) (y - 24) : 28 = 20
y - 24 = 20 x 28
y - 24 = 560
y = 560 + 24
y = 584
vậy y = ...
a.
\(\left(y-24\right):28=20\)
\(\left(y-24\right)=560\)
\(y=584\)
b. \(13\times\left(y-6\right)=4\times y-6\)
\(13\times y-78=4\times y-6\)
\(9\times y=72\)
\(y=8\)
c.\(y\times3+y\times4+y:3+y:4=182\)
\(y\times\left(3+4\right)+y:\left(3+4\right)=182\)
\(y\times\left(7+\dfrac{1}{7}\right)=182\)
\(y=\dfrac{637}{25}\)
Bài 4. Tìm x ∈ N biết:
a) x3 = 27 b) (2x – 1)3 = 8
c) (2x – 3)2 = 9 d) 2x + 5= 3^4 : 3^2
3^4 tức là 3 mũ 4
a, x= 3
b, ko có x thỏa mãn
c, x= 3
d, x= 2
a: x=3
b: \(2x-1=2\)
hay \(x=\dfrac{3}{2}\)
c: \(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
Bài 4. Tìm x biết:
a. \(\dfrac{x}{5}=\dfrac{2}{5},\dfrac{3}{8}=\dfrac{6}{x},\dfrac{1}{9}=\dfrac{x}{27}\)
b. \(\dfrac{4}{x}=\dfrac{8}{6},\dfrac{3}{x-5}=\dfrac{-4}{x+2},\dfrac{x}{-2}=\dfrac{-8}{x}\)
a,2/5 = 2/5 ; 3/8=6/16 ; 1/9=3/27
b, 4/3=8/6 ; -1=-1 ; -4/-2=-8/4
tick cho mik nhé
a) x= 2, x= 8.(6 : 3) = 16, x= 1. (27 : 9)= 3
b) x= 6 : (8 : 4) = 3, x= -1, x= -2 . -8 = x.x => 16 = x2 => 42 = x2 => x=4
Tick cho mình đi
tìm x , biết:
a) \(x\) : \(4\dfrac{1}{3}\) = -2,5 b) \(\dfrac{3}{5}x\) + \(\dfrac{1}{4}\) = \(\dfrac{1}{10}\)
c) \(2\dfrac{7}{9}\) \(-\) \(\dfrac{12}{13}x\) = \(\dfrac{7}{9}\) d)\(\dfrac{-2}{3}-\dfrac{1}{3}\)\(\left(2x-5\right)=\dfrac{3}{2}\)
a, \(x\) : \(\dfrac{13}{3}\) = -2,5
\(x\) = -2,5 . \(\dfrac{13}{3}\)
\(x\) = \(\dfrac{65}{6}\)
b,\(\dfrac{3}{5}\)\(x\) = \(\dfrac{1}{10}-\)\(\dfrac{1}{4}\)
\(\dfrac{3}{5}x\) = \(\dfrac{-3}{20}\)
\(x\) = \(\dfrac{-3}{20}\) : \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{-1}{4}\)
c, \(\dfrac{25}{9}-\dfrac{12}{13}x=\dfrac{7}{9}\)
\(\dfrac{12}{13}x\)\(=\dfrac{25}{9}-\dfrac{7}{9}\)
\(\dfrac{12}{13}x=2\)
\(x=2:\dfrac{12}{13}\)
\(x=\dfrac{13}{6}\)